1 Calculate the hydrostatic pressure at the bottom of the fluid column for each case shown in Fig 4.52. (Ans. 5200 psig
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1 Calculate the hydrostatic pressure at the bottom of the fluid column for each case shown in Fig 4.52. (Ans. 5200 psig for Case A)
Given: D = 10,000 ft
ρ = 10 ppg
Required: PA, PB, PC
Solution: CASE A: 𝑃𝐴 = 0.052 × 𝜌 × 𝐷
CASE B: 𝑃𝐵 = 0.052 × 𝜌 × 𝐷
𝑃𝐴 = 0.052 × 10𝑝𝑝𝑔 × 10,000𝑓𝑡
𝑃𝐵 = 0.052 × 10𝑝𝑝𝑔 × 10,000𝑓𝑡
𝑷𝑨 = 𝟓, 𝟐𝟎𝟎 𝒑𝒔𝒊
𝑷𝑩 = 𝟓, 𝟐𝟎𝟎 𝒑𝒔𝒊
CASE C: 𝑃𝐶 = 0.052 × 𝜌 × 𝐷 𝑃𝐶 = 0.052 × 10𝑝𝑝𝑔 × 10,000𝑓𝑡 𝑷𝑪 = 𝟓, 𝟐𝟎𝟎 𝒑𝒔𝒊 2 Calculate the mud density required to fracture stratum at 5,000 ft. if the fracture pressure is 3,800 psig. (Ans. 14.6 lbm/gal) Given: D = 5,000 ft
PF = 3,800 psig
Required: ρmud Solution: 𝜌=
𝑃𝐹 0.052 × 𝐷
𝜌=
3,800 𝑝𝑠𝑖𝑔 0.052 × 5,000𝑓𝑡
𝝆 = 𝟏𝟒. 𝟔𝟏𝟓𝟑𝟖𝟓 𝒑𝒑𝒈 3 An ideal gas has an average molecular weight of 20. What is the density of the gas at 2,000 psia and 600⁰R? (Ans. 0.8 Ibm/gal) Given: MW = 20 P = 2,000 psia
Solution: 𝜌=
𝑃 × 𝑀𝑊 80.3 × 𝑧 × 𝑇
𝜌=
2,000 psia × 20 80.3 × 1 × 600⁰R
T = 600⁰R Z=1 Required: ρ
𝝆 = 𝟎. 𝟖𝟑𝟎𝟐𝟐𝟎 𝒍𝒃𝒎 ⁄𝒈𝒂𝒍