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CÁLCULO ESTRUCTURAL LOSA DE TABLERO
Datos generales:
Luz del Puente
Luz := 38 m
Carga de Diseño: H2O-S16-44 N° de Vias
N°v := 2
Espesor capa de rodadura:
er := 0.03 m
Recubrimiento :
r := 2.5
Ancho losa interior:
s := 2.59 m
Ancho losa exterior
a := 0.91 m
Propiedad de los materiales:
fc := 250
Kg/cm2
fy := 4200
Kg/cm2
γH°A° := 2400 Kg/m3 γH°S° := 2300 Kg/m3
Esquema General:
Apoyos sobre vigas de HºPº
a
s
cm
CALCULO DE LOSA INTERIOR Luz de cálculo Usaremos la distancia entre ejes L := s L = 2.59
m
Predimensionado del espesor de la losa L + 3.05
t :=
30
t = 0.188 m
t := 0.18 Factor de impacto 15 L + 38
= 0.3695
⎛ 15 ≥ 0.3 , 0.3 , 15 ⎞ ⎟ L + 38 ⎠ ⎝ L + 38
I := if ⎜
I = 0.3 Carga muerta
Ancho de calculo: Losa := t ⋅
b 100
⋅ γH°A°
Rodadura := er ⋅
b 100
⋅ γH°S°
qCM := Losa + Rodadura
b := 100
cm
Losa = 432
Kgr/m
Rodadura = 69
Kgr/m (H° simple)
qCM = 501
Kgr/m
Momento por carga muerta Aplicando factor de continuidad de 0.8, para tres o mas apoyos. 2
Mcm := 0.8 ⋅ qCM ⋅
L
8
Mcm = 336.0758 Kgr.m/m
Momento por carga viva
Aplicando factor de continuidad de 0.8, para tres o mas apoyos. P := 7265 Mcv := 0.8 ⋅
kgr
(Carga de una rueda HS20)
L + 0.61 9.75
⋅P
Mcv = 1907.5282
Kgr.m/m
Momento por impacto MI := I ⋅ Mcv MI = 572.2585
Kgr.m/m
Momento último Mu := 1.3[ Mcm + 1.67( Mcv + MI) ] Mu = 5820.5154
Kgr.m/m
Canto útil Diametro del fierro
φ := 1.2
Espesor de la losa
h := t ⋅ 100
d := h − r −
φ 2
d = 14.9 cm Cuantía necesaria Φ := 0.9 ρ :=
⎛⎜ 1− 1.18 ⋅ fy ⎜ ⎝ fc
1−
2.36 ⋅ Mu ⋅ 100 ⎞⎟
ρ = 0.0075
Cuantía balanceada β1 := 0.85
⎛ 6090 ⎞ fc ⎟ ⎝ 6090 + fy ⎠ fy
ρb := 0.85 ⋅ β1 ⋅ ⎜
ρb = 0.0255
2
Φ ⋅ fc ⋅ b ⋅ d
⎟⎠
Cuantía máxima y mínima
ρmax := 0.75 ⋅ ρb
ρmax = 0.0191
Verificacion := if ( ρ < ρmax , "cumple" , "no cumple" ) Verificacion = "cumple" ρmin :=
14
ρmin = 0.0033
fy
Cuantía de diseño ρ := if ( ρ ≥ ρmin , ρ , ρmin)
ρ = 0.0075
Acero de refuerzo As := ρ ⋅ b ⋅ d As = 11.1634 cm2
Ao :=
π ⋅φ
2
Ao = 1.131 cm2
4
N°Barras :=
As
N°Barras = 9.8706
Ao
N°Barras := 10 Usar :
N°Barras = 10 de φ = 1.2 cm
(por metro de ancho)
Area de acero proporcionada: Asprop := N°Barras ⋅ Ao Asprop = 11.3097 cm2 /m
Acero de distribución: Para armadura principal perpendicular al transito:
⎛ 1.22 ≤ 0.67 , 1.22 , 0.67⎞ ⎟ L ⎝ L ⎠
D := if ⎜
D = 0.67 AD := D ⋅ As AD = 7.4795 cm2
φ := 1.2 Ao :=
π ⋅φ
2
Ao = 1.131 cm2
4
N°Barras :=
AD Ao
N°Barras = 6.6133
N°Barras := 7
Usar :
N°Barras = 7 de φ = 1.2 cm
(por metro de ancho)
(En la cara inferior, sobre la armadura positiva) Area de acero proporcionada: ADprop := N°Barras ⋅ Ao ADprop = 7.9168 cm2 /m
Acero por retacción y temperatura Cuantía mínima por temperatura: ρtem := 0.0020 As := ρtem ⋅ h ⋅ b As = 3.6 cm2 /m φ := 1.0 Ao :=
π ⋅φ
2
4
N°Barras :=
Ao = 0.7854 As Ao
N°Barras = 4.5837
N°Barras := 5
Usar :
N°Barras = 5 de
φ = 1 cm
(por metro de ancho)
Area de acero proporcionada: Asprop := N°Barras ⋅ Ao Asprop = 3.927 cm2 /m
CALCULO LOSA EXTERIOR
Ancho de distrubucion de la carga puntual
a 0.3m
X
X := a − 0.3 m E := 0.8 ⋅ X + 1.14 E = 1.628
m
Momento por Cargas muertas
Qba
Qba Qp2
Qp1 Qa
a
Qp3 QL Qbo
Peso propio losa + capa de rodadura QL := a ⋅ ( t + er ) ⋅ γH°A° MQL :=
a 2
⋅ QL
QL = 458.64
Kgr/m
MQL = 208.6812
Kgr.m/m
Bordillo Alto del Bordillo
hbo := 0.45 m
Ancho del Bordillo
abo := 0.2 m
Qbo := hbo ⋅ abo ⋅ γH°A°
⎛ ⎝
MQbo := ⎜ a +
Qbo = 216
abo ⎞
⎟ ⋅ Qbo ⎠
2
Kgr/m
MQbo = 218.16
Kgr.m/m
Acera Alto
ha := 0.15
m
Ancho
aa := 0.65
m
Qa := ha ⋅ aa ⋅ γH°A°
⎛ ⎝
MQa := ⎜ a +
Qa = 234 Kgr/m
aa ⎞ 2
⎟ ⋅ Qa ⎠
MQa = 288.99 Kgr.m/m
Barandado Alto del Barandado
hb := 0.125 m
Ancho del Barandado
ab := 0.15 m
Qb := 2 ⋅ hb ⋅ ab ⋅ γH°A°
⎛ ⎝
MQb := ⎜ a + aa −
Qb = 90 Kgr/m
ab ⎞
⎟ ⋅ Qb ⎠
2
MQb = 133.65
Postes Alto del poste:
hp := 0.9
m
Profundidad del poste
bp := 0.2
m
Dimensiones del poste:
ap1 := 0.12 m ap2 := 0.08 m ap3 := 0.10 m N°p := 20
Calculo N° de postes:
Sep :=
Luz − bp N°p − 1
Sep = 1.9895
Verificacion := if ( Sep ≤ 2 , "Cumple" , "aumentar postes" ) Verificacion = "Cumple"
Qp1 :=
hp ⋅ ap1 ⋅ bp ⋅ γH°A° ⋅ N°p
Qp1 = 27.2842 Kgr/m
Luz
⎛ ⎝
MQp1 := ⎜ a + aa + ap3 − ap2 − Qp2 :=
2
⎟ ⋅ Qp1 MQp1 = 41.472 ⎠
0.5 ⋅ ap2 ⋅ hp ⋅ bp ⋅ γH°A° ⋅ N°p
Qp2 = 9.0947
Luz
⎛ ⎝
2 ⋅ ap2 ⎞
MQp2 := ⎜ a + aa + ap3 −
Qp3 :=
ap1 ⎞
3
⎟ ⋅ Qp2 ⎠
ha ⋅ ap3 ⋅ bp ⋅ γH°A° ⋅ N°p
⎛ ⎝
MQp3 := ⎜ a + aa +
ap3 ⎞ 2
MQp2 = 14.6122
Qp3 = 3.7895
Luz
⎟ ⋅ Qp3 ⎠
Kgr/m
Kgr/m
MQp3 = 6.1011
Momento total por carga muerta: Mcm := MQL + MQbo + MQb + MQp1 + MQp2 + MQp3 + MQa Mcm = 911.6665 Kgr.m/m
Momento por Cargas vivas
a
F2v F3h F3v 0.3m
t
D
F3h := 750.0 kgr/m h3h := hbo −
t
h3h = 0.36 m
2
MF3h := h3h ⋅ F3h
MF3h = 270
F2v := 290 ⋅ aa
kgr/m
⎛ ⎝
aa ⎞
MF2v := F2v ⋅ ⎜ a +
2
⎟ ⎠
F2v = 188.5 MF2v = 232.7975
Carga de camión: P = 7265 F3v :=
P
Kgr
F3v = 4462.5307 kgr/m
E
MF3v := F3v ⋅ ( a − 0.3)
MF3v = 2722.1437
Momento total por carga viva: Mcv := MF3v + MF3h + MF2v Mcv = 3224.9412
kgr.m/m
Impacto:
⎛ 15 ≥ 0.3 , 0.3 , 15 ⎞ ⎟ a + 38 ⎠ ⎝ a + 38
I := if ⎜
MI := I ⋅ Mcv
I = 0.3
MI = 967.4824
Momento de diseño Mu := 1.3[ Mcm + 1.67( Mcv + MI) ] Mu = 10286.918
kgr.m/m
Canto útil φ := 1.2 d := h − r −
φ 2
d = 14.9 Cuantía necesaria b = 100 cm
ρ :=
⎛⎜ 1− 1.18 ⋅ fy ⎜ ⎝ fc
1−
2.36 ⋅ Mu ⋅ 100 ⎞⎟ 2
φ ⋅ fc ⋅ b ⋅ d
⎟⎠
ρ = 0.0102
Cuantia balanceada β1 := 0.85
⎛ 6090 ⎞ fc ⎟ ⎝ 6090 + fy ⎠ fy
ρb := 0.85 ⋅ β1 ⋅ ⎜
ρb = 0.0255
Cuantía máxima y mínima ρmax := 0.75 ⋅ ρb
ρmax = 0.0191
Verificacion := if ( ρ < ρmax , "cumple" , "no cumple" ) ρmin :=
14
Verificacion = "cumple"
ρmin = 0.0033
fy
Cuantía de diseño ρ := if ( ρ ≥ ρmin , ρ , ρmin)
ρ = 0.0102
Acero de refuerzo As := ρ ⋅ b ⋅ d Ao :=
N°Barras :=
As Ao
π ⋅φ 4
As = 15.2443
cm2
2
Ao = 1.131
N°Barras = 13.4789
N°Barras := 14
Usar :
N°Barras = 14 de φ = 1.2 cm Area de acero proporcionada: Asprop := N°Barras ⋅ Ao Asprop = 15.8336 cm2 /m
Acero de distribución L := a Para armadura principal perpendicular al transito:
⎛ 1.22 ≤ 0.67 , 1.22 , 0.67⎞ ⎟ L ⎝ L ⎠
D := if ⎜
D = 0.67 AD := D ⋅ As AD = 10.2137 cm2 Por Tanto: φ := 1.2 cm Ao :=
π ⋅φ
2
Ao = 1.131
4
N°Barras :=
AD Ao
N°Barras = 9.0309
N°Barras := 10
Usar :
N°Barras = 10 de φ = 1.2 cm Area de acero proporcionada: Asprop := N°Barras ⋅ Ao Asprop = 11.3097
cm2 /m
(En la carga superior, bajo la armacdura negativa)
Acero por temperatura Cuantía mínima por temperatura: ρtem := 0.0020 As := ρtem ⋅ h ⋅ b
As = 3.6 cm2 /m
φ := 1 cm
Ao :=
π ⋅φ
2
4
N°Barras :=
As Ao
Ao = 0.7854
N°Barras = 4.5837
N°Barras := 5 Usar :
N°Barras = 5 de φ = 1
cm
Area de acero proporcionada: Asprop := N°Barras ⋅ Ao Asprop = 3.927 cm2 /m