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FUTURE IPR FOR VERTICAL WELL

Dengan bertambahnya waktu produksi (Np), maka tekanan reservoir berkurang (p )  perubahan pada sifak fisik reservoir seperti: , Rs, Bo. Menyebabkan perubahan kurva IPR

METODE IPR DI MASA MENDATANG 1. Metode Fetkovich  Harga eksponen (n) tetap selama masa produksi  Konstanta aliran (Jo) berubah. PRESENT IPR

FUTURE IPR

Example # 1 Given data: four-point oil well test, Pr = 2500 psia dan Pb = 3000 psia Test

qo

Pwf

1

880

2000

2

1320

1500

3

1595

1000

Calculate: 4 1752 500 a. Value of exponent n b. Value of Jo c. PRESENT IPR EQUATION d. Absolute open flow potential (AOFP) or q omax e. qo for Pwf = 2200 psia f. FUTURE IPR EQUATION g. qo,max when Pr lowers to 1800 psia h. qo for Pwf = 800 psia when Pr = 1800 psia i. Construct IPR @ Pr = 2500 psia and IPR @ Pr = 1800 psia.

Solution of Example # 1 a. Prepare a table as follows: Test

qo

Pwf

(Pr2-Pwf2)x103

1

880

2000

2250

2

1320

1500

4000

3

1595

1000

5250

4

1752

500

6000

b. Construct a graph on log-log paper based on paper: (Pr2-Pwf2) psi2

10000000

1000000 100000 10000

y = 143.57x1.4247 R² = 1

1000 100

100

1000 q (bpd)

10000

Solution of Example # 1 c. Find the exponent, n, n = 1/Slope = 1/1.4247 = 0.7019 d. Find, Jo,

e. PRESENT IPR

f. Find AOFP

Solution of Example # 1 g. Find qo for Pwf = 2200 psia

h. FUTURE IPR

i. qo,max when Pr lowers to 1800 psia

Solution of Example # 1 g. Find qo for Pwf = 800 psia when Pr = 1800 psia i. Construct IPR @ Pr = 2500 psia and IPR @ Pr = 1800 psia. PRESENT IPR FUTURE IPR q, bpd 1805.51 1797.39 1772.94 1731.87 1673.67 1597.54 1502.35 1386.42 1247.29 1081.13 881.39 634.91 302.36 0.00

Pwf, psia 0 200 400 600 800 1000 1200 1400 1600 1800

q, bpd 819.73 812.62 791.11 754.69 702.41 632.64 542.62 427.14 274.00 0

2500

Present Future

2000

Pwf, psia

Pwf, psia 0 200 400 600 800 1000 1200 1400 1600 1800 2000 2200 2400 2500

1500 1000 500

0 0

500

1000 q, bpd

1500

2000

METODE IPR DI MASA MENDATANG 2. Metode Eickmer  Menggabungkan Future IPR Fetkovich dan Vogel.  Harga eksponen aliran sama dengan 1, maka laju alir maksimum pada kondisi awal dapat dibandingkan dengan laju alir maksimum di masa mendatang.  Hubungan q dan pwf di masa mendatang menggunakan persamaan Vogel PRESENT IPR FUTURE IPR

PRESENT-FUTURE CORR

Example # 2 Given data: Pr = 3000 psia (Pb = 3000 psia) A test shows q = 200 bpd at a flowing pressure of 2500 psia. Calculate: (1). qomax at 3000 psia (2). qomax when the static pressure drops to 2000 psia (3). Construct PRESENT IPR Curve (@2500 psia) and FUTURE IPR Curve (@2000 psia) (4). Qo for Pr = 2000 psia and Pwf = 1000 psia

Solution of Example # 2 (1). qomax at 3000 psia (Eq.4a)

(2). qomax when the static pressure drops to 2000 psia (Eq. 5)

Solution of Example # 2 (3). Construct PRESENT IPR Curve (@2500 psia) and FUTURE IPR Curve (@2000 psia) Present (Eq. 4a) Pwf, psia 0 200 400 600 800 1000 1200 1400

q, bpd Pwf, psia 720 1600 707.84 1800 690.56 2000 668.16 2200 640.64 2400 608 2600 570.24 2800 527.36 3000

Present (Eq. 4b) q, bpd 479.36 426.24 368 304.64 236.16 162.56 83.84 0

Pwf, psia 0 200 400 600 800 1000

q, bpd Pwf, psia 213 1200 207.04 1400 197.66 1600 184.88 1800 168.70 2000 149.1

q, bpd 126.10 99.68 69.86 36.64 0

Pwf, psia

Solution of Example # 2 3500 3000 2500 2000 1500 1000 500 0

Present Future

0

200

400 q, bpd

600

800

(4). Qo for Pr = 2000 psia and Pwf = 1000 psia (Eq. 4b)

METODE IPR DI MASA MENDATANG 3. Metode Pudjo Sukarno

METODE IPR DI MASA MENDATANG • If API  40

• If API < 40

Example # 3 Given data: Pr = 1345 psia (Pb = 3000 psia) A test shows q = 321 bpd at a flowing pressure of 719 psia. API > 40 and S = 0 Calculate: (1). qomax at 1345 psia (2). qomax when the static pressure drops to 1000 psia (3). Construct PRESENT IPR Curve (@1345 psia) and FUTURE IPR Curve (@719 psia)

Solution of Example # 3

(1). qomax at 1345 psia

Solution of Example # 3 (2). qomax when the static pressure drops to 1000 psia (Eq. 6)

(3). Construct PRESENT IPR Curve (@1345 psia) and FUTURE IPR Curve (@719 psia) 1500 Present (Eq.5) Future (Eq.5) q, bpd 432.43 422.57 396.85 294.08 211.75 102.17 0.85

Pwf, psia 0 200 400 800 1000

q, bpd 183.95 176.74 157.21 73.89 0.36

Present

Pwf, psia

Pwf, psia 0 200 400 800 1000 1200 1345

1000

Future

500

0 0

200

q, bpd

400

600

METODE IPR DI MASA MENDATANG 4. Metode Sukarno-Ariadji-Regina  Menggabungkan Asumsi IPR Vogel, Sukarno, Klins, dan Wiggins. PRESENT IPR (depletion Np/N = 1%-4%)

FUTURE IPR (depletion Np/N = 6%-8%)

PRESENT-FUTURE correlation

Example # 4 Given data: Pr = 1345 psia (Pb = 3000 psia) A test shows q = 321 bpd at a flowing pressure of 719 psia. API > 40 and S = 0 Calculate: (1). qomax at 1345 psia (2). qomax when the static pressure drops to 1000 psia (3). Construct PRESENT IPR Curve (@1345 psia) and FUTURE IPR Curve (@719 psia)

Solution of Example # 4

(1). qomax at 1345 psia (Eq. 8)

(2). qomax when the static pressure drops to 1000 psia (Eq.10)

Solution of Example # 4 (3). Construct PRESENT IPR Curve (@1345 psia) and FUTURE IPR Curve (@719 psia) Present (Eq.8) Future (Eq.9) q, bpd 501 471.19 425.78 364.74 288.10 195.84 87.97 0

Pwf, psia q, bpd 0 196.6 200 172.84 400 141.29 600 101.97 800 54.87 1000 0

1500 Pwf, psia

Pwf, psia 0 200 400 600 800 1000 1200 1345

Present

1000

Future 500 0 0

200

q, bpd

400

600

ASSIGNMENT Obtained isochronal test data: Pr = 1350 psi. Flow Test

Qo , bpd

Pwf, psia

1

134

1142

2

229

921

3

321

719

Apply Fetkovich, Eickmer, Sukarno, Sukarno-Ariadji-Regina Methods to a. Calculate qo max at present. b. Draw Present IPR Curves @ Pr = 1350 psia. c. Calculate qo max at future when reservoir pressure (Pr) drop to 1000 psia and 800 psia. d. Draw Future IPR Curves @ Pr = 1000 psia and Pr = 800 psia. e. Calculate qo if pwf = 400 psia and Pr = 800 psia.