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• Marvin Vásquez

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UNIVERSIDAD DE EL SALVADOR. FACULTA DE INGENIERÍA Y ARQUITECTURA. ESCUELA DE INGENIERIA ELECTRICA ANALISIS ELECTRICO II CICLO 02 - 2018

INTEGRANTES: APELLIDOS Vásquez Lara

NOMBRES Marvin Josué

CARNÉ VL16001

CATEDRÁTICO: Ing. Gerardo Marvin Jorge Hernández. INSTRUCTOR: Br. Aura Mendoza GRUPO LAB: 01

CIUDAD UNIVERSITARIA, 21 DE OCTUBRE DE 2018

Guía de Asignación III: Filtros Activos Parte II. Ejercicio. Filtro pasa banda 35KHz de 10 orden, topología Butterworth. Graficar diagrama de Bode de fase y magnitude

* AEL215 Ciclo II-2018. * Guia de Asignacion 3 y 4 Ejercicio 1 *********************** Parámetros del Circuito .param Vm = 1V .param Vs = Vm/sqrt(2) .param VDD = 15V .param VSS = -15V .param f = 1kHz .param T = 1/f .param RF1 = 151.6kohm .param CX = 150pF .param RF2 = 303.2kohm .param RF3 = 3.1kOhm *********************** Descripción del Circuito V1 1 0 DC 0V AC {Vs}V 0deg SIN ( 0V {Vm} {f} 0s 0 0deg ) VDD 17 0 DC {VDD} VSS 18 0 DC {VSS} R1 1 2 {RF1} C1 2 3 {CX} R2 2 0 {RF2} R3 3 4 {RF3} C2 2 4 {CX} X1 0 3 17 18 4 LF356/NS R4 4 5 {RF1} C3 5 6 {CX} R5 5 0 {RF2} R6 6 7 {RF3} C4 5 7 {CX} X2 0 6 17 18 7 LF356/NS R7 7 8 {RF1} C5 8 9 {CX} R8 8 0 {RF2}

R9 9 10 {RF3} C6 8 10 {CX} X3 0 9 17 18 10 LF356/NS R10 10 11 {RF1} C7 11 12 {CX} R11 11 0 {RF2} R12 12 13 {RF3} C8 11 13 {CX} X4 0 12 17 18 13 LF356/NS R13 13 14 {RF1} C9 14 15 {CX} R14 14 0 {RF2} R15 15 16{RF3} C10 14 16 {CX} X5 0 15 17 18 16 LF356/NS *************************** Subcircuitos *////////////////////////////////////////////////////////////////////// * (C) National Semiconductor, Inc. * Models developed and under copyright by: * National Semiconductor, Inc. *///////////////////////////////////////////////////////////////////// * Legal Notice: This material is intended for free software support. * The file may be copied, and distributed; however, reselling the * material is illegal *//////////////////////////////////////////////////////////////////// * For ordering or technical information on these models, contact: * National Semiconductor's Customer Response Center * 7:00 A.M.--7:00 P.M. U.S. Central Time * (800) 272-9959 * For Applications support, contact the Internet address: * [email protected] * /////////////////////////////////////////////////////////////////// * User Notes: * * 1. Input resistance (Rin) for these JFET op amps is 1TOhm. Rin is * modeled by assuming the option GMIN=1TOhm. If a different (non* default) GMIN value is needed, users may recalculate as follows: * Rin=(R1||GMIN+R2||GMIN), where R1=R2, * to maintain a consistent Rin model. *////////////////////////////////////////////////////////// *LF356 Monolithic JFET-Input OP-AMP MACRO-MODEL *////////////////////////////////////////////////////////// * * connections: non-inverting input * | inverting input

* | | positive power supply * | | | negative power supply * | | | | output *||||| *||||| .SUBCKT LF356/NS 1 2 99 50 28 * *Features: *Low input bias current = 30pA *Low input offset current = 3pA *High input impedance = 1Tohm *Low input offset voltage = 1mV * ****************INPUT STAGE************** * IOS 2 1 3P *^Input offset current R1 1 3 1E12 R2 3 2 1E12 I1 99 4 100U J1 5 2 4 JX J2 6 7 4 JX R3 5 50 20K R4 6 50 20K *Fp2=20 MHz C4 5 6 1.9894E-13 * ***********COMMON MODE EFFECT*********** * I2 99 50 4.65MA *^Quiescent supply current EOS 7 1 POLY(1) 16 49 3E-3 1 *Input offset voltage.^ R8 99 49 50K R9 49 50 50K * *********OUTPUT VOLTAGE LIMITING******** V2 99 8 2.63 D1 9 8 DX D2 10 9 DX V3 10 50 2.63 * **************SECOND STAGE************** * EH 99 98 99 49 1 F1 9 98 POLY(1) VA3 0 0 0 1.5944E7 G1 98 9 5 6 2E-3

R5 98 9 100MEG VA3 9 11 0 *Fp1=31.96 HZ C3 98 11 49.9798P * *********COMMON-MODE ZERO STAGE********* * G4 98 16 3 49 1E-8 L2 98 17 530.52M R13 17 16 1K * **************OUTPUT STAGE************** * F6 99 50 VA7 1 F5 99 23 VA8 1 D5 21 23 DX VA7 99 21 0 D6 23 99 DX E1 99 26 99 9 1 VA8 26 27 0 R16 27 28 20 V5 28 25 -.25V D4 25 9 DX V4 24 28 -.25V D3 9 24 DX * ***************MODELS USED************** * .MODEL DX D(IS=1E-15) .MODEL JX PJF(BETA=1.25E-5 VTO=-2.00 IS=30E-12) * .ENDS *$ .control ************************ Respuesta en Frecuencia set units=degress ac dec 10000 1kHz 1000kHz plot dB(V(16)/V(1)) vs (frequency/1k) xlabel 'Frecuencia [kHz]' +ylabel 'Ganancia [dB]' title 'Diagrama de Bode de la magnitud de Vout/Vin' plot ph(V(16)/V(1)) vs (frequency/1k) xlabel 'Frecuencia [kHz]' +ylabel 'Angulo [Grados]' title 'Diagrama de Bode de la fase de Vout/Vin' .endc .end

Guía de Asignación IV: Acoplamiento Magnético. Ejercicio. Determinar las corrientes mostradas, la red opera a 6 Hz.

* Asignacion 3 y 4 ejercicio 2 ************************** Parámetros del Circuito .param Vs1 = 60V .param Vs2 = 40V .param Vm1 = Vs1*sqrt(2) .param Vm2 = Vs2*sqrt(2) .param argV1 = -10 .param argV2 = 0 .param f = 6Hz ************************ Descripcion del Circuito V1 1 0 DC 0 AC {Vs1} {argV1} sin ( 0 {Vm1} {f} 0s 0 {argV1}deg ) V2 9 0 DC 0 AC {Vs2} {argV2} sin ( 0 {Vm2} {f} 0s 0 {argV2}deg ) VX1 1 2 DC 0V R1 2 4 100ohm VX2 2 3 DC 0V R2 3 5 70ohm L1 4 7 3H L2 6 7 3H L3 7 8 4H L4 5 6 2H VX3 9 6 DC 0V C 8 0 270uf *********************** Acoplamiento de Inductores KAcople1 L1 L2 1H KAcople2 L1 L3 1.5H KAcople3 L2 L3 2H .control

************************ Respuesta en Frecuencia set units=degress ac dec 1 6Hz 6Hz let I1=Mag(i(VX1)) let I2=Mag(i(VX2)) let I3=Mag(i(VX3)) echo echo La corriente en la fuente V1: echo print I1 echo echo La corriente en la malla: echo print I2 echo La corriente en la fuente V2: echo print I3 .endc .end