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TASACIÓN DE LOTE URBANO DE UN SOLO FRENTE 1)

F= L=

6 20

At=

120

3F^2=

108

Valor arancelario=

264 soles/m2

At > 3F^2 3F2 * VALOR ARANCELARIO + 0.5 ( F * L – 3 F2 ) * VALOR ARANCELARIO 30096

2)

F= At= 3F^2=

monto de tasacion reglamentaria

10 110 m2 300 m2

Valor arancelario=

264 soles/m2

3 F2 >= F * L, entonces ÁREA TERRENO X VALOR ARANCELARIO

At < 3F^2 29040

TASACIÓN DE LOTE URBANO CON FRENTES 3) a

F1= F2=

At= VATU1= VATU2=

5.62 6.10 11.72

60.4712 65.636

3F1^2= A1=

94.75 60.47

3F1^2> A1 3144.50

126.11 52.00 58.00

3F2^2= A2=

111.63 65.64

3F2^2> A2 3806.888 6951.39

b)

F1= At= VATU1=

5.62 126.11 52.00

3F1^2= 94.75 At > 3F1^2 3F^2 * VALOR ARANCELARIO + 0.5 ( F * L – 3 F^2 ) * VALOR ARANCELARIO

5742.37 c)

F2= At= VATU2=

6.10 126.11 58.00

3F2^2=

112

At> 3F2^2 3F^2 * VALOR ARANCELARIO + 0.5 ( F * L – 3 F^2 ) * VALOR ARANCELARIO 6894.38

6951.39

ALOR ARANCELARIO

ALOR ARANCELARIO