I. ObtΓ©n el lΓmite de las siguientes funciones aplicando las propiedades de los lΓmites. 1. 2. 3. lim 5 = π₯ β5 12.
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I.
ObtΓ©n el lΓmite de las siguientes funciones aplicando las propiedades de los lΓmites. 1. 2.
3.
lim 5 =
π₯ β5
12. lim
π₯2 + 9
=
π₯ β2 π₯ β 9
lim (β3) =
π₯ β0
13. lim
lim π₯ =
π₯2β 4
=
π₯ β0 π₯ β 2
π₯ β(β2)
3
4.
14. lim 5 + π₯ =
lim1 π₯ =
π₯ β1
π₯ β( ) 4
15. lim 2π₯ 2 β 3βπ₯ + β2 = π₯ β0
5. lim 2π₯ = π₯ β3
6. 7. 8.
16. lim (π₯ + 3)(π₯ + 5) = π₯ β1
1
lim 2 π₯ =
π₯ β8
17. lim
π₯ β0 π₯+ 2
lim (2π₯ β 5) =
π₯ β1
π₯ β0
lim β2π₯ + 4 =
π₯ β0
π₯ 3 +2π₯ +16
lim β
2π₯ 2 +7
π₯ β3
10. lim
=
18. lim βπ₯ 2 β 25 = 19. lim
9.
π₯+3
3π‘ 2
β 4π‘ + 3 π‘+2
π‘ β1
π₯ 3 β 27
π₯ β0 π₯ 2 + 9
= 20. lim
π‘ β1
=
3π‘ 3 β π‘ β 5 π‘2β 5
=
=
11. lim π₯ 2 + π₯ = π₯ β2
II.
Aplica directamente las propiedades de los lΓmites y calcula los siguientes lΓmites, si existen. 1. 2. 3. 4.
III.
lim π₯ 2 =
5.
π₯ β3
lim1 π₯ =
9.
π₯β
2
lim (4π₯ + 5) =
π₯ β0
6.
lim (5π₯ β 2) =
π₯ ββ2
7.
lim
2π₯ 2 +π₯β1
π₯ β2
4π₯β2
=
lim (π₯ 2 β 4) =
π₯ β2
8.
10. lim (4π₯ 2 β 8π₯ + π₯ β2
5) = π₯+1
11. lim 2π₯+3 = π₯ β3
lim 6 =
π₯ β4
lim 3π₯ 2 =
π₯ ββ2
lim 5π₯ =
12. lim β3π₯ 2 + 4 =
π₯ ββ1
π₯ ββ2
Aplica el artificio algebraico del caso II y resuelve los siguientes lΓmites que presentan π la forma indetermina (π). 1.
lim
π₯ β0
8π₯ 2 β2π₯ 2π₯
=
2.
lim
π₯ 2 β1
π₯ ββ1 π₯+1
=
3.
lim
5π₯
π₯ β0 π₯
=
4.
5.
6.
IV.
π₯ ββ5
lim
π₯ 2 β25
=
7.
=
8.
π₯ 2 +π₯β3 π₯ 2 β1
π₯ β1
2π₯ 2 β π₯ β 3
lim
=
π₯+1
π₯ ββ1
9.
lim
π₯ 2 + 4π₯ β 21 π₯β3
π₯ β3
lim
=
11.
π₯+4
π₯ 2 β 8π₯+ 12
π₯ β2
10.
π₯ 2 + 5π₯ + 4
π₯ ββ4
lim
=
π₯β2
=
12.
π₯3 + 1
lim
π₯ ββ1 π₯ + 1
lim
2.
3.
β3 + π₯ β π₯ β β3 π₯ π₯ β0
lim
π₯
lim
π₯ β0 β2 + π₯ β β2 βπ₯+3 β 2 lim π₯ β 1 π₯ β1
=
=
4.
5.
6.
=
lim
2 β βπ₯
π₯ β4 4 β π₯
lim
π₯ β0
lim
=
π₯ 3 β 125
=
π₯ β5 π₯ 2 β 25
lim
π₯3 β 8
π₯ β2 π₯ β 2
=
2β β4 β π₯ π₯
=
25β π₯ 2
2. 3. 4.
f(x) = ax2 + bx + c f(x) = f(x) =
1 π₯
6.
f(x) = βπ₯ 2 β 1
7.
f(x) = 2x2 +7x β 1
π₯ β2
f(x) = x3 + 5x β 3
9.
f(x) = βππ₯ + π
π₯ β1
f(x) =
β 3 β1
+3β2
= =
π(π + π)βπ(π)
.
π
12. f(x) =
1 βππ₯ 2 βπ₯ + 1
13. f(x) = βπ₯ + 9
5x3
14. f(x) = 5.
=
π₯β1
lim βπ₯ 2
11. f(x) =
8.
+7β4
π₯2 β 4
lim βπ₯ 2
9.
=
π₯ β5 3 β βπ₯ 2 β16
π₯ β3
8.
πβπ
f(x) = mx2
π₯2 β 9
lim βπ₯ 2
7.
Para cada una de las siguientes funciones dadas, determina π₯π’π¦ 1.
VI.
=
Aplica el artificio del caso III y resuelve los siguientes lΓmites que presentan la forma π indeterminada (π). 1.
V.
π₯+5
lim
1
10. f(x) = 3x2 + 5x
π₯2
1 β4 β π₯
Aplica el articulo algebraico y resuelve los siguientes limites que representan la forma β indeterminada (β). 1.
2. 3.
lim
2π‘ 3 β 3π‘ 2 + 4
π‘ββ 5π‘β π‘ 2 β7π‘ 3
lim
π₯ββ
lim
7β 3π₯ 2 5π₯ + 9π₯ 2 6π₯ + 2
π₯ββ 3π₯ +5
=
4. 5.
= 6.
= 7.
lim
8π₯ 3 β 3π₯2 + 1
π₯ββ 4π₯ 3 β 5π₯ β7 2π₯ 3 + 3
lim
π₯ββ 4 β π₯ β 5π₯ 2
lim
4π₯ + 2
π₯ββ 8π₯ β 3
lim
=
8.
lim
π₯ββ 4π₯ 3 β 3
= 9.
lim
π₯ββ 8π₯ 2 β 5π₯ + 3
2π₯ 3
π₯ββ π₯ 3 + 3
=
8π₯ 2 β 4π₯ + 2
π₯ 3 β 2π₯ β 5
10. lim
=
π₯2 β 4
π₯ββ π₯ 2 β π₯ β 12
=
=
=
lΓmites de las funciones trigonomΓ©tricas. 1.
limπ sin π₯
π₯β
2. 3. 4. 5. 6. 7.
lim lim
11. lim tan π₯
sin 3π₯
π₯βπ
π₯
12. lim cos 3π₯
sin2 π₯
π₯βπ
π₯
π₯β0
lim
π₯β0
π₯
π₯β0
lim
lim cos ππ₯
π₯β2
10. lim cos ππ₯
sin 2π₯
π₯β0
13. lim sin π₯ 5π π₯β
sin π₯
3
π₯β0 5π₯
lim
14. lim cos
tan π₯
π₯β0
π₯βπ
6
15. limπ π₯ sin π₯ π₯β
2
2
16. lim
tan π₯
π₯β0
limπ sin π₯
π₯β
π₯
π₯
lim cos π₯ 3π
π₯β
8.
9.
4
π₯
β cos π₯
2
Determina los lΓmites en donde intervienen funciones exponenciales.
1. 2.
1 π₯+4
lim [1 + π₯]
π₯ββ
1 π₯+2
lim [1 + ]
3
5.
π₯ββ
π₯
lim [1 +
1 π₯ ] π₯
7.
1 4π₯
8.
4.
π₯ββ
lim [1 + π₯]
π₯ββ
π₯β0
5
6.
lim (1 + π₯)π₯
π₯β0
1
3
3.
lim (1 + π₯)π₯
lim (1 + 2π₯)π₯
π₯β0
1
lim (1 + 4π₯)π₯
π₯β0
Aplica directamente las propiedades de los lΓmites y calcula los siguientes lΓmites, si existen.
1. lim (π₯ 4 + 5π₯ 3 β π₯ β 1) π₯β1
3π₯β24
21. lim π₯ 2 β64 π₯β8
2. lim (π₯ 3 β 4π₯ 2 + 2π₯ + 10) π₯β1
π₯β7
22. lim π₯ 2 β49 π₯β7
3. lim (π₯ 4 + 2π₯ 3 + 4π₯ 2 β 7π₯ β 34) π₯β2
π₯β8
23. lim
π₯ββ8 π₯ 2 β64
4. lim βπ₯ β 1 π₯β1
24. lim
π₯ 2 β17π₯+72 π₯β9
π₯β9
5.
lim (π₯ 3 π₯β2
6. lim
2
β 7π₯ β 8π₯ + 24)
π₯ 2 β7π₯+6 π₯ 2 β9
π₯β3
π₯+4
25. lim π₯ 2 β16
2π₯β6
7. lim π₯ 2 β9 π₯β3
4π₯β10
8. lim 4π₯β20 π₯β5
π₯β4
26. lim
π₯ 3 β1
π₯β1 π₯ 2 β1
27. lim βπ‘ β 2 π‘β6
28. lim β6π₯ β 14 π₯β5
9.
lim
3π₯ 2 βπ₯β16 2π₯+4
π₯ββ2
10. lim
π₯ββ5 π₯ 2 β25
π₯ 2 β7π₯+12 π₯β4
π₯β4
8π₯+40
29. lim
2π‘β8
30. lim π‘ 2 β16 π‘β4
π₯β1
11. lim π₯ 2 β1 π₯β1
31. lim
π₯β5
π₯ββ3 π₯ 2 β5π₯
2π₯
12. lim π₯ 2 β5π₯ π₯β0
32. lim (4π₯ + 9)2 π₯ββ3
3π₯+4
13. lim
π₯ββ5 2π₯ 2 +7π₯β15
33. lim
π₯ββ4 π₯ 2 β16
3π₯β6
14. lim 2π₯ 2 +3π₯β14 π₯β2
34. lim
π₯β3
16. lim
π₯β0
2π₯+12
π₯β6 π₯ 2 β36
6π₯β18
15. lim π₯ 2 β3π₯
2π₯β12
35. lim π₯ 2 β36 π₯β6
π₯ 2 β2π₯ 7π₯
5π₯β20
36. lim π₯ 2 β7π₯+12 π₯β4
2π₯+3
17. lim π₯ 2 β16 π₯β4
4π₯β36
37. lim π₯ 2 βπ₯β72 π₯β9
π₯+2
18. lim π₯ 2 β4 π₯β2
19. lim
2π₯ 2 β12π₯
π₯β6 4π₯β24
20. lim
π₯
π₯β0 π₯ 2 +7π₯
4π₯+16
38. lim
3π₯
π₯ββ0 π₯ 2 +3π₯
39. lim βπ₯ β 4 π₯β4
40. lim β6 β π₯ π₯β6
β
Resuelve los siguientes limites que presentan la forma indeterminada ( ). β
1. 2.
3. 4.
5.
6.
7.
8.
9.
10.
5π₯β20
lim
π₯ββ π₯ 2 β7π₯+12 4π₯β36
lim
π₯ββ π₯ 2 βπ₯β72 4π₯ 2 β16
lim
π₯ββ π₯ 2 β4 3π₯
lim
π₯ββ
π₯ 2 β3π₯ 3π₯ 2 β7π₯β18
lim
π₯ββ
3π₯β12 28π₯ 2 β5π₯+3
lim
π₯ββ
4π₯ 2 +6π₯β1 βπ₯ 2 +3
lim
π₯ββ
2π₯ 2 β1 π₯ 2 β9
lim
π₯ββ π₯ 3 +27 12π₯ 3 β8π₯+620
lim
π₯ββ
π₯ 2 β5π₯+6 6π₯ 2 β5π₯
lim
π₯ββ 2π₯ 2 β8
11. 12.
13. 14.
15.
16.
17. 18. 19.
20.
π₯β3
lim
π₯ββ π₯ 2 β3π₯ 4π₯β7
lim
π₯ββ π₯ 2 β36 16π₯ 3 β7π₯ 2 β8π₯+6
lim
π₯ 2 β9
π₯ββ 2π₯β7
lim
π₯ββ π₯ 2 β16 βπ₯ 2 β4
lim
π₯ββ π₯ 2 β9 5π₯ 3 β4π₯+6
lim
π₯ββ 10π₯ 3 βπ₯+1 π₯ 2 β11
lim
π₯ββ 4βπ₯ 2 3
lim 8 + π₯ 2
π₯ββ
lim
π₯+7
π₯ββ 9π₯ 2 β1
lim
β5π₯ 4 +1
π₯ββ β3π₯ 4 +6
π
Aplica el artificio del caso III y resuelve los siguientes lΓmites que presentan la forma indeterminada ( ). π
βπ₯ +3 β2
1. 2. 3.
βπ₯+3 β 2 lim π₯β1 π₯β1
lim
π¦+2
π¦ββ2 βπ¦+3 β1 βπ€ lim ββ3 βπ€+3 π€β0
4. lim1 π₯β
β4π₯ 2 +3 β2 2π₯β1
6. lim 1 ββ3π₯ β2 π₯β1
3π₯ β2π₯ 2
7. lim 5π₯β6π₯ 3 π₯β0
8. lim
ββ0
9. lim
β4 β β2 4π¦ 5 β 5π¦ 3
π¦β0 π¦ 4 β π¦ 2
2
5. lim
2β3 β 5β2 +β
ππ₯ 2 + ππ₯ 3
π₯ β5
π₯β5 βπ₯ ββ5
10. lim ππ₯ 2 β ππ₯ 3 π₯β0
LΓmites de las funciones trigonomΓ©tricas. cos 3π₯
1. lim ( π₯β0
π₯ +3
)
β4 cos π₯
6. lim βsin π₯ + cos π₯ π₯β0
2. limπ(sin π + cos π) πβ
3.
tan β
7. limπ π ππ2 β β 1
6
ββ
3
πΌ
lim (2sin 2 cos πΌ)
πΌβπ
8.
sin π₯ + cos π₯
lim 3π sin π₯ β cos π₯
π₯β
4.
π‘ππ2 π€ β1
4
lim π‘ππ2 π€ +1
π€β0
π ππ 2 π€
π
π
9. lim 1 β π ππ2 π€ π₯βπ
5. limπ sin (π₯ β 4 ) cos (π₯ + 4 ) π₯β
2
10.
limπ
π½β
3
sin π½ β cos π½ tan π½ β β3