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CALCULATION SHEET FOR SPINNING-MEMBRANE DEAERATOR (JOB NO.: 86811-345) (DRAWING NO.: HMC-250(13)-00. REV. 0)

3 2 1 0 REVISION

DATE

DESCRIPTION

DESIGNED BY ENGINEER

TECHNOLOGY DEPT. MANAGER

青岛畅隆电力设备有限公司 QINGDAO CHANGLONG POWER EQUIPMENT Co. Ltd .

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TABLE OF CONTENTS

1

DESIGN DATA

3

2

MAX. ALLOWABLE STRESS AT DESIGN TEMPERATURE

6

3

THICKNESS OF CYLINDRICAL SHELL UNDER INTERAL PRESSURE

7

4

THICKNESS OF ELLIPSOIDAL HEADS, PRESSURE ON CONCAVE SIDE

9

5

THICKNESS OF NOZZLE NECK UNDER INTERNAL PRESSURE

12

6

MAX. ALLOWABLE WORKING PRESSURE

21

7

HYDROSTATIC TEST PRESSURE AND TEMPERATURE

22

8

REINFORCEMENT FOR OPENINGS

23

9

PRESSURE-TEMPERATURE RATING FOR ASME FLANGE

139

10

THE CALCULATION OF LIFTING LUG

140

11

CHECK FOR STRENGTH AND STABILITY OF THE HORIZONTAL VESSEL

148

12

CHECK FOR POST WELD HEAT TREATMENT

152

13

EVALUATION OF IMPACT TEST REQUIREMENT

152

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1. DESIGN DATA: ASME BOILER AND PRESSURE VESSELS CODE APPLICABLE CODE

SECTION Ⅷ DIVSION 1 2010 EDITION AND

CUSTOMER SPECIFICATION

PED 97/23/EC

(1)

DOC. NO.

2011-83-1-86811-345-0/Rev 0

(2)

DESIGN PRESSURE

INTERNAL 0.65 MPa

(3)

DESIGN TEMPERATURE

300℃

(4)

TYPE OF JOINTS OF CATEGORIES A AND B

TYPE NO.1

(5)

RADIOGRAPHY

SPOT PER UW-11(b)

(6)

JOINT EFFICIENCY

SHELL: 0.85, HEAD: 0.85, SHELL to HEAD: 0.85

(7)

CORROSION ALLOWANCE(TANK/TOWER)

2.6 mm / 3.5 mm.

(8)

MATERIAL

SHELL & HEAD :SA-516MGr.485 NOZZLE: SA-106Gr.B FLANGE: SA-105M

(9)

MAX.

ALLOWABLE

STRESS

AT

DESIGN

TEMPERATURE(SEE TABLE 2.1 )

SA-105: 129.3MPa at 300℃ SA-106Gr.B: 125.3MPa at 300℃ SA-516MGr.485: 136MPa at 300℃

(10)

HEAD TYPE

2:1 Standard Ellipsoidal Head

(11)

CAPACITY (TANK / TOWER)

64.9 m3 /6.7 m3

(12)

SERVICE FLUID

WATER AND STEAM (no lethal)

(13)

MIN. SERVICE TEMPERATURE

-10℃

(14)

THE LOADING CONSIDERED IN DESIGNING

SEE TABLE 1-1

(15)

VESSEL DIMENSIONS

SEE FIG. 1-1

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TABLE 1.1 LOADING CONSIDERED IN DESIGNING DEAERATOR′S TANK

Item 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21

Description Internal pressure External pressure Weight of vessel Weight of normal contents under operation conditions Weight of normal contents under test conditions Superimposed static reactions from weight of attached equipment The attachments of internals The attachments of vessel supports (skirt, legs, saddles etc.) The attachments of hanger Cyclic and dynamic reactions due to pressure Cyclic and dynamic reactions due to thermal variations Cyclic and dynamic reactions due to equipment mounted on the vessel Cyclic and dynamic reactions due to mechanical loadings Wind reactions Snow reactions Seismic reactions Impact reactions, such as those due to fluid shock Temperature gradients Differential thermal expansion Abnormal pressure, such as those caused by deflagration Test pressure and coincident static head acting during the test (See UG-99)

DEAERATOR′S TOWER

Yes [√] [ ] [√] [√]

No [ ] [√] [ ] [ ]

Yes [√] [ ] [√] [ ]

No [ ] [√] [ ] [√ ]

[√] [ ]

[ ] [√]

[√] [ ]

[ ] [√]

[ ] [√]

[√] [ ]

[ ] [√]

[√] [ ]

[√] [ ] [ ]

[ ] [√] [√]

[√] [ ] [ ]

[ ] [√] [√]

[ ]

[√]

[ ]

[√]

[ ]

[√]

[ ]

[√]

[ [ [ [ [ [ [

] ] ] ] ] ] ]

[√] [√] [√] [√] [√] [√] [√]

[ [ [ [ [ [ [

] ] ] ] ] ] ]

[√] [√] [√] [√] [√] [√] [√]

[√ ]

[ ]

[√ ]

[ ]

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LIST OF NOZZLES TABLE 1.2 NOZZLE

NO.

Q’TY

SIZE

TYPE

DESCRIPTION

REMARKS

A1

1

DN500

CLASS150 SO RF

MANHOLE

SA-516MGr.485

A2

1

DN450

CLASS150 SO RF

MANHOLE

SA-516MGr.485

B

1

DN200

WELDING

STEAM CONNECT NOZZLE

SA-106Gr.B

C1-2

2

DN80

WELDING

RECYCLING NOZZLE

SA-106Gr.B

D1-2

2

DN150

CLASS150 SO RF

SAFETY VALVE NOZZLE

SA-106Gr.B

E

1

DN100

WELDING

HP DRAIN INLET

SA-106Gr.B

F

1

DN150

CLASS150 SO RF

CHECK-UP NOZZLE

SA-106Gr.B

G

1

DN80

CLASS150 SO RF

EXHAUST NOZZLE

SA-106Gr.B

H

1

DN200

WELDING

FEED WATER INLET

SA-106Gr.B

I

1

DN150

WELDING

SUPPLY WATER INLET

SA-106Gr.B

J

1

DN80

WELDING

SECONDARY STEAM INLET

SA-106Gr.B

K

1

DN200

WELDING

STEAM INLET

SA-106Gr.B

L

1

DN100

WELDING

M

1

DN80

WELDING

REBOILING NOZZLE

SA-106Gr.B

N

1

DN150

WELDING

OUTFALL NOZZLE

SA-106Gr.B

O

1

DN250

WELDING

DEAERATED WATER OURLET

SA-106Gr.B

P1-2

2

DN10

WELDING

SAMPLING WATER NOZZLE

SA-106Gr.B

Q

1

DN200

WELDING

WATER CONNECT NOZZLE

SA-106Gr.B

R

1

DN250

WELDING

DEAERATED WATER OURLET

SA-106Gr.B

S

1

DN100

WELDING

HIGH LEVEL ELECTRIC OFFLET

SA-106Gr.B

T1-2

2

DN50

CLASS150 SO.RF

ELECTRIC CONTACT LEVEL GAUGE NOZZLE

SA-106Gr.B

STEAM LEAKING FROM GATE POLE

SA-106Gr.B

NOZZLE

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Q’TY

SIZE

TYPE

DESCRIPTION

REMARKS

U1-4

4

DN50

CLASS150 SO RF

EQUALIZER NOZZLE

SA-106Gr.B

V1-2

2

DN20

INTERNAL THREAD

V3

1

DN20

INTERNAL THREAD

RESISTANCE THERMOMETER NOZZLE

SA-105M

W1-2

2

DN15

INTERNAL THREAD

PRESSURE GAUGE

SA-105M

W3

1

DN10

WELDING

PRESSURE SIGNAL NOZZLE

SA-106Gr.B

X1-2

2

DN50

CLASS150 PL. RF

LEVEL GAUGE NOZZLE

SA-106Gr.B

Y1

1

DN100

WELDING

Z1-2

2

DN50

CLASS150 SO RF

Y2

1

DN80

WELDING

BIMETALLIC THERMOMETER NOZZLE

DRAIN INLET

SA-105M

SA-106Gr.B

ELECTRIC CONTACT LEVEL GAUGE NOZZLE

SA-106Gr.B

WATER FROM SLAG-COOLER INLET

SA-106Gr.B

Note: Bolt holes of flanges shall straddle center line of the vessel.

FIG.1-1 Brief Drawing of Shell

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2. MAX. ALLOWABLE STRESS AT DESIGN TEMPERATURE TABLE 2.1 ALLOWABLE STRESS VALUE (MPa) ASME

SHELL AND HEAD MATERIAL SA-516MGr.485 PIPE MATERIAL SA-106Gr.B FLANGE MATERIAL SA-105 BOLT MATERIAL SA-193.B7

YIELD STRENGTH

TENSILE STRENGTH

VALUE (MPa)

VALUE (MPa)

ASME

ASME

PED

300℃

20℃

300℃

20℃

300℃

20℃

300℃

20℃

136

138

136

174.6

204

262

483

483

118

118

125.3

160.6

188

241

414

414

129

138

129.3

165.3

194

248

483

483

130

130

287

287

595

724

689

689

注/NOTE: 1 材料的许用应力取值依据 PED/97/23/EC 附录Ⅰ规定: MATERIAL ALLOWANCE STRESS VALUE IS IN ACCORDANCE WITH PED/97/23/EC REGULATION ANNEX Ⅰ: 1. 对材料/FOR MATERIAL SA-516MGr.485: Re/t=204MPa, Rm/20=483MPa, Sd=MIN{Re/t×2/3, Rm/20×5/12}=136 MPa 2. 对 材 料 /FOR MATERIAL SA-106Gr.B: Re/t=188MPa, Rm/20=414MPa, Sd=MIN{Re/t × 2/3, Rm/20×5/12}=125.3 MPa 3. 对材料/FOR MATERIAL SA-105: Re/t=194MPa, Rm/20=483MPa, Sd=MIN{Re/t×2/3, Rm/20× 5/12}=129.3 MPa 4. 对材料/FOR MATERIAL SA-193.B7: Re/t=595MPa, Rm/20=689MPa, Sd=MIN{Re/t×2/3, Rm/20 ×5/12}=287 MPa

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3. THICKNESS OF CYLINDRICAL SHELL UNDER INTERNAL PRESSURE 3-1 DEAERATOR′S TANK: ASME SEC.Ⅷ DIV.1 UG-27 z Part z Design pressure

:

Shell of tank

P (MPa)

:

0.65

(℃)

:

300

:

SA-516MGr.485

z Design temperature z Material z Maximum allowable stress value at design temperature Sd

(MPa)

:

136

z Maximum allowable stress value at test temperature

St

(MPa)

:

174.6

z Height to point under consideration

H

(m)

:

6.769

z Density of test medium (water) at test temperature

ρ (kg/m3)

:

1000

z Type of welded joints in TABLE UW-12

:

Type No. (1)

z Radiographic examination

:

SPOT Per UW-11(b)

z Joint efficiency (specified in UW-12)

E

z Negative Deviation:

C1

z Corrosion allowance (designated by customer)

:

0.85

(mm)

:

0.3

C2

(mm)

:

2.6

z Nominal shell thickness

tn

(mm)

z Inside radius corroded

R

(mm)

z Final center line radius

16 :

1402.6

Rf (mm)

:

1408

z Original center line radius (specified in UCS-79)

Ro (mm)

:

∞(Infinity）

z Shell length

L (mm)

:

9280

z Total weight

WT (kg)

:

95000

z Reaction at each saddle

Q (N)

:

465975

z Head depth

H (mm)

:

700

z Saddle to tangent line

A (mm)

:

1140

(1)

Thickness calculation for shells under internal pressure with supplemental loading. Here three cases must be investigated: (a)

circumferential stress due to internal pressure

(b)

longitudinal tensile stress due to bending must be added to the longitudinal stress due to

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internal pressure. (c)

Longitudinal compressive stress due to bending.

Case 1 circumferential tensile stress. In this horizontal vessel; the equation in UG-27 (c)(1) is used: P = 0.65 + ρgH/106 = 0.65 + 1000×9.81×6.769/106 = 0.7165 MPa

t1 =

PR 0.7165 × 1402.6 = = 8.73mm S d E − 0.6 P 136 × 0.85 − 0.6 × 0.7165

Case 2 longitudinal tensile stress. The following equation combines longitudinal tensile stress due to pressure with the longitudinal tensile stress due to bending at the midpoint between two saddles:

⎡ 2( R 2 − H 2 ) ⎤ 1+ ⎢ 2 QL 4A⎥ PR L × − ± t2 = ⎢ ⎥ 4H L ⎥ 2SE + 0.4 P 4πR 2 SE ⎢ 1+ ⎥⎦ 3L ⎣⎢ =

0.7165 × 1402.6 ± 2 × 136 × 0.85 + 0.4 × 0.7165

⎡ 2(1402.62 − 7002 ) ⎤ 1+ ⎢ 2 465975 × 9280 4 × 1140 ⎥ 9280 × − ⎢ ⎥ 4 × 700 4π× 1402.62 × 136 × 0.85 ⎢ 9280 ⎥ 1+ ⎥⎦ 3 × 9280 ⎣⎢ = 4.35 ± 1.514×(0.9242-0.4914) = 4.35 ± 0.656 = 5.006 mm Case 3 Longitudinal compressive stress. First determine the allowable compressive stress [see UG-23(b)] A=

0.125 0.125 = = 0.00141 RO / t 1418.6 / 16

B= 70 MPa (from Fig. CS-2) The general equation for thickness is the same as for longitudinal tensile stress except the pressure portion drops out since the most servere condition occurs when there is no pressure in the vessels.

⎡ 2( R 2 − H 2 ) ⎤ ⎢1 + ⎥ 2 4 A QL L ×⎢ − t3 = ⎥ 2 4H 4πR SE ⎢ L ⎥ 1+ ⎢⎣ ⎥⎦ 3L

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⎡ 2(1402.62 − 7002 ) ⎤ ⎢1 + ⎥ 2 465975 × 9280 4 × 1140 9280 × − = ⎢ ⎥ 4 × 700 4π× 1402.6 2 × 70 × 0.85 ⎢ 9280 ⎥ 1+ ⎥⎦ 3 × 9280 ⎣⎢ = 2.94×(0.9242-0.4914) = 1.28 mm (2)

Design thickness Required minimum shell thickness including allowance t = max(t1,t2,t3) + C1+C2 = 8.73+0.3+2.6 = 11.63 mm

(3)

Provided thickness Nominal thickness (mm) 16 > t

(4)

OK

Check minimum required thickness for paragraph UG-16 (b) (4) Minimum thickness required (including corrosion allowance) : 2.5 + 2.6 = 5.1 mm, nominal thickness is 16 mm > 5.1 mm, OK

(5)

Check extreme fiber elongation for paragraph UCS-79 Maximum allowable fiber elongation without post weld heat treatment is based on the following formula: For single curvature

r=

50t ⎛ R f ⎞ 50 × 16 ⎛ 1408 ⎞ ⎜⎜1 − ⎟⎟% = × ⎜1 − ⎟% = 0.569% < 5% Rf ⎝ R0 ⎠ 1408 ⎝ ∞ ⎠

None of the conditions in UCS-79 (1~5) apply, so no heat treatment after cold forming need to apply.

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3-2 DEAERATOR′S TOWER: ASME SEC.Ⅷ DIV.1 UG-27 z Part z Design pressure

:

Shell of tower

P (MPa)

:

0.65

(℃)

:

300

:

SA-516MGr.485

z Design temperature z Material z Maximum allowable stress value at design temperature Sd

(MPa)

:

136

z Maximum allowable stress value at test temperature

St

(MPa)

:

174.6

z Height to point under consideration

H

(m)

:

2.950

z Density of test medium (water) at test temperature

ρ (kg/m3)

:

1000

z Type of welded joints in TABLE UW-12

:

Type No. (1)

z Radiographic examination

:

SPOT Per UW-11(b)

z Joint efficiency (specified in UW-12)

E

z Negative Deviation:

C1

z Corrosion allowance (designated by customer)

:

0.85

(mm)

:

0.3

C2

(mm)

:

3.5

z Nominal shell thickness

tn

(mm)

z Inside radius corroded

R

(mm)

z Final center line radius z Original center line radius (specified in UCS-79) (1)

12 :

903.5

Rf (mm)

:

906

Ro (mm)

:

∞（Infinity）

Required minimum shell thickness excluding allowance (circumferential stress) 0.385SE = 0.385×136×0.85=44.506> P (a)

For design condition

tmin 1 = (b)

according to UG-27(b)&(c)

PR 0.65 × 903.5 = = 5.10mm S d E − 0.6 P 136 × 0.85 − 0.6 × 0.65

For hydrostatic test condition

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PR (9.81Hρ / 106 ) R + St E − 0.6 P St E − 0.6(9.81Hρ / 106 )

0.65 × 903.5 9.81 × 2.95 × 1000 / 106 × 903.5 = + 174.6 × 0.85 − 0.6 × 0.65 174.6 × 0.85 − 0.6 × (9.81 × 2.95 × 1000 / 106 ) = 3.97 + 0.15 = 4.12mm (2)

Design thickness Required minimum shell thickness including allowance T = max(tmin1,tmin2)+C1+C2 = 5.10 + 0.3 + 3.5 = 8.9 mm

(3)

Provided thickness Nominal thickness (mm) 12 > t

(4)

OK

Check minimum required thickness for paragraph UG-16 (b) (4) Minimum thickness required (including corrosion allowance) : 2.5 + 3.5 = 6.0 mm, nominal thickness is 12 mm> 6.0 mm, OK

(5)

Check extreme fiber elongation for paragraph UCS-79 Maximum allowable fiber elongation without post weld heat treatment is based on the following formula: For single curvature

r=

50t ⎛ R f ⎞ 50 × 12 ⎛ 906 ⎞ ⎜⎜1 − ⎟⎟% = × ⎜1 − ⎟% = 0.663% < 5% Rf ⎝ R0 ⎠ 906 ∞ ⎠ ⎝

None of the conditions in UCS-79 (1~5) apply, so no heat treatment after cold forming need to apply.

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4. THICKNESS OF ELLIPSOIDAL HEAD, PRESSURE ON CONCAVE SIDE 4-1 DEAERATOR′S TANK: ASME SEC.Ⅷ DIV.1 UG-32 ●Part ●Design

pressure

●Design

temperature

P (MPa) (℃)

●Material

:

Heads of tank

:

0.65

:

300

:

SA-516MGr.485

●Maximum

allowable stress value at design temperature

Sd

(MPa)

:

136

●Maximum

allowable stress value at test temperature

St

(MPa)

:

174.6

●Height

to point under consideration

(left head)

H

(m)

:

6.769

●Height

to point under consideration

(right head)

H

(m)

:

6.769

:

1000

Type of welded joints in TABLE UW-12

:

Type No. (1)

Radiographic examination

:

SPOT

●Density

of test medium at test temperature

ρ(kg/m3)

Per UW-11(b) ●Weld

joining heads to shell

:

Type No. (1)， SPOT

Per

UW-11(b) ●Joint

efficiency (specified in UW-12(d))

E

:

0.85

Negative Deviation:

C1

(mm)

:

0.3

●Corrosion

C2

(mm)

:

2.6

allowance (designated by customer)

●Inside

diameter of ellipsoidal head (corroded)

D

●Inside

spherical radius of hemispherical head

R

● Crown

final centerline radius

(specified in UG-32(d)

2805.2 (mm)

:

1402.6

Rf (mm)

:

2528

rf

(mm)

:

482.96

R0 (mm)

:

∞（Infinity）

and UCS-79) ●Knuckle

final centerline radius (specified in UG-32(d)

and UCS-79) ●Original

center line radius (specified in UCS-79)

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Required minimum head thickness Without joint, according to UW-12(d), E=0.85, L = 0.9D = 0.9×2805.2 = 2524.68 mm ts/L = 13.92/2524.68=0.00552 > 0.002

according to UG-32(d)

(a) For the left head according to UG-32(d) (a-1) for design condition Required minimum head thickness excluding allowance tmin

tmin 1 =

PD 0.65 × 2805.2 = = 7.90mm 2S d E − 0.2 P 2 × 136 × 0.85 − 0.2 × 0.65

(b) For the right head (b-1) for design condition Required minimum head thickness excluding allowance tmin

tmin 2 =

PD 0.65 × 2805.2 = = 7.90mm 2S d E − 0.2 P 2 × 136 × 0.85 − 0.2 × 0.65

(b-2) for hydrostatic test condition (Due to same dimension for ellipsoidal heads, the bottom head will be applied for calculation)

tmin 3 =

PD (9.81Hρ / 106 ) D + 2St E − 0.2 P 2St E − 0.2(9.81Hρ / 106 )

0.65 × 2805.2 9.81 × 6.769 × 1000 / 106 × 2805.2 + 2 × 174.6 × 0.85 − 0.2 × 0.65 2 × 174.6 × 0.85 − 0.2 × (9.81 × 6.769 × 1000 / 106 ) = 6.15 + 0.63 = 6.78mm =

(2)

Design thickness Required minimum head thickness including allowance t= max(tmin1,tmin2,tmin3) + C1+C2 = 7.90 + 0.3 + 2.6 = 10.8 mm

(3)

Provided thickness Nominal thickness (mm) 16 Minimum thickness after forming (mm) 13.92 ≥ t OK

(4)

Check minimum head thickness for hemispherical head from paragraph UG-32 (b) & (f) 0.665SE = 0.665 × 136× 0.85 = 76.874 MPa >P

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Required minimum hemispherical head thickness

tmin h =

PL 0.65 × 2524.68 = = 7.11mm 2SE − 0.2 P 2 × 136 × 0.85 − 0.2 × 0.65

Tr = tminh/E= 7.11/0.85 = 8.37 mm < 13.92 mm OK (5)

Check minimum required thickness for paragraph UG-16(b)(4) Minimum thickness required (including corrosion allowance) : 2.5+2.6 = 5.1mm, minimum thickness after forming is 13.92 mm.> 5.1 mm

(6)

OK

Check extreme fiber elongation for paragraph UCS-79 Maximum allowable fiber elongation without heat treatment is based on the following formula: For double curvature Crown radius elongation

r=

75t ⎛ R f ⎞ 75 × 16 ⎛ 2528 ⎞ ⎜⎜1 − ⎟⎟% = × ⎜1 − ⎟% = 0.475% < 5% Rf ⎝ R0 ⎠ 2528 ⎝ ∞ ⎠

Knuckle radius elongation

r=

r ⎞ 75t ⎛ 75 × 16 ⎛ 482.96 ⎞ ⎜⎜1 − f ⎟⎟% = × ⎜1 − ⎟% = 2.49% < 5% rf ⎝ R0 ⎠ 482.96 ⎝ ∞ ⎠

None of the conditions listed in UCS-79(d)(1) through (5) exist, so no heat treatment of heads after cold forming need to apply for SA-516MGr.485 (P-NO.1 Group NO.2).

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DEAERATOR′S TOWER: ASME SEC.Ⅷ DIV.1 UG-32

●Part ●Design

pressure

●Design

temperature

P (MPa) (℃)

●Material

:

Heads of tower

:

0.65

:

300

:

SA-516MGr.485

●Maximum

allowable stress value at design temperature

Sd

(MPa)

:

136

●Maximum

allowable stress value at test temperature

St

(MPa)

:

174.6

●Height

to point under consideration

(bottom head)

H

(m)

:

3.437

●Height

to point under consideration

(top head)

H

(m)

:

0.787

:

1000

Type of welded joints in TABLE UW-12

:

Type No. (1)

Radiographic examination

:

SPOT

●Density

of test medium at test temperature

ρ(kg/m3)

Per UW-11(b) ●Weld

joining heads to shell

:

Type No. (1)， SPOT

Per

UW-11(b) ●Joint

efficiency (specified in UW-12(d))

E

:

0.85

Negative Deviation:

C1

(mm)

:

0.3

●Corrosion

C2

(mm)

:

3.5

allowance (designated by customer)

●Inside diameter of ellipsoidal head (corroded)

D

●Inside spherical radius of hemispherical head

R

(mm)

:

903.5

●Crown final centerline radius

Rf (mm)

:

1626

rf

(mm)

:

311.22

R0 (mm)

:

∞（Infinity）

(specified in UG-32(d)

1807

and UCS-79) ●Knuckle

final centerline radius (specified in UG-32(d)

and UCS-79) ●Original

(1)

center line radius (specified in UCS-79)

Required minimum head thickness Without joint, according to UW-12(d), E = 0.85, L=0.9D = 0.9×1807 = 1626.3mm

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

ts/L = 10.44/1626.3 =0.00642 > 0.002 (a) For the top head

PAGE

17

OF

152

according to UG-32(d)

according to UG-32(d)

(a-1) for design condition Required minimum head thickness excluding allowance tmin

tmin 1 =

PD 0.65 × 1807 = = 5.09mm 2S d E − 0.2 P 2 × 136 × 0.85 − 0.2 × 0.65

(b) For the bottom head (b-1) for design condition Required minimum head thickness excluding allowance tmin

tmin 2 =

PD 0.65 × 1807 = = 5.09mm 2 S d E − 0.2 P 2 × 136 × 0.85 − 0.2 × 0.65

(b-2) for hydrostatic test condition (Due to same dimension for ellipsoidal heads, the bottom head will be applied for calculation)

tmin 3 =

PD (9.81Hρ / 106 ) D + 2St E − 0.2 P 2St E − 0.2(9.81Hρ / 106 )

0.65 × 1807 9.81 × 3.437 × 1000 / 106 × 1807 = + 2 × 174.6 × 0.85 − 0.2 × 0.65 2 × 174.6 × 0.85 − 0.2 × (9.81 × 3.437 × 1000 / 106 ) = 3.96 + 0.21 = 4.17 mm (2)

Design thickness Required minimum head thickness including allowance t=max(tmin1,tmin2,tmin3)+C1+C2= 5.09 + 0.3+3.5 = 8.89 mm

(3)

Provided thickness Nominal thickness (mm) 12 Minimum thickness after forming (mm) 10.44 ≥ t OK

(4)

Check minimum head thickness for hemispherical head from paragraph UG-32 (b) & (f) 0.665SE = 0.665 × 136× 0.85 =76.874 MPa

>P

Required minimum hemispherical head thickness

DOC. NO.: 2011-83-1-86811-342-0

tmin h =

REV.: 0

PAGE

18

OF

152

PL 0.65 × 1626.3 = = 4.58mm 2SE − 0.2 P 2 × 136 × 0.85 − 0.2 × 0.65

tr=tminh/E= 4.58/0.85 = 5.39 mm < 10.44 mm OK (5)

Check minimum required thickness for paragraph UG-16(b)(4) Minimum thickness required (including corrosion allowance) : 2.5 + 3.5 = 6.0 mm, minimum thickness after forming is 10.44 mm.> 6.0 mm

(6)

OK

Check extreme fiber elongation for paragraph UCS-79 Maximum allowable fiber elongation without heat treatment is based on the following formula: For double curvature Crown radius elongation

r=

75t ⎛ R f ⎞ 75 × 12 ⎛ 1626 ⎞ ⎜⎜1 − ⎟⎟% = × ⎜1 − ⎟% = 0.554% < 5% Rf ⎝ R0 ⎠ 1626 ⎝ ∞ ⎠

Knuckle radius elongation

r=

r ⎞ 75t ⎛ 75 × 12 ⎛ 311.22 ⎞ ⎜⎜1 − f ⎟⎟% = × ⎜1 − ⎟% = 2.892% < 5% rf ⎝ R0 ⎠ 311.22 ⎝ ∞ ⎠

None of the conditions listed in UCS-79(d)(1) through (5) exist, so no heat treatment of heads after cold forming need to apply for SA-516MGr.485 (P-NO.1 Group NO.2).

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

19

OF

152

5. THICKNESS OF NOZZLE NECK INTERNAL PRESSURE 5-1 DEAERATOR′S TANK: 5-1-1

FOR NOZZLE A1

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-516M Gr.485

Sd (MPa)

:

136

St (MPa)

:

174.6

:

SA-516M Gr.485

Ss (MPa)

:

136

H (m)

:

6.387

ρ(k/m3)

:

1000

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of head

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

Type No. (1)

UW-12 ●Radiographic ●Joint

efficiency of nozzle neck (specified in UW-12)

●Negative

Deviation:

●Corrosion ●Outside

allowance (designated by customer)

radius of nozzle neck

SPOT Per UW-11(b) E

:

0.85

:

0.3

C2 (mm)

:

2.6

Ro

:

254

C1

(mm)

(mm)

●Inside

radius of nozzle corroded

R (mm)

:

244.6

●Inside

radius of shell corroded

Rs

:

1402.6

Rf (mm)

:

248

R0 (mm)

:

∞(Infinity)

●Final

center line radius of nozzle

●Original

(1)

examination of nozzle neck

center line radius of nozzle

(mm)

Minimum required thickness of nozzle par. UG-45 (a) and UG-27 (c) (1)

0.385SE = 0.385×136×0.85 = 44.506 > P (a)

under design condition

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

20

OF

152

Required minimum thickness including allowance

tmin 1 =

PR 0.65 × 244.6 +C = + 0.3 + 2.6 = 1.39 + 2.9 = 4.29mm S d E − 0.6 P 136 × 0.85 − 0.6 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2

PR (9.81Hρ / 106 ) R = + +C St E − 0.6 P St E − 0.6(9.81Hρ / 106 )

0.65 × 244.6 9.81 × 6.387 × 1000 / 106 × 244.6 + + 0.3 + 2.6 174.6 × 0.85 − 0.6 × 0.65 174.6 × 0.85 − 0.6 × (9.81 × 6.387 × 1000 / 106 ) = 1.08 + 0.11 + 2.9 = 4.09mm

=

(c) With supplemental loading by flange and cover ●

Weight of flange and cover

W = 250 kg

●

Bending moment due to supplemental loading Under operating condition

M1 = 250×9.81×0.166= 408 N·m

Under cover opened condition

M2 = 250×9.81×0.466=1143 N·m

Per UG-27(c) and Appendix L, Use S = 136 × 1.5 = 204 MPa (see UG-23(c))

PR M + 21 +C 2SE + 0.4 P πR SE 0.65 × 244.6 408 = + + 0.3 + 2.6 2 2 × 204 × 0.85 + 0.4 × 0.65 π × 244.6 × 204 × 0.85 = 0.46 + 0.000013 + 2.9 ≈ 3.4mm

t3 =

M2 1143 +C = + 0.3 + 2.6 = 0.00004 + 2.9 ≈ 3.0mm 2 πR SE π × 244.6 2 × 204 × 0.85

t4 = (2)

Provided thickness Nominal thickness (mm) 12 > tmin1,tmin2,t3,t4

(3)

OK

Check extreme fiber elongation for paragraph UCS-79 Maximum allowable fiber elongation without post weld heat treatment is based on the following formula: for single curvature

r=

50t ⎛ R f ⎞ 50 × 12 ⎛ 248 ⎞ ⎜⎜1 − ⎟⎟% = × ⎜1 − ⎟% = 2.42% < 5% Rf ⎝ R0 ⎠ 248 ⎝ ∞ ⎠

None of the condition list in UCS-79 (d) (1-5) exists, so no heat treatment after cold forming need to apply.

DOC. NO.: 2011-83-1-86811-342-0

5-1-2 FOR NOZZLE

REV.: 0

B.K

PAGE

OF

152

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

3.953

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

109.55

tstd (mm)

:

8.18

Rs

:

1402.6

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

21

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 109.55 +C = + 2.6 = 3.17mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

DOC. NO.: 2011-83-1-86811-342-0

tmin 2 =

REV.: 0

PAGE

22

OF

152

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 109.55 9.81 × 3.953 × 1000 / 106 × 109.55 = + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 3.953 × 1000 / 106 ) = 0.45 + 0.03 + 2.6 = 3.08mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 8.18 + 2.6 = 9.76 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 9.33 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 12.7 Minimum thickness (mm) 12.7×0.875 = 11.11 ≥ t 5-1-3

FOR NOZZLE

OK

C1-2. .M

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

3.953

ρ(kg/m3)

:

1000

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Nominal ●Inside

(1)

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

44.45

tstd (mm)

:

5.49

Rs

:

1402.6

C

radius of nozzle neck thickness of the standard wall pipe(B36.10M)

radius of shell corroded

OF

: E

allowance (designated by customer)

23

(mm)

152

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 44.45 +C = + 2.6 = 2.84mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 44.45 9.81 × 3.953 × 1000 / 106 × 44.45 + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 3.953 × 1000 / 106 ) = 0.18 + 0.02 + 2.6 = 2.8mm

=

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 5.49 + 2.6 = 7.41 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.41 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t

OK

DOC. NO.: 2011-83-1-86811-342-0

5-1-4

FOR NOZZLE

REV.: 0

D1

PAGE

OF

152

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

3.953

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

84.15

tstd (mm)

:

7.11

Rs

:

1402.6

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

24

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 84.15 +C = + 2.6 = 3.04mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

DOC. NO.: 2011-83-1-86811-342-0

tmin 2 =

REV.: 0

PAGE

25

OF

152

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 84.15 9.81 × 3.953 × 1000 / 106 × 84.15 = + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 3.953 × 1000 / 106 ) = 0.35 + 0.03 + 2.6 = 2.98mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 7.11 + 2.6 = 8.82 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 8.82 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 10.97 Minimum thickness (mm) 10.97×0.875 = 9.6 ≥ t 5-1-5

FOR NOZZLE

OK

L

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

3.953

ρ(kg/m3)

:

1000

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Nominal ●Inside

(1)

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

57.15

tstd (mm)

:

6.02

Rs

:

1402.6

C

radius of nozzle neck thickness of the standard wall pipe(B36.10M)

radius of shell corroded

OF

: E

allowance (designated by customer)

26

(mm)

152

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 57.15 +C = + 2.6 = 2.9mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 57.15 9.81 × 3.953 × 1000 / 106 × 57.15 + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 3.953 × 1000 / 106 ) = 0.24 + 0.02 + 2.6 = 2.86mm

=

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 ×6.02 + 2.6 = 7.87 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.87 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t

OK

DOC. NO.: 2011-83-1-86811-342-0

5-1-6 FOR NOZZLE

REV.: 0

N

PAGE

OF

152

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

6.919

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

84.15

tstd (mm)

:

7.11

Rs

:

1402.6

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

27

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 84.15 +C = + 2.6 = 3.04mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

DOC. NO.: 2011-83-1-86811-342-0

tmin 2 =

REV.: 0

PAGE

28

OF

152

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 84.15 9.81 × 6.919 × 1000 / 106 × 84.15 = + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 6.919 × 1000 / 106 ) = 0.35 + 0.04 + 2.6 = 2.99mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 7.11 + 2.6 = 8.82 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 8.82 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 10.97 Minimum thickness (mm) 10.97×0.875 = 9.6 ≥ t 5-1-7

FOR NOZZLE

OK

O.R

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

6.919

ρ(kg/m3)

:

1000

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Nominal ●Inside

(1)

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

136.5

tstd (mm)

:

9.27

Rs

:

1402.6

C

radius of nozzle neck thickness of the standard wall pipe(B36.10M)

radius of shell corroded

OF

: E

allowance (designated by customer)

29

(mm)

152

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 136.5 +C = + 2.6 = 3.31mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 136.5 9.81 × 6.919 × 1000 / 106 × 136.5 + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 6.919 × 1000 / 106 ) = 0.56 + 0.06 + 2.6 = 3.22mm =

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 9.27 + 2.6 = 10.7 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 9.33 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 12.7 Minimum thickness (mm) 12.7×0.875 = 11.11 ≥ t

OK

DOC. NO.: 2011-83-1-86811-342-0

5-1-8

FOR NOZZLE

REV.: 0

S

PAGE

OF

152

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

6.919

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

57.15

tstd (mm)

:

6.02

Rs

:

1402.6

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

30

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 57.15 +C = + 2.6 = 2.9mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

DOC. NO.: 2011-83-1-86811-342-0

tmin 2 =

REV.: 0

PAGE

31

OF

152

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 57.15 9.81 × 6.919 × 1000 / 106 × 57.15 = + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 6.919 × 1000 / 106 ) = 0.24 + 0.03 + 2.6 = 2.87 mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 ×6.02 + 2.6 = 7.87 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.87 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t 5-1-9 FOR NOZZLE

OK

Q

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

6.919

ρ(kg/m3)

:

1000

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Nominal ●Inside

(1)

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

109.55

tstd (mm)

:

8.18

Rs

:

1402.6

C

radius of nozzle neck thickness of the standard wall pipe(B36.10M)

radius of shell corroded

OF

: E

allowance (designated by customer)

32

(mm)

152

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 109.55 +C = + 2.6 = 3.17mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 109.55 9.81 × 6.919 × 1000 / 106 × 109.55 + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 6.919 × 1000 / 106 ) = 0.45 + 0.05 + 2.6 = 3.1mm =

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 8.18 + 2.6 = 9.76 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 9.33 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 12.7 Minimum thickness (mm) 12.7×0.875 = 11.11 ≥ t

OK

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

OF

152

5-1-10

FOR NOZZLE T1.U1.U3.Z1.X1

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

4.284

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

30.15

tstd (mm)

:

3.91

Rs

:

1402.6

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

33

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 30.15 +C = + 2.6 = 2.76mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

DOC. NO.: 2011-83-1-86811-342-0

tmin 2 =

REV.: 0

PAGE

34

OF

152

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 30.15 9.81 × 4.284 × 1000 / 106 × 30.15 = + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 4.284 × 1000 / 106 ) = 0.13 + 0.008 + 2.6 = 2.738mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 3.91 + 2.6 = 6.02 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 6.02 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 8.74 Minimum thickness (mm) 8.74×0.875 = 7.65 ≥ t

OK

5-1-11

FOR NOZZLE T2.U2.U4.Z2.X2

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

6484

ρ(kg/m3)

:

1000

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Nominal ●Inside

(1)

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

30.15

tstd (mm)

:

3.91

Rs

:

1402.6

C

radius of nozzle neck thickness of the standard wall pipe(B36.10M)

radius of shell corroded

OF

: E

allowance (designated by customer)

35

(mm)

152

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 30.15 +C = + 2.6 = 2.76mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 30.15 9.81 × 6.484 × 1000 / 106 × 30.15 + + 2.6 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 6.484 × 1000 / 106 ) = 0.13 + 0.02 + 2.6 = 2.75mm =

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 3.91 + 2.6 = 6.02 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 6.02 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 8.74 Minimum thickness (mm) 8.74×0.875 = 7.65 ≥ t

OK

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

OF

152

5-1-12

FOR NOZZLE W2

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-105M

Sd (MPa)

:

129.3

St (MPa)

:

165.3

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

5364

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

17.5

tstd (mm)

:

2.77

Rs

:

1402.6

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

36

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 129.3 ×1.00 = 49.78 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 17.5 +C = + 2.6 = 2.69mm S d E + 0.4 P 129.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

DOC. NO.: 2011-83-1-86811-342-0

tmin 2 =

REV.: 0

PAGE

37

OF

152

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 17.5 9.81 × 5.364 × 1000 / 106 × 17.5 = + + 2.6 165.3 × 1 + 0.4 × 0.65 165.3 × 1 + 0.4 × (9.81 × 5.364 × 1000 / 106 ) = 0.07 + 0.006 + 2.6 = 2.676mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 2.77 + 2.6 = 5.02 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 5.02 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 6.5 ≥ t

OK

5-1-13

FOR NOZZLE V2-3

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-105M

Sd (MPa)

:

129.3

St (MPa)

:

165.3

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

5378

ρ(kg/m3)

:

1000

:

Seamless

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12

DOC. NO.: 2011-83-1-86811-342-0

●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

PAGE

E

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

REV.: 0

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

38

OF

:

1.0

(mm)

:

2.6

Ro (mm)

:

25

tstd (mm)

:

2.87

Rs

:

1402.6

C

(mm)

152

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 129.3 ×1.00 = 49.78 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 25 +C = + 2.6 = 2.73mm S d E + 0.4 P 129.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2

PRo (9.81Hρ / 106 ) Ro = + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 25 9.81 × 5.378 × 1000 / 106 × 25 = + + 2.6 165.3 × 1 + 0.4 × 0.65 165.3 × 1 + 0.4 × (9.81 × 5.378 × 1000 / 106 ) = 0.1 + 0.008 + 2.6 = 2.708mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 2.87 + 2.6 = 5.12 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 5.12 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.0 ≥ t OK 5-1-14

FOR NOZZLE P1-2

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

DOC. NO.: 2011-83-1-86811-342-0

●Design

REV.: 0

temperature

●Material

● Allowable

● Type

300

:

SA-105M

Sd (MPa)

:

129.3

St (MPa)

:

165.3

:

SA-106Gr.B

stress of shell at design temperature

Ss (MPa)

:

125.3

H (m)

:

6852

of test medium at test temperature (water)

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

2.6

Ro (mm)

:

12.5

tstd (mm)

:

2.31

Rs

:

126.4

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

152

:

of shell(nozzle R.O)

to point under consideration

●Density

OF

stress of nozzle neck material at test

temperature

●Allowable

39

stress of nozzle neck material at design

temperature

●Height

T (℃)

of nozzle neck

● Allowable

●Material

PAGE

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 129.3 ×1.00 = 49.78 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 12.5 +C = + 2.6 = 2.67mm S d E + 0.4 P 129.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2

PRo (9.81Hρ / 106 ) Ro = + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 12.5 9.81 × 6.852 × 1000 / 106 × 12.5 + + 2.6 165.3 × 1 + 0.4 × 0.65 165.3 × 1 + 0.4 × (9.81 × 6.852 × 1000 / 106 ) = 0.05 + 0.006 + 2.6 = 2.656mm

=

(2)

Minimum required thickness of shell (nozzle R.O) for par. UG-45 (b) (1), and UG-16 (b) (4),

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

40

OF

152

Es = 1.00

ts =

PRs 0.65 × 126.4 +C = + 2.6 = 3.26mm ＜ 2.5+2.6 = 5.1 mm S s Es + 0.4 P 125.3 × 1 + 0.4 × 0.65

ts = 5.1 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 2.31 + 2.6 = 4.62 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 4.62 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 7.5 ≥ t 5-1-15

OK

FOR ANNECTENT NOZZLE OF TANK AND

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-516MGr.485

Sd (MPa)

:

136

St (MPa)

:

174.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

4015

ρ(kg/m3)

:

1000

TOWER

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

Type No. (1) :

UW-12 ●Radiographic

examination

:

SPOT Per UW-11(b)

●Joint

efficiency (specified in UW-12)

E

:

0.85

DOC. NO.: 2011-83-1-86811-342-0

●Corrosion ●Outside

●Final

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

center line radius of nozzle

●Original

(1)

allowance (designated by customer)

radius of nozzle neck

●Nominal ●Inside

REV.: 0

center line radius of nozzle

PAGE

C

41

OF

152

(mm)

:

2.6

Ro (mm)

:

406.4

tstd (mm)

:

9.53

Rs

:

1402.6

Rf (mm)

:

398.4

R0 (mm)

:

∞(Infinity)

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 136 ×0.85 = 44.506 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PR 0.65 × 406.4 +C = + 2.6 = 2.3 + 2.6 = 4.9mm S d E − 0.6 P 136 × 0.85 − 0.6 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PR (9.81Hρ / 106 ) R + +C St E − 0.6 P St E − 0.6(9.81Hρ / 106 )

0.65 × 406.4 9.81 × 4.015 × 1000 / 106 × 406.4 + + 2.6 174.6 × 0.85 − 0.6 × 0.65 174.6 × 0.85 − 0.6 × (9.81 × 4.015 × 1000 / 106 ) = 1.79 + 0.11 + 2.6 = 4.5mm

=

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 1402.6 +C = + 2.6 = 6.73 + 2.6 = 9.33mm＞2.5 + 2.6 = 5.1 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 9.33 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 9.53 + 2.6 = 10.94 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 9.33 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 16.0 ≥ t OK

(5)

Maximum allowable fiber elongation without post weld heat treatment is based on the following formula: for single curvature

DOC. NO.: 2011-83-1-86811-342-0

r=

REV.: 0

PAGE

42

OF

152

50t ⎛ R f ⎞ 50 × 16 ⎛ 398.4 ⎞ ⎜⎜1 − ⎟⎟% = × ⎜1 − ⎟ % = 2.1% < 5% Rf ⎝ R0 ⎠ 398.4 ⎝ ∞ ⎠

None of the condition list in UCS-79 (d) (1-5) exists, so no heat treatment after cold forming need to apply. 5-2

DEAERATOR′S TOWER:

5-2-1

FOR NOZZLE

E

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

2.378

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

57.15

tstd (mm)

:

6.02

Rs

:

903.5

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

radius of nozzle neck

●Nominal ●Inside

(1)

allowance (designated by customer)

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

(mm)

DOC. NO.: 2011-83-1-86811-342-0

tmin 1 =

REV.: 0

PAGE

43

OF

152

PRo 0.65 × 57.15 +C = + 3.5 = 3.8mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 57.15 9.81 × 2.378 × 1000 / 106 × 57.15 + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 2.378 × 1000 / 106 ) = 0.24 + 0.01 + 3.5 = 3.75mm =

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 3.5 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 ×6.02 + 3.5 = 8.77 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.84 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t 5-2-2

FOR NOZZLE

OK

Y2

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

PAGE

:

136

H (m)

:

1.165

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

44.45

tstd (mm)

:

5.49

Rs

:

903.5

152

of welded joints of nozzle neck in TABLE

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

E

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

OF

Ss (MPa)

UW-12 ●Joint

44

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 44.45 +C = + 3.5 = 3.74mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 44.45 9.81 × 1.165 × 1000 / 106 × 44.45 + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 1.165 × 1000 / 106 ) = 0.18 + 0.004 + 3.5 = 3.684mm

=

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 3.5 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 5.49 + 3.5 = 8.31 mm t = (the smaller value of ts or tp) = 7.84 mm. > tmin1,tmin2

per UG-45(b)

DOC. NO.: 2011-83-1-86811-342-0

(4)

REV.: 0

PAGE

45

OF

152

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t 5-2-3

FOR NOZZLE

OK

J

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

1.445

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

44.45

tstd (mm)

:

5.49

Rs

:

903.5

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

radius of nozzle neck

●Nominal ●Inside

(1)

allowance (designated by customer)

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 44.45 +C = + 3.5 = 3.74mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

46

OF

152

Required minimum thickness including allowance

t min 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 44.45 9.81× 1.445 × 1000 / 106 × 44.45 + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81× 1.445 × 1000 / 106 ) = 0.18 + 0.004 + 3.5 = 3.684mm

=

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 3.5 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 5.49 + 3.5 = 8.31 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.84 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t 5-2-4

FOR NOZZLE

OK

F

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

1.205

ρ(kg/m3)

:

1000

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density

of test medium at test temperature (water)

DOC. NO.: 2011-83-1-86811-342-0

● Type

REV.: 0

PAGE

efficiency of nozzle neck

●Corrosion ●Outside

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

84.15

tstd (mm)

:

7.11

●Inside

Rs

:

903.5

E

allowance (designated by customer)

C

radius of nozzle neck

●Nominal

(1)

OF

152

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

47

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 84.15 +C = + 3.5 = 3.94mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 84.15 9.81 × 1.205 × 1000 / 106 × 84.15 + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 1.205 × 1000 / 106 ) = 0.35 + 0.007 + 3.5 = 3.857mm =

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 3.5 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 7.11 + 3.5 = 9.73 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.84 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t

OK

DOC. NO.: 2011-83-1-86811-342-0

5-2-5

FOR MANHOLE NOZZLE

REV.: 0

A2

PAGE

48

OF

152

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-516MGr.485

:

136

●Material ●

of nozzle neck

Allowable stress of nozzle neck material at design Sd (MPa)

temperature ●Allowable ●Height

to point under consideration

●Density ●Type

stress of nozzle neck material at test temperature

of test medium at test temperature (water)

174.6

H (m)

:

2166

ρ(kg/m3)

:

1000

of welded joints of nozzle neck in TABLE UW-12

●Radiographic ●Joint

St (MPa)

examination of nozzle neck

efficiency of nozzle neck (specified in UW-12)

●Negative

Deviation:

●Corrosion ●Outside

Type No. (1)

allowance (designated by customer)

radius of nozzle neck

SPOT Per UW-11(b) E

:

0.85

:

0.3

C2 (mm)

:

3.5

Ro

:

228.5

C1

(mm)

(mm)

●Inside

radius of nozzle corroded

R (mm)

:

220

●Inside

radius of shell corroded

Rs

:

1803.5

Rf (mm)

:

222.5

R0 (mm)

:

∞(Infinity)

●Final

center line radius of nozzle

●Original

center line radius of nozzle

(mm)

(1) Minimum required thickness of nozzle par. UG-45 (a) and UG-27 (c) (1)

0.385SE = 0.385×136×0.85 = 44.506 > P (a) under design condition Required minimum thickness including allowance

tmin 1 =

PR 0.65 × 220 +C = + 0.3 + 3.5 = 1.25 + 3.8 = 5.05mm S d E − 0.6 P 136 × 0.85 − 0.6 × 0.65

(b)under hydrostatic test condition Required minimum thickness including allowance

DOC. NO.: 2011-83-1-86811-342-0

tmin 2 =

REV.: 0

PAGE

49

OF

152

PR (9.81Hρ / 106 ) R + +C St E − 0.6 P St E − 0.6(9.81Hρ / 106 )

0.65 × 220 9.81 × 2.166 × 1000 / 106 × 220 = + + 0.3 + 3.5 174.6 × 0.85 − 0.6 × 0.65 174.6 × 0.85 − 0.6 × (9.81 × 2.166 × 1000 / 106 ) = 0.97 + 0.032 + 3.8 = 4.802mm (c) With supplemental loading by flange and cover ●

Weight of flange and cover

W = 193 kg

●

Bending moment due to supplemental loading Under operating condition

M1 = 193×9.81×0.162 = 307 N·m

Under cover opened condition

M2 = 193×9.81×0.462 =875 N·m

Per UG-27(c) and Appendix L, Use S = 136 × 1.5 = 204 MPa (see UG-23(c))

PR M + 21 +C 2SE + 0.4 P πR SE 0.65 × 220 307 = + + 0.3 + 3.5 2 2 × 204 × 0.85 + 0.4 × 0.65 π × 220 × 204 × 0.85 = 0.42 + 0.00002 + 3.8 ≈ 4.23mm

t3 =

t4 =

M2 875 +C = + 0.3 + 3.5 = 0.000034 + 3.8 ≈ 3.81mm 2 2 πR SE π × 220 × 204 × 0.85

(2) Provided thickness Nominal thickness (mm) 12.0 > tmin1, tmin2, t3, t4

OK

(3) Check extreme fiber elongation for paragraph UCS-79 Maximum allowable fiber elongation without post weld heat treatment is based on the following formula: for single curvature

r=

50t ⎛ R f ⎞ 50 × 12 ⎛ 222.5 ⎞ ⎜⎜1 − ⎟⎟% = × ⎜1 − ⎟% = 2.70% < 5% Rf ⎝ R0 ⎠ 222.5 ⎝ ∞ ⎠

None of the condition list in UCS-79 (d) (1-5) exists, so no heat treatment after cold forming need to apply. 5-2-6

FOR NOZZLE W1

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-105M

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

temperature ● Allowable

●

OF

152

Sd (MPa)

:

129.3

St (MPa)

:

165.3

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

1745

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

17.5

tstd (mm)

:

2.77

Rs

:

903.5

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

50

stress of nozzle neck material at test

temperature ●Material

PAGE

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 129.3 ×1.00 = 49.78 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 17.5 +C = + 2.6 = 3.59mm S d E + 0.4 P 129.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 17.5 9.81 × 1.745 × 1000 / 106 × 17.5 + + 3.5 165.3 × 1 + 0.4 × 0.65 165.3 × 1 + 0.4 × (9.81 × 1.745 × 1000 / 106 ) = 0.07 + 0.002 + 3.5 = 3.572mm =

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 2.6 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

51

OF

152

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 2.77 + 2.6 = 5.02 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 5.02 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 6.5 ≥ t 5-2-7

OK

FOR NOZZLE V1

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-105M

Sd (MPa)

:

129.3

St (MPa)

:

165.3

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

1752

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

25

tstd (mm)

:

2.87

Rs

:

903.5

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

radius of nozzle neck

●Nominal ●Inside

(1)

allowance (designated by customer)

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 129.3 ×1.00 = 49.78 > P (a) under design condition Appendix 1-1

(mm)

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

52

OF

152

Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 25 +C = + 3.5 = 3.63mm S d E + 0.4 P 129.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2

PRo (9.81Hρ / 106 ) Ro = + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 25 9.81 × 1.752 × 1000 / 106 × 25 + + 3.5 165.3 × 1 + 0.4 × 0.65 165.3 × 1 + 0.4 × (9.81 × 1.752 × 1000 / 106 ) = 0.1 + 0.003 + 3.5 = 3.603mm

=

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 2.6 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 2.87 + 2.6 = 5.12 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 5.12 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.0 ≥ t OK 5-2-8

FOR NOZZLE W3

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-105M

Sd (MPa)

:

129.3

St (MPa)

:

165.3

:

SA-516MGr.485

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material

of shell

●Allowable

stress of shell at design temperature

Ss (MPa)

:

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

53

OF

152

136 ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

H (m)

:

1740

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

12.5

tstd (mm)

:

2.31

Rs

:

903.5

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

(1)

allowance (designated by customer)

radius of nozzle neck

●Nominal ●Inside

E

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 129.3 ×1.00 = 49.78 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 12.5 +C = + 3.5 = 3.57mm S d E + 0.4 P 129.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 12.5 9.81 × 1.74 × 1000 / 106 × 12.5 + + 3.5 165.3 × 1 + 0.4 × 0.65 165.3 × 1 + 0.4 × (9.81 × 1.74 × 1000 / 106 ) = 0.05 + 0.002 + 3.5 = 3.552mm =

(2)

Minimum required thickness of shell (nozzle R.O) for par. UG-45 (b) (1), and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 2.6 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 2.31 + 2.6 = 4.62 mm t = (the smaller value of ts or tp)

per UG-45(b)

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

54

OF

152

= 4.62 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 7.5 ≥ t 5-2-9

FOR NOZZLE

OK

Y1

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-106Gr.B

Ss (MPa)

:

125.3

H (m)

:

1.178

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

57.15

tstd (mm)

:

6.02

Rs

:

170.17

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell (nozzle H)

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

radius of nozzle neck

●Nominal ●Inside

(1)

allowance (designated by customer)

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 57.15 +C = + 3.5 = 3.8mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

55

OF

152

Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 57.15 9.81 × 1.178 × 1000 / 106 × 57.15 + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 1.178 × 1000 / 106 ) = 0.24 + 0.01 + 3.5 = 3.75mm =

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 170.17 +C = + 3.5 = 4.39mm ＜ 2.5 + 3.5 =6.0 mm S s Es + 0.4 P 125.3 × 1 + 0.4 × 0.65

ts = 6.0 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 ×6.02 + 3.5 = 8.77 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 6.0 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t

OK

5-2-10

FOR NOZZLE

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-106Gr.B

Ss (MPa)

:

125.3

H (m)

:

1.205

ρ(kg/m3)

:

1000

●Material

I

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

ASME SEC.Ⅷ DIV.1 UG-45

of shell (nozzle H)

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density

of test medium at test temperature (water)

DOC. NO.: 2011-83-1-86811-342-0

● Type

REV.: 0

PAGE

efficiency of nozzle neck

●Corrosion ●Outside

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

84.15

tstd (mm)

:

7.11

●Inside

Rs

:

170.17

E

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

OF

152

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

56

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 84.15 +C = + 3.5 = 3.94mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 84.15 9.81 × 1.205 × 1000 / 106 × 84.15 + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 1.205 × 1000 / 106 ) = 0.35 + 0.01 + 3.5 = 3.86mm =

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 170.17 +C = + 3.5 = 4.39mm ＜2.5 + 3.5 = 6.0 mm S s Es + 0.4 P 125.3 × 1 + 0.4 × 0.65

ts = 6.0 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 ×7.11 + 3.5 = 9.72 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 6.0 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 10.97 Minimum thickness (mm) 10.97×0.875 = 9.6 ≥ t OK

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

OF

152

FOR NOZZLE

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516MGr.485

Ss (MPa)

:

136

H (m)

:

1.298

ρ(kg/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

177.8

tstd (mm)

:

9.53

Rs

:

903.5

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

ASME SEC.Ⅷ DIV.1 UG-45

of nozzle neck

● Allowable

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

thickness of the standard wall pipe(B36.10M)

radius of shell corroded

E C

(mm)

5-2-11-a: for large section (OD. = 355.6 mm) (1)

57

5-2-11

●Material

H

PAGE

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 177.8 +C = + 3.5 = 4.43mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

DOC. NO.: 2011-83-1-86811-342-0

tmin 2 =

REV.: 0

PAGE

58

OF

152

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 177.8 9.81 × 1.298 × 1000 / 106 × 177.8 = + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 1.298 × 1000 / 106 ) = 0.72 + 0.015 + 3.5 = 4.235mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 3.5 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 9.53 + 3.5 = 11.84 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.84 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t

OK

5-2-11-b: for conical reducer (α=11.7°) (1)

Minimum required thickness of conical reducer for par. UG-45 (a) (a) under design condition Required minimum thickness including allowance (for the large end):

tmin 1 =

PD 0.65 × 355.6 +C = + 3.5 = 4.45mm 2 cosα( S d E − 0.6 P) 2 × cos11.7(125.3 × 1 − 0.6 × 0.65)

Required minimum thickness including allowance (for the small end):

tmin 1 =

PD 0.65 × 219.1 +C = + 3.5 = 4.09mm 2 cosα( S d E − 0.6 P) 2 × cos11.7(125.3 × 1 − 0.6 × 0.65)

(b) under hydrostatic test condition Required minimum thickness including allowance (for the large end):

tmin 2 =

PD (9.81Hρ/ 106 ) D + +C 2 cosα( S d E − 0.6 P) 2 cosα[ S d E − 0.6(9.81Hρ/ 106 )]

DOC. NO.: 2011-83-1-86811-342-0

=

REV.: 0

PAGE

59

OF

152

0.65 × 355.6 （9.81 × 1.298 × 1000 / 106）× 355.6 + + 3.5 2 × cos11.7(160.6 × 1 − 0.6 × 0.65) 2 cos11.7[160.6 × 1 − 0.6 × (9.81 × 1.298 × 1000 / 106 )]

= 0.74 + 0.015 + 3.5 = 4.255 mm Required minimum thickness including allowance (for the small end):

tmin 2 =

=

PD (9.81Hρ/ 106 ) D + +C 2 cosα( S d E − 0.6 P) 2 cosα[ S d E − 0.6(9.81Hρ/ 106 )]

0.65 × 219.1 （9.81 × 1.23 × 1000 / 106）× 219.1 + + 3.5 2 × cos11.7(160.6 × 1 − 0.6 × 0.65) 2 cos11.7[160.6 × 1 − 0.6 × (9.81 × 1.23 × 1000 / 106 )]

= 0.46 + 0.01 + 3.5 = 3.97 mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 3.5 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 9.53 + 3.5 = 11.84 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.84 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t

OK

5-2-11-c: for small section (OD. = 219.1 mm THK. =12.7 mm ) (1)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2405 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 109.55 +C = + 3.5 = 4.07mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

DOC. NO.: 2011-83-1-86811-342-0

tmin 2 =

REV.: 0

PAGE

60

OF

152

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 109.55 9.81 × 1.23 × 1000 / 106 × 109.55 = + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 1.23 × 1000 / 106 ) = 0.45 + 0.009 + 3.5 = 3.959mm (2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PRs 0.65 × 903.5 +C = + 3.5 = 4.34 + 3.5 = 7.84mm＞2.5 + 3.5 = 6.0 mm S s Es − 0.6 P 136 × 1 − 0.6 × 0.65

ts = 7.84 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 7.11 + 3.5 = 9.73 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.84 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 12.7 Minimum thickness (mm) 12.7×0.875 = 11.11 ≥ t

OK

5-2-12

FOR NOZZLE D2

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516M Gr.485

Ss (MPa)

:

136

H (m)

:

0.420

ρ(k/m3)

:

1000

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of shell

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

radius of nozzle neck

●Nominal ●Inside

(1)

thickness of the standard wall pipe(B36.10M)

diameter of ellipsoidal head (corroded)

OF

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

406.4

tstd (mm)

:

7.11

D

:

1807

E

allowance (designated by customer)

61

C

(mm)

152

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2045 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 84.15 +C = + 3.5 = 3.94mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 84.15 9.81 × 0.42 × 1000 / 106 × 84.15 + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 0.42 × 1000 / 106 ) = 0.35 + 0.003 + 3.5 = 3.853mm =

(2)

Minimum required thickness of head for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PD 0.65 × 1807 +C = + 3.5 = 4.33 + 3.5 = 7.83mm＞2.5 + 3.5 = 6.0 mm 2S s Es − 0.2 P 2 × 136 × 1 − 0.2 × 0.65

ts = 7.83 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 7.11 + 3.5 = 9.73 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.83 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 10.97 Minimum thickness (mm) 10.97×0.875 = 9.6 ≥ t OK

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

5-2-13 FOR ANNECTENT NOZZLE OF TANK AND

PAGE

62

OF

152

ASME SEC.Ⅷ DIV.1 UG-45

TOWER ●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-516M Gr.485

●Material

of nozzle neck

● Allowable

Sd (MPa)

temperature ● Allowable

●

: 174.6

stress of nozzle neck material at test St (MPa)

temperature ●Material

136

stress of nozzle neck material at design

of shell

: :

SA-516M Gr.485

Ss (MPa)

:

136

H (m)

:

3.542

ρ(k/m3)

:

1000

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

Type No. (1) :

UW-12 ●Radiographic

examination

:

SPOT Per UW-11(b)

●Joint

efficiency (specified in UW-12)

●Corrosion ●Outside

radius of nozzle neck

●Nominal ●Inside ●Final

thickness of the standard wall pipe(B36.10M)

diameter of ellipsoidal head (corroded)

center line radius of nozzle

●Original

(1)

allowance (designated by customer)

center line radius of nozzle

E

:

0.85

(mm)

:

3.5

Ro (mm)

:

406.4

tstd (mm)

:

9.53

D

:

1807

Rf (mm)

:

398.4

R0 (mm)

:

∞(Infinity)

C

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 136 ×0.85 = 44.506 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

(mm)

DOC. NO.: 2011-83-1-86811-342-0

tmin 1 =

REV.: 0

PAGE

63

OF

152

PR 0.65 × 406.4 +C = + 3.5 = 2.3 + 3.5 = 5.8mm S d E − 0.6 P 136 × 0.85 − 0.6 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PR (9.81Hρ / 106 ) R + +C St E − 0.6 P St E − 0.6(9.81Hρ / 106 )

0.65 × 406.4 9.81 × 3.542 × 1000 / 106 × 406.4 + + 3.5 174.6 × 0.85 − 0.6 × 0.65 174.6 × 0.85 − 0.6 × (9.81 × 3.542 × 1000 / 106 ) = 1.79 + 0.1 + 3.5 = 5.39mm

=

(2)

Minimum required thickness of shell for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

0.65 × 1807 PD + 3.5 = 4.33 + 3.5 = 7.83mm＞2.5 + 3.5 = 6.0 mm +C = 2S s Es − 0.2 P 2 × 136 × 1 − 0.2 × 0.65

ts = 7.83 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 9.53 + 2.6 = 10.94 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.83 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 16.0 ≥ t OK

(5)

Maximum allowable fiber elongation without post weld heat treatment is based on the following formula: for single curvature

r=

50t ⎛ R f ⎞ 50 × 16 ⎛ 398.4 ⎞ ⎟⎟% = ⎜⎜1 − × ⎜1 − ⎟ % = 2.1% < 5% Rf ⎝ R0 ⎠ 398.4 ⎝ ∞ ⎠

None of the condition list in UCS-79 (d) (1-5) exists, so no heat treatment after cold forming need to apply. 5-2-14

FOR NOZZLE OF STEAM SEPARATOR

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

temperature ● Allowable

OF

152

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-516M Gr.485

Ss (MPa)

:

136

H (m)

:

0.321

ρ(k/m3)

:

1000

:

Seamless

:

1.0

(mm)

:

3.5

Ro (mm)

:

177.8

tstd (mm)

:

9.53

D

:

1807

of shell

Allowable stress of shell (or head) at design

●

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

●Inside

allowance (designated by customer)

radius of nozzle neck

●Nominal

(1)

64

stress of nozzle neck material at test

temperature ●Material

PAGE

thickness of the standard wall pipe(B36.10M)

diameter of ellipsoidal head (corroded)

E C

(mm)

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2045 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 177.8 +C = + 3.5 = 4.43mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + +C St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 177.8 9.81 × 0.321 × 1000 / 106 × 177.8 + + 3.5 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 0.321 × 1000 / 106 ) = 0.72 + 0.004 + 3.5 = 4.224mm

=

(2)

Minimum required thickness of head for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00

ts =

PD 0.65 × 1807 +C = + 3.5 = 4.33 + 3.5 = 7.83mm＞2.5 + 3.5 = 6.0 mm 2S s Es − 0.2 P 2 × 136 × 1 − 0.2 × 0.65

DOC. NO.: 2011-83-1-86811-342-0

REV.: 0

PAGE

65

OF

152

ts = 7.83 mm (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 9.53 + 3.5 = 11.8 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 7.83 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t

OK

5-2-15

FOR NOZZLE G

ASME SEC.Ⅷ DIV.1 UG-45

●Design

pressure

P (MPa)

:

0.65

●Design

temperature

T (℃)

:

300

:

SA-106Gr.B

Sd (MPa)

:

125.3

St (MPa)

:

160.6

:

SA-105M

Ss (MPa)

:

129.3

H (m)

:

0.185

ρ(k/m3)

:

1000

:

Seamless

:

1.0

:

3.5

Ro (mm)

:

44.45

tstd (mm)

:

5.49

D

:

535

●Material

of nozzle neck

● Allowable

stress of nozzle neck material at design

temperature ● Allowable

stress of nozzle neck material at test

temperature ●Material ●

of blind flange

Allowable stress of shell (or head) at design

temperature ●Height

to point under consideration

●Density ● Type

of test medium at test temperature (water)

of welded joints of nozzle neck in TABLE

UW-12 ●Joint

efficiency of nozzle neck

●Corrosion ●Outside

radius of nozzle neck

●Nominal ●Long

allowance (designated by customer)

thickness of the standard wall pipe(B36.10M)

span of cover measured perpendicular to short

E C2

(mm)

(mm)

span(corroded) ●

Factor

C

:

0.3

●

Diameter, measured as indicated in Fig. UG-34

d ( mm )

:

425.3

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●

Gasket moment arm,as shown in table 2-5-2

hG (mm)

:

25.5

●

Effective gasket sealing width

b (mm)

:

12.1

152

Minimum required thickness of nozzle neck for par. UG-45 (a) 0.385SE = 0.385× 125.3 ×1.00 = 48.2045 > P (a) under design condition Appendix 1-1 Required minimum thickness including allowance

tmin 1 =

PRo 0.65 × 44.45 + C2 = + 3.5 = 3.74mm S d E + 0.4 P 125.3 × 1 + 0.4 × 0.65

(b) under hydrostatic test condition Required minimum thickness including allowance

tmin 2 =

PRo (9.81Hρ / 106 ) Ro + + C2 St E + 0.4 P St E + 0.4(9.81Hρ / 106 )

0.65 × 44.45 9.81 × 0.185 × 1000 / 106 × 44.45 + 3.5 + 160.6 × 1 + 0.4 × 0.65 160.6 × 1 + 0.4 × (9.81 × 0.185 × 1000 / 106 ) = 0.18 + 0.0006 + 3.5 = 3.69mm

=

(2)

Minimum required thickness of covers for par. UG-45 (b) (1),and UG-16 (b) (4), Es = 1.00 (a) under operating condition UG-34(C)-(3) Appendix 2-5 Required minimum thickness including allowance W:total bolt load, given for circular heads for Formulas (4) 2-5 (e) Wm1 = 0.785G2P + (2b×3.14GmP) = 0.785×425.32×0.65 + (2×12.1×3.14×425.3×1.25×0.65) = 92294.1 + 26258.1 = 118552.2 N

t sa = d CP / SE + 1.9WhG / SEd 3 + C2

= 425.3 × 0.3 × 0.65 / 129.3 × 1.0 + 1.9 × 118552.2 × 25.5 / 129.3 × 1 × 425.33 + 3.5 = 19.5 + 3.5 = 23.0 mm＞ 2.5 + 3.5 = 6.0 mm tsa = 23.0 mm (b) under gasket seating condition

UG-34(C)-(3) Appendix 2-5

Required minimum thickness including allowance W:total bolt load, given for circular heads for Formulas (5) 2-5 (e) W=

( Am + Ab ) S a 2

Am: Total required bolt aream, Am = max.(Am1, Am2)

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Am1 = Wm1/Sb = 118552.2/287 = 413.1 mm2 Am2 = Wm2/Sa Wm2 = 3.14bGγ= 3.14×12.1×425.3×2.8 = 45244.8 N Am2 = Wm2/Sa = 45244.8/287 = 157.7 mm2 Am = max.(Am1, Am2) = 413.1 mm2 Ab = 0.785 ndB2 =0.785×12×272 = 6867.18 mm2 W=

( Am + Ab ) S a (413.1 + 6867.18) × 287 = 2 2

= 1044720.18 N

tsb = d CP / SE + 1.9WhG / SEd 3 + C2

= 425.3 × 0.3 × 0 / 165.3 × 1.0 + 1.9 × 1044720.18 × 25.5 / 165.3 × 1 × 425.33 + 3.5 = 26.9 + 3.5 = 30.4 mm＞ 2.5 + 3.5 = 6.0 mm tsb = 30.4 mm ts: the larger of (tsa, tsb) = 30.4 mm2 (3)

Minimum thickness of standard wall pipe including allowance for par. UG-45 (b) (4)

tp = 0.875tstd + C = 0.875 × 5.49 + 3.5 = 8.31 mm t = (the smaller value of ts or tp)

per UG-45(b)

= 8.31 mm. > tmin1,tmin2 (4)

Provided thickness Nominal thickness (mm) 11.13 Minimum thickness (mm) 11.13×0.875 = 9.74 ≥ t

OK

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6. Max. Allowable working pressure (corroded) The maximum allowable working pressure may be assumed to be the same as the design pressure when calculations are not made to determine the maximum allowable working pressure. (ASME SEC.Ⅷ DIV.1 UG-99 notes: 34) So we take the maximum allowable working pressure is 0.65 MPa at 300 ℃

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HYDROSTATIC TEST PRESSURE AND TEMPERATURE ASME SEC. Ⅷ

DIV.1 UG-99 AND

PED/97/23/EC ANNEX Ⅰ ●Maximum

allowable working pressure (Hot & Corroded) *

●Hydrostatic ●Design ●Test

temperature

●Material

:

0.65 at 300 ℃

(MPa)

:

1.04

(℃)

:

300

(℃)

:

5～40

(℃)

:

-29

:

See table 7.1

test pressure

temperature

●Minimum

(MPa)

design metal temperature

of parts of the vessel

●Allowable

stress of vessel wall at design temperature

Sd (MPa)

:

See table 7.1

●Allowable

stress of vessel wall at test temperature

St (MPa)

:

See table 7.1

*: The maximum allowable working pressure may be assumed to be the same as the design pressure. (specified in UG-99 note34) (1)

Minimum required test pressure per PED/97/23/EC annex Ⅰ Table 7.1 Hydrostatic Test Pressure per PED/97/23/EC annex Ⅰ Shell

Head

Nozzle B

Ps MAWP (MPa)

Nozzle E

Flange

0.2

Material

SA-516MGr.485

SA-516MGr.485

SA-105M

SA-516MGr.485

SA-106Gr.B

SA-105M

St(MPa)

174.6

174.6

165.3

174.6

160.6

165.3

Sd(MPa)

136

136

129.3

136

125.3

129.3

1.2839

1.2839

1.2785

1.2839

1.2818

1.2785

ratio of (St/Sd)

1.2785

The lowest ratio of (St/Sd)

1.04

PT1(MPa): 1.25×min(St/Sd)×Ps

PT2(MPa): 1.43×Ps

0.93

PT(MPa): Max(PT1 , PT2)

1.04

PHT(MPa): Min. Req.

1.04

Hydrostatic test

(2)

Nozzle A.C.D.F.G.H1-4.I1-2

Provided test pressure

per UG-99 (h)

Hydrostatic test pressure (MPa) is 1.04 at 5~40℃

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REINFORCEMENT FOR OPENINGS 8-1 DEAERATOR′S TANK:

8-1-1

For manhole A1 (DN500) per UG-37

●Internal ●Design

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-516MGr.485

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 136

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

D

: 2805.2

●Inside

diameter of ellipsoidal head (corroded)

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

(mm)

t (mm)

: 11.32

Rno(mm)

: 254

Rn (mm)

: 244.6

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 9.6

●Finished

diameter of opening corroded

d (mm)

: 489.2

tnc (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

●Material

of the reinforcing pad

●Allowable

●Outside

factor

stress of reinforcing pad at design temperature

diameter of reinforcing pad

●Nominal

thickness of reinforcing pad

8-1-1-1 Size of opening

: SA-516MGr.485 Sp (MPa)

: 136

Dp (mm)

: 840

te

(mm)

12

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Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 489.2 mm, so supplemental rules of 1-7 are not applied. 8-1-1-2 Wall thicknesses Required ellipsoidal head

tr =

Required thickness of a seamless shell tr (E=1.0)

PD 0.65 × 2805.2 = 6.71mm = 2 S d E − 0.2 P 2 × 136 × 1.0 − 0.2 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

PRno 0.65 × 254 = 1.22mm = S n E1 + 0.4 P 136 × 1 + 0.4 × 0.65

8-1-1-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1= Sn/SV= 136/136 = 1.0 Strength reduction factor for nozzle fr2 fr2= Sn/SV = 136/136 = 1.0 Strength reduction factor for all parts fr3 fr3= (less of Sn or Sp)/SV = 136/136 = 1.0 Strength reduction factor for reinforcing pad fr4 fr4= Sp/SV = 136/136 = 1.0 8-1-1-4 Size of weld required [UW-16(d),Fig.UW-16.1 Sketch (q)] 8-1-1-4(a) Inner (reinforcing pad) fillet weld size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 13.92 , 12.0 ) = 12.0 mm tc ( minimum ) = lesser of 1/4 in. or 0.7 tmin , 6.0 or 0.7×12.0 = 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 × 9.0 = 6.3 mm 8-1-1-4(b) Outer (reinforcing pad) fillet weld:

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Throat = 1/2 tmin= 0.5 × 12.0 = 6.0 mm ( minimum throat required ) Throat = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm (actual) 8-1-1-4(c) Upper groove weld: tw = 0.7 tmin = 0.7 × 12.0 = 8.4 mm ( required ) tw = 12mm (actual) The weld size used is satisfactory. 8-1-1-4(d) Check for limits of reinforcement: 8-1-1-4(d) (1) Limit parallel to the vessel wall: larger of d = 489.2 mm

or Rn + tn + t = 244.6 + 9.6 + 11.32 = 265.52 mm

Use 489.2 mm 8-1-1-4(d) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×11.32 =28.3 mm or 2.5tn+te = 2.5×9.4 + 12 = 35.5 mm

Use 28.3 mm 8-1-1-5 Area of reinforcement required [UG-37] 8-1-1-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 489.2 × 6.71 × 1.0 + 2 × 9.4 × 6.71 × 1.0 × (1 − 1.0) = 3282.6 + 0 = 3282.6 mm2 8-1-1-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 489.2×(1.0×11.32-1×6.71)-2×9.4×(1.0×11.32-1.0×6.71)×(1-1.0) = 2255.2 – 0 = 2255.2 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(11.32 + 9.4) × (1.0×11.32-1×6.71)-2×9.4× (1.0×11.32-1.0×6.71)×(1-1.0) = 191 – 0 = 191 mm2 A1= the larger of (A11,A12)= 2255.2 mm2 8-1-1-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (9.4 − 1.22 ) × 1.0 × 11.32 = 462.9mm 2

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A22 = 2(tn − trn )(2.5tn + te ) f r 2 = 2 × (9.4 − 1.22) × (2.5 × 9.4 + 12) × 1.0 = 580.7mm2 A2=the smaller of (A21, A22) = 462.9 mm2 8-1-1-5(d) Area available in welds A4 8-1-1-5(d)(1) Area available in outward weld A41 A41= (leg)^2 × fr3 = 9.0 × 9.0 × 1.0 = 81 Sq. mm A42= (leg)^2 × fr4 = 9.0 × 9.0 × 1.0 = 81 Sq. mm 8-1-1-5(e)

Area provided by:

A1 +A2 +A41 +A42 = 2255.2 + 462.9 + 81 +81 = 2880.1 Sq. mm 8-1-1-5(f) Area available in reinforcing pad: A5 = (Dp-d-2tn) te fr4 =(840-489.2-2×9.4)×12×1.0 = 3984 Sq. mm 8-1-1-5(g) Total area available A1 +A2 +A41 + A42 + A5 = 2918.1 + 3984 = 6864.1 Sq. mm This is greater than the required reinforcing area of 3282.6 sq. mm; therefore, the opening is adequately reinforced. 8-1-1-6 Check the welds per UW-16 and UW-16.1 (q) 8-1-1-6-1 Check Load to be carried by welds [Fig.UG-41.1 Sketch (a)] 8-1-1-6-1 (a) Per UG-41 (b) (1) W1-1 = (A2 + A5 + A41 + A42) × Sv = ( 462.9 + 3984 + 81 + 81 ) × 136 = 626810.4 N W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = ( 462.9+ 0 + 81 + 0 + 2 × 9.4 ×11.32 × 1.0 )× 136 = 102913.4 N W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) Sv = ( 462.9+ 0 + 3984 + 81 + 81+ 0 + 2 × 9.4 ×11.32 × 1.0 )× 136 = 655753.3 N 8-1-1-6-1 (b) Per UG-41 (b) (2) W= [A - A1 + 2tn fr1 (E1t – F tr )]Sv = [3282.6 –2255.2 + 2× 9.4 × 1.0× (1.0 × 11.32 - 1.00× 6.71)] × 136 = 151513.2 N Since W is smaller than W1-1 and W3-3, W may be used in place of W1-1 and W3-3 for comparing weld capacity to weld load.

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8-1-1-6-2 Unit Stresses per UG-45(c) and UW-15 (c) 8-1-1-6-2 (a) Fillet weld shear = 0.49×136 = 66.64 Mpa 8-1-1-6-2 (b) Groove weld tension = 0.74×136 = 100.64 Mpa 8-1-1-6-2 (c) Groove weld shear = 0.6×136 = 81.6 Mpa 8-1-1-6-2 (d) Nozzle wall shear = 0.7×136 = 95.2 Mpa 8-1-1-6-3 Strength of connection elements 8-1-1-6-3 (a) Upper fillet or cover weld = π/2 × nozzle O.D. × weld leg × 66.64 = 1.57 × 508 × 9.0 × 66.64 = 478344.6 N 8-1-1-6-3 (b) Nozzle wall shear = π/2 × mean nozzle diameter × tn × 95.2 = 1.57 × 496 × 9.4 × 95.2 = 696860.9 N 8-1-1-6-3 (c) Lower groove weld tension = π/2 × nozzle O.D. × weld leg × 100.64 = 1.57 × 508 × 9.0 × 100.64 = 722397.9 N 8-1-1-6-3 (d) Outer (reinforcing element) fillet weld = π/2 × reinforcing pad O.D. × weld leg × 66.64 = 1.57 × 840 × 9.0 ×66.64 = 790963.5 N 8-1-1-6-3 (e) Upper groove weld tension = π/2 × nozzle O.D. × weld leg × 100.64 = 1.57 × 508 × 9.0 × 100.64 = 722397.9 N 8-1-1-6-4 Check Strength paths Path 1-1 = 790963.5 + 696860.9 = 1487824.4 N ＞W1-1 = 626810.4 N

OK

Path 2-2 = 478344.6 + 722397.9 + 722397.9 = 1923140.4 N＞W2-2 = 102913.4 N Path 3-3 = 790963.5 + 722397.9 = 1513361.4 N＞W3-3 = 655753.3 N

OK

OK

Also paths are stronger than the required strength of W of 151513.2 N [see UG-41 (b) (2)] thus, the Weld Strength Paths Are Adequate. 8-1-2

For steam connect nozzle B and water connect nozzle Q (DN200) per UG-37

●Internal

design pressure

P (MPa)

: 0.65

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PAGE

(℃)

temperature

●Material

of the vessel wall

●Allowable ●Material

stress of the vessel wall at design temperature

75

OF

: 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

R (mm)

: 1402.6

t (mm)

: 13.4

Rno(mm)

: 109.55

Rn (mm)

: 99.45

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 10.1

●Finished

diameter of opening corroded

d (mm)

: 198.9

Weld leg (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

152

8-1-2-1 Size of opening Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 198.9 mm, so supplemental rules of 1-7 are not applied. 8-1-2-2 Wall thicknesses Required Shell

tr =

Required thickness of a seamless shell tr (E=1.0)

PR 0.65 × 1402.6 = = 6.73mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

t rn =

PRno 0.65 × 109.55 = = 0.57mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

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8-1-2-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV= 125.3/136= 0.9214 Strength reduction factor for nozzle fr2 fr2=Sn/SV = 125.3/136 = 0.9214 8-1-2-4 Size of weld required [UW-16(c),Fig.UW-16.1 Sketch (e)] 8-1-2-4(a) throat size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 16.0, 12.7 ) = 12.7 mm tc (mininum) = lesser of 1/4 in. or 0.7 tmin, 6.0 or 0.7×12.7 = 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm Cover weld satisfactory 8-1-2-4(b) Check for limits of reinforcement: 8-1-2-4(b) (1) Limit parallel to the vessel wall: larger of d = 198.9 mm or Rn + tn + t = 99.45 + 10.1 + 13.4 = 122.95 mm Use 98.9 mm 8-1-2-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×13.4 = 33.5 mm or 2.5tn+te = 2.5×10.1 + 0 = 25.25 mm

Use 25.25 mm 8-1-2-5 Area of reinforcement required [UG-37] 8-1-2-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 198.9 × 6.73 × 1.0 + 2 × 10.1 × 6.73 × 1.0 × (1 − 0.9213) = 1338.6 + 10.7 = 1349.3 mm2 8-1-2-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 )

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= 198.9×(1.0×13.4-1×6.73)-2×10.1×(1.0×13.4-1.0×6.73)×(1-0.9213) = 1326.6 – 10.6 = 1316 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(13.4 + 10.1) × (1.0×13.4-1×6.73)-2×10.1× (1.0×13.4-1.0×6.73)×(1-0.9213) = 313.5 – 10.6 = 302.9 mm2 A1 = the larger of (A11,A12) = 1316 mm2 8-1-2-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (10.1 − 0.57 ) × 0.9213 × 13.4 = 588.3mm2 A22 = 5(tn − trn ) f r 2tn = 5 × (10.1 − 0.57 ) × 0.9213 × 10.1 = 443.4mm2 A2=the smaller of (A21, A22) = 443.4 mm2 8-1-2-5(d) Area available in welds A4 8-1-2-5(d)(1) Area available in outward weld A41 8-1-2-5(e)

A41= (leg)^2 × fr2 = 9.0 × 9.0 × 0.9213 = 74.6 Sq. mm Total area available

A1 +A2 +A41 = 1316 + 443.4 + 74.6 = 1834 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-1-2-6

Strength calculations for attachment welds are not required for this detail which conforms with Fig. UW-16.1 sketch (e) [see UW-15(b)]

8-1-3

For recycling nozzle C1-2

●Internal ●Design

and reboiling nozzle M (DN80)

design pressure

temperature

●Material

P (MPa) (℃)

of the vessel wall

●Allowable ●Material

per UG-37

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

R (mm)

: 1402.6

t (mm)

: 13.4

●Inside

radius of shell corroded

●Analysis

thickness of the vessel wall corroded

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●Inside

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radius of the nozzle

radius of the nozzle corroded

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OF

Rno(mm)

: 44.45

Rn (mm)

: 35.92

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 8.53

●Finished

diameter of opening corroded

d (mm)

: 71.84

●Leg

length of outward nozzle fillet weld

Weld leg (mm)

: 12.0

●Leg

length of inward nozzle fillet weld

Weld leg (mm)

: 12.0

θ (deg)

: 0.0

F

: 1.0

●Angle

of plane with longitudinal axis

●Correction

factor

152

8-1-3-1 Size of opening Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 71.84 mm, so supplemental rules of 1-7 are not applied. 8-1-3-2 Wall thicknesses Required Shell

Required thickness of a seamless shell tr (E=1.0)

tr =

PR 0.65 × 1402.6 = = 6.73mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

PRno 0.65 × 44.45 = = 0.24mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-1-3-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV=125.3/136 = 0.9213 Strength reduction factor for nozzle fr2 fr2=Sn/SV =125.3/136 = 0.9213 8-1-3-4 Size of weld required [UW-16(c),Fig.UW-16.1 Sketch (i)] 8-1-3-4(a) throat size of weld required UW-16(b)

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t1 or t2 = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 16.0 , 11.13 ) = 11.13 mm t1 or t2 ≥ min.( 6 , 0.7×11.13 ) = 6.0 mm therefore throat must be at least 6.0 mm Weld 41, actual weld leg = 12.0 mm Weld 43, actual weld leg = 12.0 mm t1 or t2 = 0.7 × weld size = 0.7 ×12.0 = 8.4 mm (actual)

1 tmin = 13.9125 mm 4 1 t1 + t2 = 8.4 + 8.4 = 16.8 ＞ 1 tmin = 13.9125 mm 4

check t1 + t2 ≥ 1

Cover weld satisfactory 8-1-3-4(b) Check for limits of reinforcement: 8-1-3-4(b) (1) Limit parallel to the vessel wall: larger of

d= 71.84 mm

or

Rn + tn + t = 35.92 + 8.53 + 13.4 = 57.85 mm

Use 71.84 mm 8-1-3-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×13.4 =33.5 mm or 2.5tn+te = 2.5×8.53 + 0 = 21.325 mm

Use 21.325 mm 8-1-3-5 Area of reinforcement required [UG-37] 8-1-3-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 71.84 × 6.73 × 1.0 + 2 × 8.53 × 6.73 × 1.0 × (1 − 0.9213) = 483.5 + 9.1 = 492.6 mm2 8-1-3-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 71.84×(1×13.4-1×6.73)-2×8.53×(1×13.4-1.0×6.73)×(1-0.9213) = 479.2 – 9.0 = 470.2 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 )

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=2(13.4 + 8.53) × (1×13.4-1×6.73)-2×8.53× (1×13.4-1.0×6.73) × (1-0.9213) = 292.5 – 9.0 = 283.5 mm2 A1=the larger of (A11,A12)= 470.2 mm2 8-1-3-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (8.53 − 0.24) × 0.9213 × 13.4 = 511.7mm 2 A22 = 5(tn − trn ) f r 2tn = 5 × (8.53 − 0.24) × 0.9213 × 8.53 = 325.7mm2 A2= the smaller of (A21, A22) = 325.7 mm2 8-1-3-5(d) Area available in nozzle projecting inward A3

Inner "h" limit:

min[h, 2.5t , 2.5tn]= [345, 33.5 , 21.325] = 21.325 mm

A31 = 5tt j f r 2 = 5 × 13.4 × 8.53 × 0.9213 = 526.5mm 2

A32 = 5t j t j f r 2 = 5 × 8.53 × 8.53 × 0.9213 = 335.1mm 2 A33 = 5ht j f r 2 = 5 × 21.325 × 8.53 × 0.9213 = 837.9mm 2 A3= the smaller of (A31, A32, A33 ) = 335.1 mm2 8-1-3-5(e) Area available in fillet welds A4 8-1-3-5(e)(1) Area available in outward fillet weld A41 A41= (leg)^2 × fr2 = 12.0 × 12.0 × 0.9213 = 132.6 Sq. mm 8-1-3-5(e)(2) Area available in inward fillet weld A43 A43= (leg)^2 × fr2 = 12.0 × 12.0 × 0.9213 = 132.6 Sq. mm 8-1-3-5(f) Total area available A1 +A2 +A3 +A41 +A43 = 470.2 + 325.7 + 335.1 + 132.6 + 132.6 = 1396.2 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-1-3-6 Check the welds per UW-16 and UW-16.1 (i) 8-1-3-6-1 Check Load to be carried by welds [Fig.UG-41.1 Sketch (a)] 8-1-3-6-1 (a) Per UG-41 (b) (1) W1-1 = (A2 + A5 + A41 + A42) × Sv = ( 325.7 + 0 + 132.6 + 0) × 136 = 62328.8 N W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = ( 325.7+ 335.1 + 132.6 + 132.6 +2 × 8.53 × 13.4 × 0.9213)× 136 = 154579.3 N 8-1-3-6-1 (b) Per UG-41 (b) (2)

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W= [A - A1 + 2tn fr1 (E1t - Ftr)]Sv = [ 492.6 – 470.2 + 2× 8.53× 0.9213× (1.0 × 13.4 - 1.0 × 6.73)] *136 = 17303.9 N Since W is smaller than W1-1 and W2-2, W may be used in place of W1-1 and W2-2 for comparing weld capacity to weld load. 8-1-3-6-2 Unit Stresses per UG-45(c) and UW-15 (c) 8-1-3-6-2 (a) Fillet weld shear = 0.49×125.3 = 61.4 Mpa 8-1-3-6-2 (b) Nozzle wall shear = 0.7×125.3 = 87.71 Mpa 8-1-3-6-3 Strength of connection elements 8-1-3-6-3 (a) Fillet weld shear = π/2 × nozzle O.D. × weld leg × 61.4 = 1.57 × 88.9 × 12.0 ×61.4 = 102837.4 N 8-1-6-3 (b) Nozzle wall shear = π/2 × mean nozzle diameter × tn × 87.71 = 1.57×77.77×8.53 × 87.71 = 91350.3 N 8-1-3-6-4 Check Strength paths Path 1-1 = 102837.4 + 91350.3 = 194187.7 N Path 2-2 = 102837.4 + 102837.4 = 205674.8 N All paths are stronger than the required strength of W of 17303.9 N [see UG-41 (b) (2)] Weld Strength Paths Are Adequate. 8-1-4

For safety valve nozzle D1 and outfall nozzle N (DN150) per UG-37

●Internal ●Design

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

R (mm)

: 1402.6

●Inside

radius of shell corroded

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●Outside

●Inside

REV.: 0

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

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t (mm)

: 13.4

Rno(mm)

: 84.15

Rn (mm)

: 75.78

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 8.37

●Finished

diameter of opening corroded

d (mm)

: 151.56

Weld leg (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

152

8-1-4-1 Size of opening Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 151.56 mm, so supplemental rules of 1-7 are not applied. 8-1-4-2 Wall thicknesses Required Shell

tr =

Required thickness of a seamless shell tr (E=1.0)

PR 0.65 × 1402.6 = = 6.73mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

t rn =

PRno 0.65 × 84.15 = = 0.44mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-1-4-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV= 125.3/136= 0.9214 Strength reduction factor for nozzle fr2 fr2=Sn/SV = 125.3/136 = 0.9214 8-1-4-4 Size of weld required [UW-16(c),Fig.UW-16.1 Sketch (e)] 8-1-4-4(a) throat size of weld required UW-16(b)

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tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 16.0, 10.97 ) = 10.97 mm tc (mininum) = lesser of 1/4 in. or 0.7 tmin, 6.0 or 0.7× 10.97 = 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm Cover weld satisfactory 8-1-4-4(b) Check for limits of reinforcement: 8-1-4-4(b) (1) Limit parallel to the vessel wall: larger of d = 151.56 mm or Rn + tn + t = 75.78 + 8.37 + 13.4 = 97.55 mm Use 151.56 mm 8-1-4-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×13.4 = 33.5 mm or 2.5tn+te = 2.5×8.37 + 0 = 20.925 mm

Use 20.925 mm 8-1-4-5 Area of reinforcement required [UG-37] 8-1-4-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 151.56 × 6.73 × 1.0 + 2 × 8.37 × 6.73 × 1.0 × (1 − 0.9213) = 1020 + 8.9 = 1028.9 mm2 8-1-4-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 151.56×(1.0×13.4-1×6.73)-2×8.37×(1.0×13.4-1.0×6.73)×(1-0.9213) = 1011 – 8.8 = 1002.2 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(13.4 + 8.37) × (1.0×13.4-1×6.73)-2×8.37× (1.0×13.4-1.0×6.73)×(1-0.9213) = 290.4 – 8.8 = 281.6 mm2 A1 = the larger of (A11,A12) = 1002.2 mm2 8-1-4-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (8.37 − 0.44) × 0.9213 × 13.4 = 489.5mm2

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A22 = 5(tn − trn ) f r 2tn = 5 × (8.37 − 0.44) × 0.9213 × 8.37 = 305.7mm 2 A2=the smaller of (A21, A22) = 305.7 mm2 8-1-4-5(d) Area available in welds A4 8-1-4-5(d)(1) Area available in outward weld A41 8-1-4-5(e)

A41= (leg)^2 × fr2 = 9.0 × 9.0 × 0.9213 = 74.6 Sq. mm Total area available

A1 +A2 +A41 = 1002.2 + 305.7 + 74.6 = 1382.5 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-1-4-6

Strength calculations for attachment welds are not required for this detail which conforms with Fig. UW-16.1 sketch (e) [see UW-15(b)]

8-1-5

For steam inlet nozzle K (DN200)

●Internal ●Design

per UG-37

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

R (mm)

: 1402.6

t (mm)

: 13.4

Rno(mm)

: 109.55

Rn (mm)

: 99.45

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 10.1

●Finished

diameter of opening corroded

d (mm)

: 198.9

●Leg

length of outward nozzle fillet weld

Weld leg (mm)

: 12.0

●Leg

length of inward nozzle fillet weld

Weld leg (mm)

: 12.0

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●Correction

factor

PAGE

85

θ (deg)

: 0.0

F

: 1.0

OF

152

8-1-5-1 Size of opening Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 198.9 mm, so supplemental rules of 1-7 are not applied. 8-1-5-2 Wall thicknesses Required Required thickness of a seamless shell tr (E=1.0)

Shell

tr =

PR 0.65 × 1402.6 = = 6.73mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

t rn =

PRno 0.65 × 109.55 = = 0.57mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-1-5-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV=125.3/136 = 0.9213 Strength reduction factor for nozzle fr2 fr2=Sn/SV =125.3/136 = 0.9213 8-1-5-4 Size of weld required [UW-16(c),Fig.UW-16.1 Sketch (i)] 8-1-5-4(a) throat size of weld required UW-16(b) t1 or t2 = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 16.0 , 12.7 ) = 12.7 mm t1 or t2 ≥ min.( 6 , 0.7×12.7 ) = 6.0 mm therefore throat must be at least 6.0 mm Weld 41, actual weld leg = 12.0 mm Weld 43, actual weld leg = 12.0 mm

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t1 or t2 = 0.7 × weld size = 0.7 ×12.0 = 8.4 mm (actual)

1 tmin = 15.875 mm 4 1 t1 + t2 = 8.4 + 8.4 = 16.8 ＞ 1 tmin = 15.875 mm 4

check t1 + t2 ≥ 1

Cover weld satisfactory 8-1-5-4(b) Check for limits of reinforcement: 8-1-5-4(b) (1) Limit parallel to the vessel wall: larger of

d= 198.9 mm

or

Rn + tn + t = 99.45 + 10.1 + 13.4 = 122.95 mm

Use 198.9 mm 8-1-5-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×13.4 =33.5 mm or 2.5tn+te = 2.5×10.1 + 0 = 25.25 mm

Use 25.25 mm 8-1-5-5 Area of reinforcement required [UG-37] 8-1-5-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 198.9 × 6.73 × 1.0 + 2 × 10.1 × 6.73 × 1.0 × (1 − 0.9213) = 1338.6 + 10.7 = 1349.3 mm2 8-1-5-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 198.9×(1×13.4-1×6.73)-2×10.1×(1×13.4-1.0×6.73)×(1-0.9213) = 1326.6 – 10.6 = 1316 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(13.4 + 10.1) × (1×13.4-1×6.73)-2×10.1× (1×13.4-1.0×6.73) × (1-0.9213) = 313.5 – 10.6 = 302.9 mm2 A1=the larger of (A11,A12)= 1316 mm2 8-1-5-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (10.1 − 0.57 ) × 0.9213 × 13.4 = 588.3mm2 A22 = 5(tn − trn ) f r 2tn = 5 × (10.1 − 0.57 ) × 0.9213 × 10.1 = 443.4mm2 A2= the smaller of (A21, A22) = 443.4 mm2

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8-1-5-5(d) Area available in nozzle projecting inward A3

Inner "h" limit:

min[h, 2.5t , 2.5tn]= [810, 33.5 , 25.25] = 25.25 mm

A31 = 5tt j f r 2 = 5 × 13.4 × 10.1 × 0.9213 = 623.4mm 2 A32 = 5t j t j f r 2 = 5 × 10.1 × 10.1 × 0.9213 = 469.9mm 2 A33 = 5ht j f r 2 = 5 × 25.25 × 10.1 × 0.9213 = 1174.8mm 2 A3= the smaller of (A31, A32, A33 ) = 469.9 mm2 8-1-5-5(e) Area available in fillet welds A4 8-1-5-5(e)(1) Area available in outward fillet weld A41 A41= (leg)^2 × fr2 = 12.0 × 12.0 × 0.9213 = 132.6 Sq. mm 8-1-5-5(e)(2) Area available in inward fillet weld A43 A43= (leg)^2 × fr2 = 12.0 × 12.0 × 0.9213 = 132.6 Sq. mm 8-1-5-5(f) Total area available A1 +A2 +A3 +A41 +A43 = 1316 + 443.4 + 469.9 + 132.6 + 132.6 = 2494.5 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-1-5-6 Check the welds per UW-16 and UW-16.1 (i) 8-1-5-6-1 Check Load to be carried by welds [Fig.UG-41.1 Sketch (a)] 8-1-5-6-1 (a) Per UG-41 (b) (1) W1-1 = (A2 + A5 + A41 + A42) × Sv = ( 443.4 + 0 + 132.6 + 0) × 136 = 78336 N W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = ( 443.4+ 469.9 + 132.6 + 132.6 +2 × 10.1 × 13.4 × 0.9213)× 136 = 194191.3 N 8-1-5-6-1 (b) Per UG-41 (b) (2) W= [A - A1 + 2tn fr1 (E1t - Ftr)]Sv = [ 1349.3 – 1316 + 2× 10.1× 0.9213× (1.0 × 13.4 - 1.0 × 6.73)] *136 = 21410.5 N Since W is smaller than W1-1 and W2-2, W may be used in place of W1-1 and W2-2 for comparing weld capacity to weld load. 8-1-5-6-2 Unit Stresses per UG-45(c) and UW-15 (c) 8-1-5-6-2 (a) Fillet weld shear = 0.49×125.3 = 61.4 Mpa 8-1-5-6-2 (b) Nozzle wall shear

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= 0.7×125.3 = 87.71 Mpa 8-1-5-6-3 Strength of connection elements 8-1-5-6-3 (a) Fillet weld shear = π/2 × nozzle O.D. × weld leg × 61.4 = 1.57 × 219.1 × 12.0 ×61.4 = 253449.6 N 8-1-5-6-3 (b) Nozzle wall shear = π/2 × mean nozzle diameter × tn × 87.71 = 1.57×206.4×10.1 × 87.71 = 287064.7 N 8-1-5-6-4 Check Strength paths Path 1-1 = 253449.6 + 287064.7 = 540514.3 N Path 2-2 = 253449.6 + 253449.6 = 506899.2 N All paths are stronger than the required strength of W of 21410.5 N [see UG-41 (b) (2)] Weld Strength Paths Are Adequate. 8-1-6

For steam leaking from gate pole nozzle L (DN100)

●Internal ●Design

design pressure

temperature

●Material

P (MPa) (℃)

of the vessel wall

●Allowable ●Material

per UG-37

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

R (mm)

: 1402.6

t (mm)

: 13.4

Rno(mm)

: 57.15

Rn (mm)

: 48.62

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 8.53

●Finished

diameter of opening corroded

d (mm)

: 97.24

Weld leg (mm)

: 12.0

●Leg

length of outward nozzle fillet weld

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●Leg

REV.: 0

PAGE

length of inward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

89

OF

Weld leg (mm)

: 12.0

θ (deg)

: 0.0

F

: 1.0

152

8-1-6-1 Size of opening Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 97.24 mm, so supplemental rules of 1-7 are not applied. 8-1-6-2 Wall thicknesses Required Required thickness of a seamless shell tr (E=1.0)

Shell

tr =

PR 0.65 × 1402.6 = = 6.73mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

PRno 0.65 × 57.15 = = 0.3mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-1-6-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV=125.3/136 = 0.9213 Strength reduction factor for nozzle fr2 fr2=Sn/SV =125.3/136 = 0.9213 8-1-6-4 Size of weld required [UW-16(c),Fig.UW-16.1 Sketch (i)] 8-1-6-4(a) throat size of weld required UW-16(b) t1 or t2 = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 16.0 , 11.13 ) = 11.13 mm t1 or t2 ≥ min.( 6 , 0.7×11.13 ) = 6.0 mm therefore throat must be at least 6.0 mm Weld 41, actual weld leg = 12.0 mm

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Weld 43, actual weld leg = 12.0 mm t1 or t2 = 0.7 × weld size = 0.7 ×12.0 = 8.4 mm (actual)

1 tmin = 13.9125 mm 4 1 t1 + t2 = 8.4 + 8.4 = 16.8 ＞ 1 tmin = 13.9125 mm 4

check t1 + t2 ≥ 1

Cover weld satisfactory 8-1-6-4(b) Check for limits of reinforcement: 8-1-6-4(b) (1) Limit parallel to the vessel wall: larger of

d= 97.24 mm

or

Rn + tn + t = 48.62 + 8.53 + 13.4 = 70.55 mm

Use 97.24 mm 8-1-6-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×13.4 =33.5 mm or 2.5tn+te = 2.5×8.53 + 0 = 21.325 mm

Use 21.325 mm 8-1-6-5 Area of reinforcement required [UG-37] 8-1-6-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 97.24 × 6.73 × 1.0 + 2 × 8.53 × 6.73 × 1.0 × (1 − 0.9213) = 654.5 + 9.1 = 663.6 mm2 8-1-6-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 97.24×(1×13.4-1×6.73)-2×8.53×(1×13.4-1.0×6.73)×(1-0.9213) = 648.6 – 9.0 = 639.6 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(13.4 + 8.53) × (1×13.4-1×6.73)-2×8.53× (1×13.4-1.0×6.73) × (1-0.9213) = 292.5 – 9.0 = 283.5 mm2 A1=the larger of (A11,A12)= 639.6 mm2 8-1-6-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (8.53 − 0.3) × 0.9213 × 13.4 = 508mm 2 A22 = 5(tn − trn ) f r 2tn = 5 × (8.53 − 0.3) × 0.9213 × 8.53 = 323.4mm2

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A2= the smaller of (A21, A22) = 323.4 mm2 8-1-6-5(d) Area available in nozzle projecting inward A3

Inner "h" limit:

min[h, 2.5t , 2.5tn]= [1400, 33.5 , 21.325] = 21.325 mm

A31 = 5tt j f r 2 = 5 × 13.4 × 8.53 × 0.9213 = 526.5mm 2 A32 = 5t j t j f r 2 = 5 × 8.53 × 8.53 × 0.9213 = 335.1mm 2 A33 = 5ht j f r 2 = 5 × 21.325 × 8.53 × 0.9213 = 837.9mm 2 A3= the smaller of (A31, A32, A33 ) = 335.1 mm2 8-1-6-5(e) Area available in fillet welds A4 8-1-6-5(e)(1) Area available in outward fillet weld A41 A41= (leg)^2 × fr2 = 12.0 × 12.0 × 0.9213 = 132.6 Sq. mm 8-1-6-5(e)(2) Area available in inward fillet weld A43 A43= (leg)^2 × fr2 = 12.0 × 12.0 × 0.9213 = 132.6 Sq. mm 8-1-6-5(f) Total area available A1 +A2 +A3 +A41 +A43 = 639.6 + 323.4 + 335.1 + 132.6 + 132.6 = 1563.3 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-1-6-6 Check the welds per UW-16 and UW-16.1 (i) 8-1-6-6-1 Check Load to be carried by welds [Fig.UG-41.1 Sketch (a)] 8-1-6-6-1 (a) Per UG-41 (b) (1) W1-1 = (A2 + A5 + A41 + A42) × Sv = ( 323.4 + 0 + 132.6 + 0) × 136 = 62016 N W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = ( 323.4+ 335.1 + 132.6 + 132.6 +2 × 8.53 × 13.4 × 0.9213)× 136 = 154266.5 N 8-1-6-6-1 (b) Per UG-41 (b) (2) W= [A - A1 + 2tn fr1 (E1t - Ftr)]Sv = [ 663.6 – 639.6 + 2× 8.53× 0.9213× (1.0 × 13.4 - 1.0 × 6.73)] *136 = 17521.5 N Since W is smaller than W1-1 and W2-2, W may be used in place of W1-1 and W2-2 for comparing weld capacity to weld load. 8-1-6-6-2 Unit Stresses per UG-45(c) and UW-15 (c) 8-1-6-6-2 (a) Fillet weld shear = 0.49×125.3 = 61.4 Mpa

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8-1-6-6-2 (b) Nozzle wall shear = 0.7×125.3 = 87.71 Mpa 8-1-6-6-3 Strength of connection elements 8-1-6-6-3 (a) Fillet weld shear = π/2 × nozzle O.D. × weld leg × 61.4 = 1.57 × 114.3 × 12.0 ×61.4 = 132219.5 N 8-1-6-6-3 (b) Nozzle wall shear = π/2 × mean nozzle diameter × tn × 87.71 = 1.57×103.17×8.53 × 87.71 = 121185.6 N 8-1-6-6-4 Check Strength paths Path 1-1 = 132219.5 + 121185.6 = 253405.1 N Path 2-2 = 132219.5 + 132219.5 = 264439 N All paths are stronger than the required strength of W of 17303.9 N [see UG-41 (b) (2)] Weld Strength Paths Are Adequate. 8-1-7

For high level electric offlet nozzle S (DN100) per UG-37

●Internal ●Design

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

R (mm)

: 1402.6

t (mm)

: 13.4

Rno(mm)

: 57.15

Rn (mm)

: 48.62

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 8.53

●Finished

diameter of opening corroded

d (mm)

: 97.24

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length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

93

Weld leg (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

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8-1-7-1 Size of opening Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 97.24 mm, so supplemental rules of 1-7 are not applied. 8-1-7-2 Wall thicknesses Required Required thickness of a seamless shell tr (E=1.0)

Shell

tr =

PR 0.65 × 1402.6 = = 6.73mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

PRno 0.65 × 57.15 = = 0.3mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-1-7-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV= 125.3/136= 0.9213 Strength reduction factor for nozzle fr2 fr2=Sn/SV = 125.3/136 = 0.9213 8-1-7-4 Size of weld required [UW-16(c),Fig.UW-16.1 Sketch (e)] 8-1-7-4(a) throat size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 16.0, 11.13 ) = 11.13 mm tc (mininum) = lesser of 1/4 in. or 0.7 tmin, 6.0 or 0.7×11.13 = 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm

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Cover weld satisfactory 8-1-7-4(b) Check for limits of reinforcement: 8-1-7-4(b) (1) Limit parallel to the vessel wall: larger of d = 97.24 mm or Rn + tn + t = 48.62 + 8.53 + 13.4 = 70.55 mm Use 97.24 mm 8-1-7-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×13.4 = 33.5 mm or 2.5tn+te = 2.5×8.53 + 0 = 21.325 mm

Use 21.325 mm 8-1-7-5 Area of reinforcement required [UG-37] 8-1-7-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 97.24 × 6.73 × 1.0 + 2 × 8.53 × 6.73 × 1.0 × (1 − 0.9213) = 654.5 + 9.1 = 663.6 mm2 8-1-7-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 97.24×(1.0×13.4-1×6.73)-2×8.53×(1.0×13.4-1.0×6.73)×(1-0.9213) = 648.6 – 9.0 = 639.6 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(13.4 + 8.53) × (1.0×13.4-1×6.73)-2×8.53× (1.0×13.4-1.0×6.73)×(1-0.9213) = 292.5 – 9.0 = 283.5 mm2 A1 = the larger of (A11,A12) = 639.6 mm2 8-1-7-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (8.53 − 0.3) × 0.9213 × 13.4 = 508mm 2 A22 = 5(tn − trn ) f r 2tn = 5 × (8.53 − 0.3) × 0.9213 × 8.53 = 323.4mm2 A2=the smaller of (A21, A22) = 323.4 mm2 8-1-7-5(d) Area available in welds A4 8-4-5(d)(1) Area available in outward weld A41 8-1-7-5(e)

A41= (leg)^2 × fr2 = 9.0 × 9.0 × 0.9213 = 74.6 Sq. mm Total area available

A1 +A2 +A41 = 639.6 + 323.4 + 74.6 = 1037.6 Sq. mm

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This is greater than the required area so is a reinforcing element is not needed. 8-1-7-6

Strength calculations for attachment welds are not required for this detail which conforms with Fig. UW-16.1 sketch (e) [see UW-15(b)]

8-1-8

For water outlet nozzle O (R) (DN250)

●Internal ●Design

per UG-37

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

R (mm)

: 1402.6

t (mm)

: 13.4

Rno(mm)

: 136.5

Rn (mm)

: 126.4

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 10.1

●Finished

diameter of opening corroded

d (mm)

: 252.8

Weld leg (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

8-1-8-1 Size of opening Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 252.8 mm, so supplemental rules of 1-7 are not applied. 8-1-8-2 Wall thicknesses Required

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Required thickness of a seamless shell tr (E=1.0)

PR 0.65 × 1402.6 = = 6.73mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

tr =

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

PRno 0.65 × 136.5 = = 0.71mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-1-8-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV= 125.3/136= 0.9213 Strength reduction factor for nozzle fr2 fr2=Sn/SV = 125.3/136 = 0.9213 8-1-8-4 Size of weld required [UW-16(c),Fig.UW-16.1 Sketch (e)] 8-1-8-4(a) throat size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 16.0, 12.7 ) = 12.7 mm tc (mininum) = lesser of 1/4 in. or 0.7 tmin, 6.0 or 0.7× 12.7= 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm Cover weld satisfactory 8-1-8-4(b) Check for limits of reinforcement: 8-1-8-4(b) (1) Limit parallel to the vessel wall: larger of d = 252.8 mm or Rn + tn + t = 126.4 + 10.1 + 13.4 = 149.9 mm Use 252.8 mm 8-1-8-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×13.4 = 33.5 mm or 2.5tn+te = 2.5× 10.1 + 0 = 25.25 mm

Use 25.25 mm 8-1-8-5 Area of reinforcement required [UG-37]

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Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 252.8 × 6.73 × 1.0 + 2 × 10.1 × 6.73 × 1.0 × (1 − 0.9213) = 1701.4 + 10.7 = 1712.1 mm2 8-1-8-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 252.8×(1.0×13.4-1×6.73)-2×10.1×(1.0×13.4-1.0×6.73)×(1-0.9213) = 1686.2 – 10.6 = 1675.6 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(13.4 + 10.1) × (1.0×13.4-1×6.73)-2×10.1× (1.0×13.4-1.0×6.73)×(1-0.9213) = 313.5 – 10.6 = 302.9 mm2 A1 = the larger of (A11,A12) = 1675.6 mm2 8-1-8-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (10.1 − 0.71) × 0.9213 × 13.4 = 579.6mm 2 A22 = 5(tn − trn ) f r 2tn = 5 × (10.1 − 0.71) × 0.9213 × 10.1 = 436.8mm 2 A2=the smaller of (A21, A22) = 436.8 mm2 8-1-8-5(d) Area available in welds A4 8-4-5(d)(1) Area available in outward weld A41 8-1-8-5(e)

A41= (leg)^2 × fr2 = 9.0 × 9.0 × 0.9213 = 74.6 Sq. mm Total area available

A1 +A2 +A41 = 1675.6 + 436.8 + 74.6 = 2187 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-1-8-6

Strength calculations for attachment welds are not required for this detail which conforms with Fig. UW-16.1 sketch (e) [see UW-15(b)]

8-1-9

For thermometer nozzle V2-3 (DN20)

Since the welded nozzles V2-3 (DN20) are neither subject to rapid fluctuations in pressure nor larger than 60 mm, reinforcement of openings is not required. 8-1-10

[UG-36 (c) (3)]

For pressure gauge nozzle W2 (DN15) per UG-37

Since the welded nozzles nozzle W2 (DN15) is neither subject to rapid fluctuations in pressure nor larger than 60 mm, reinforcement of openings is not required.

[UG-36 (c) (3)]

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For sampling water nozzle P1-2 (DN10)

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per UG-37

Since the welded nozzles nozzle P1-2 (DN10) are neither subject to rapid fluctuations in pressure nor larger than 60 mm, reinforcement of openings is not required. 8-1-12

For water level nozzle T1-2.U1-4.X1-2.Z1-2 (DN50)

●Internal ●Design

design pressure

temperature

●Material

per UG-37 P (MPa) (℃)

of the vessel wall

●Allowable ●Material

[UG-36 (c) (3)]

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

R (mm)

: 1402.6

t (mm)

: 13.4

Rno(mm)

: 30.15

Rn (mm)

: 24.01

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 6.14

●Finished

diameter of opening corroded

d (mm)

: 48.02

Weld leg (mm)

: 9.0

θ (deg)

: 90

F

: 0.5

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

8-1-12-1 Size of opening Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 48.02 mm, so supplemental rules of 1-7 are not applied.

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8-1-12-2 Wall thicknesses Required Required thickness of a seamless shell tr (E=1.0)

Shell

PR 0.65 × 1402.6 = = 6.73mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

tr =

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

PRno 1.0 × 30.15 = = 0.16mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-1-12-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1= Sn/SV= 125.3/136 = 0.9213 Strength reduction factor for nozzle fr2 fr2= Sn/SV = 125.3/136 = 0.9213 8-1-12-4 Size of weld required [UW-16(b), Fig.UW-16.1 Sketch (e)] 8-1-12-4 (a) Outward nozzle fillet weld: tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 16.0 , 8.74 ) = 8.74 mm tc ( minimum ) = lesser of 1/4 in. or 0.7 tmin , 6.0 or 0.7×8.74 = 6.0 mm Weld 41, actual weld leg = 9.0 mm Weld throat = 0.7 × weld size = 0.7 × 9.0 = 6.3 mm The weld size is satisfactory . 8-1-12-4 (b) In plane 90 deg to longitudinal axis : 8-1-12-4 (b) (1) calculate the opening chord length at mid-surface of the required shell thickness as follows: Rm = R+tr/2= 1402.6 + 6.73/2 = 1405.965 mm L= 1100 mm α1= cos-1(

L + Rn 1100 + 24.01 ) = cos-1( ) = 36.9 deg Rm 1405.965

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L − Rn 1100 − 24.01 ) = cos-1( ) = 40.1 deg Rm 1405.965

α=α2-α1=40.1-36.9= 3.2 deg

1 − cos 2 (а/ 2) =2×1405.965× 1 − cos 2 (3.2 / 2) =78.52 mm

d = 2Rm

Per UG-37(b) and Fig.UG-37, F=0.5 8-1-12-4(b) (2) Check for limits of reinforcement: 8-1-12-4 (b) (2-1) Limit parallel to the vessel wall (circumferentially): larger of

dc = 78.52 mm

or

Rnc + tn + t = 39.26 + 6.14 + 13.4 = 58.8 mm

Use 78.52 mm 8-1-12-4 (b) (2-2) Limit normal to the vessel wall: smaller of

2.5t = 2.5×13.4 = 33.5 mm or 2.5tn+te = 2.5×6.14 + 0 = 15.35 mm

Use 15.35 mm 8-1-12-5 Area of reinforcement required in plane 90 deg to longitudinal axis

A = dtr F + 2tntr F (1 − f r1 ) = 78.52 × 6.73 × 0.5 + 2 × 6.14 × 6.73 × 0.5 × (1 − 0.9213) = 264.3 + 3.3 = 267.6 mm2 8-1-12-6 Area of reinforcement available in plane 90 deg to longitudinal axis 8-1-12-6 (a) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 78.52×(1×13.4-0.5×6.73)-2×6.14×(1×13.4-0.5×6.73)×(1-0.9213) = 787.9 –9.7 = 778.2 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(13.4 + 6.14) × (1×13.4-0.5×6.73)-2×6.14× (1×13.4-0.5×6.73)×(1-0.9213) = 392.2 – 9.7 = 382.5 mm2 A1= the larger of (A11,A12)= 778.2 mm2 8-1-12-6 (b) Area available in nozzle A2 α3= cos-1(

1100 − 24.01 L − Rn ) = cos-1( ) = 40.5 deg R+t 1402.6 + 13.4

A2 = the smaller of the following

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By observation, A2 on the upper side of the nozzle is smaller than A2 on the lower side of the nozzle. In accordance with UG-37(b), not less than half the required reinforcement shall be on each side of the opening. Therefore,A2 on the lower side shall not be greater than A2 on the upper side.

A21 = 5(tn − trn ) f r 2t / sin(α3 ) = 5 × (6.14 − 0.16) × 0.9213 × 13.4 / sin 40.5 = 568.3mm2 A22 = 5(tn − trn )tn f r 2 / sin(α3 ) = 5 × (6.14 − 0.16) × 6.14 × 0.9213 / sin 40.5 = 260.4mm2 A2 = the smaller of (A21, A22) = 260.4 mm2 8-1-12-6(c) Area available in outward nozzle weld: Since the welds vary from a fillet to a butt-type weld, and A41 will not be considered. 8-1-12-6 (d) Area provided by A1 + A2 = 778.2 + 260.4 = 1038.6 Sq. mm ＞ A= 267.6 Sq. mm This is greater than the required reinforcing area of 267.6 sq. mm. Therefore, the opening is adequately reinforced in the plane considered. 8-4-7 Since the plane under consideration requires only 50% (F=0.5) of the required reinforcement in the plane parallel to the longitudinal shell axis, the opening may not be adequately reinforced in the other planes. A check for reinforcement in plane parallel to the longitudinal shell axis is needed. d = 48.02 mm

F = 1.0

8-1-12-7 (a) Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 48.02 × 6.73 ×1.0 + 2 × 6.14×6.73×1.0 × (1-0.9213) = 323.2 + 6.6 = 329.8 mm2 8-1-12-7 (b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 48.02×(1×13.4-1×6.73)-2×6.14 ×(1×13.4-1.0×6.73)×(1-0.9213) = 320.2 – 6.5 = 313.7 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2×(13.4+6.14) × (1×13.4-1×6.73)-2×6.14× (1×13.4-1.0×6.73)×(1-0.9213) = 260.6 – 6.5 = 254.1 mm2 A1=the larger of (A11,A12) = 313.7 mm2

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8-1-12-7 (c) Area available in nozzle A2

A21 = 5(tn − trn ) f r 2t = 5 × (6.14 − 0.16) × 0.9213 × 13.4 = 369.1mm 2 A22 = 5(tn − trn ) f r 2tn = 5 × (6.14 − 0.16) × 0.9213 × 6.14 = 169.1mm2 A2 = the smaller of (A21, A22) =169.1 mm2 8-1-12-7 (d) Area available in outward nozzle weld A41: A41= (leg)^2 × fr2 = 9.0 × 9.0 × 0.9213 = 74.6 Sq. mm 8-1-12-7 (e) Total area available A1 +A2 +A41 = 313.7 + 169.1 + 74.6 = 557.4 Sq. mm This is greater than the required reinforcing area of 329.8 Sq. mm; therefore, opening is adequately reinforced. 8-1-13

For annectent nozzle of tank and tower (DN800)

●Internal ●Design

design pressure

temperature

●Material

P (MPa) (℃)

of the vessel wall

●Allowable ●Material

per UG-37

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-516MGr.485

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 136

●Corrosion

allowance (designated by customer)

C (mm)

: 2.6

R (mm)

: 1402.6

t (mm)

: 13.4

Rno(mm)

: 406.4

Rn (mm)

: 393

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 13.4

●Finished

diameter of opening corroded

d (mm)

: 786

●Leg

length of outward nozzle fillet weld

Weld leg (mm)

: 16.0

●Leg

length of inward nozzle fillet weld

Weld leg (mm)

: 16.0

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●Correction

factor

103

θ (deg)

: 0.0

F

: 1.0

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8-1-13-1 Size of opening Since ID is 2800mm, according to UG-36(b) (1), third of the vessel diameter is 933 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 786 mm, so supplemental rules of 1-7 are not applied. 8-1-13-2 Wall thicknesses Required Required thickness of a seamless shell tr (E=1.0)

Shell

tr =

0.65 × 1402.6 PR = = 6.73mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

0.65 × 393 PRno = = 1.88mm S n E1 + 0.4 P 136 × 1 + 0.4 × 0.65

8-1-13-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV=136/136 = 1.0 Strength reduction factor for nozzle fr2 fr2=Sn/SV =136/136 = 1.0 8-1-13-4 Size of weld required [UW-16(c), Fig.UW-16.1 Sketch (i)] 8-1-13-4(a) throat size of weld required UW-16(b) t1 or t2 = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 16.0 , 16.0 ) = 16.0 mm t1 or t2 ≥ min.( 6 , 0.7×16.0 ) = 6.0 mm therefore throat must be at least 6.0 mm Weld 41, actual weld leg = 16.0 mm Weld 43, actual weld leg = 16.0 mm

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t1 or t2 = 0.7 × weld size = 0.7 ×16.0 = 11.2 mm (actual)

1 tmin = 20.0 mm 4 1 t1 + t2 = 11.2 + 11.2 = 22.4 ＞ 1 tmin = 20.0 mm 4

check t1 + t2 ≥ 1

Cover weld satisfactory 8-1-13-4(b) Check for limits of reinforcement: 8-1-13-4(b) (1) Limit parallel to the vessel wall: larger of

d= 786 mm

or

Rn + tn + t = 393 + 13.4 + 13.4 = 419.8 mm

Use 786 mm 8-1-13-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×13.4 =33.5 mm or 2.5tn+te = 2.5×13.4 + 0 = 33.5 mm

Use 33.5 mm 8-1-13-5 Area of reinforcement required [UG-37] 8-1-13-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 786 × 6.73 × 1.0 + 2 × 13.4 × 6.73 × 1.0 × (1 − 1.0) = 5289.78 + 0 = 5289.78 mm2 8-1-13-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 786×(1×13.4-1×6.73)-2×13.4×(1×13.4-1.0×6.73)×(1-1.0) = 5242.62 – 0 = 5242.62 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(13.4 + 13.4) × (1×13.4-1×6.73)-2×13.4× (1×13.4-1.0×6.73) × (1-1.0) = 357.5 – 0 = 357.5 mm2 A1=the larger of (A11,A12)= 5242.62 mm2 8-1-13-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (13.4 − 1.88) × 1.0 × 13.4 = 771.84mm2 A22 = 5(tn − trn ) f r 2tn = 5 × (13.4 − 1.88) × 1.0 × 13.4 = 771.84mm2 A2= the smaller of (A21, A22) = 771.84 mm2

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8-1-13-5(d) Area available in nozzle projecting inward A3

Inner "h" limit:

min[h, 2.5t , 2.5tn]= [50, 33.5 , 33.5] = 33.5 mm

A31 = 5tt j f r 2 = 5 × 13.4 × 13.4 × 1.0 = 897.8mm 2 A32 = 5t j t j f r 2 = 5 × 13.4 × 13.4 × 1.0 = 897.8mm 2 A33 = 5ht j f r 2 = 5 × 33.5 × 13.4 × 1.0 = 2237.8mm 2 A3= the smaller of (A31, A32, A33 ) = 897.8 mm2 8-1-13-5(e) Area available in fillet welds A4 8-1-13-5(e)(1) Area available in outward fillet weld A41 A41= (leg)^2 × fr2 = 16.0 × 16.0 × 1.0 = 196 Sq. mm 8-1-13-5(e)(2) Area available in inward fillet weld A43 8-1-13-5(f)

A43= (leg)^2 × fr2 = 16.0 × 16.0 × 1.0 = 196 Sq. mm Total area available

A1 +A2 +A3 +A41 +A43 = 5242.62 + 771.84 + 897.8 + 196 + 196 = 7304.26 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-1-13-6 Check the welds per UW-16 and UW-16.1 (i) 8-1-13-6-1 Check Load to be carried by welds [Fig.UG-41.1 Sketch (a)] 8-1-13-6-1 (a) Per UG-41 (b) (1) W1-1 = (A2 + A5 + A41 + A42) × Sv = ( 771.84 + 0 + 196 + 0) × 136 = 131626.2 N W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (771.84+ 897.8 + 196 + 196 +2 × 13.4 × 13.4 × 1.0)× 136 = 329223.4 N 8-1-13-6-1 (b) Per UG-41 (b) (2) W= [A - A1 + 2tn fr1 (E1t - Ftr)]Sv = [5289.78 – 5242.62 + 2× 13.4× 1.0× (1.0 × 13.4 - 1.0 × 6.73)] *136 = 30725 N Since W is smaller than W1-1 and W2-2, W may be used in place of W1-1 and W2-2 for comparing weld capacity to weld load. 8-1-13-6-2 Unit Stresses per UG-45(c) and UW-15 (c) 8-1-13-6-2 (a) Fillet weld shear = 0.49×136 = 66.64 Mpa 8-1-13-6-2 (b) Nozzle wall shear

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= 0.7×136 = 95.2 Mpa 8-1-13-6-3 Strength of connection elements 8-1-13-6-3 (a) Fillet weld shear = π/2 × nozzle O.D. × weld leg × 61.4 = 1.57 × 812.8 × 16.0 ×66.64 = 1360624.6 N 8-1-13-6-3 (b) Nozzle wall shear = π/2 × mean nozzle diameter × tn × 87.71 = 1.57×796.8×13.4 × 95.2 = 1595845 N 8-1-13-6-4 Check Strength paths Path 1-1 = 1360624.6 + 1595845 = 2956469.6 N Path 2-2 = 1360624.6 + 1360624.6 = 2721249.2 N All paths are stronger than the required strength of W of 30725 N [see UG-41 (b) (2)] Weld Strength Paths Are Adequate. 8-2 DEAERATOR′S TOWER: 8-2-1

For HP drain inlet nozzle E (DN100)

●Internal ●Design

per UG-37

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 3.5

R (mm)

: 903.5

t (mm)

: 8.5

Rno(mm)

: 57.15

Rn (mm)

: 49.52

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 7.63

●Finished

diameter of opening corroded

d (mm)

: 99.04

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●Leg

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length of outward nozzle fillet weld

length of inward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

107

Weld leg (mm)

: 10.0

Weld leg (mm)

: 10.0

θ (deg)

: 0.0

F

: 1.0

OF

152

8-2-1-1 Size of opening Since ID is 1800mm, according to UG-36(b) (1), third of the vessel diameter is 600 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 99.04 mm, so supplemental rules of 1-7 are not applied. 8-2-1-2 Wall thicknesses Required Required thickness of a seamless shell tr (E=1.0)

Shell

tr =

0.65 × 903.5 PR = = 4.34mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

0.65 × 57.15 PRno = = 0.3mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-2-1-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV=125.3/136 = 0.9213 Strength reduction factor for nozzle fr2 fr2=Sn/SV =125.3/136 = 0.9213 8-2-1-4 Size of weld required [UW-16(c), Fig.UW-16.1 Sketch (i)] 8-2-1-4(a) throat size of weld required UW-16(b) t1 or t2 = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 12.0 , 11.13 ) = 11.13 mm t1 or t2 ≥ min.( 6 , 0.7×11.13 ) = 6.0 mm

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therefore throat must be at least 6.0 mm Weld 41, actual weld leg = 10.0 mm Weld 43, actual weld leg = 10.0 mm t1 or t2 = 0.7 × weld size = 0.7 ×10.0 = 7.0 mm (actual)

1 tmin = 13.9 mm 4 1 t1 + t2 = 7.0 + 7.0 = 14.0 ＞ 1 tmin = 13.9 mm 4

check t1 + t2 ≥ 1

Cover weld satisfactory 8-2-1-4(b) Check for limits of reinforcement: 8-2-1-4(b) (1) Limit parallel to the vessel wall: larger of

d= 99.04 mm

or

Rn + tn + t = 49.52 + 7.63 + 8.5 = 65.65 mm

Use 99.04 mm 8-2-1-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×8.5 =21.25 mm or 2.5tn+te = 2.5×7.63 + 0 = 19.075 mm

Use 19.075 mm 8-2-1-5 Area of reinforcement required [UG-37] 8-2-1-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 99.04 × 4.34 × 1.0 + 2 × 7.63 × 4.34 × 1.0 × (1 − 0.9213) = 429.9 + 5.3 = 435.2 mm2 8-2-1-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 99.04×(1×8.5-1×4.34)-2×7.63×(1×8.5-1.0×4.34)×(1-0.9213) = 412 – 5.0 = 407 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(8.5 + 7.63) × (1×8.5-1×4.34)-2×7.63× (1×8.5-1.0×4.34) × (1-0.9213) = 106.8 – 5.0 = 101.8 mm2 A1=the larger of (A11,A12)= 407 mm2 8-2-1-5(c)

Area available in nozzle projecting outward A2

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A21 = 5(tn − trn ) f r 2t = 5 × (7.63 − 0.3) × 0.9213 × 8.5 = 287mm2 A22 = 5(tn − trn ) f r 2tn = 5 × (7.63 − 0.3) × 0.9213 × 7.63 = 257.6mm2 A2= the smaller of (A21, A22) = 257.6 mm2 8-2-1-5(d) Area available in nozzle projecting inward A3

Inner "h" limit:

min[h, 2.5t , 2.5tn]= [150, 21.25 , 19.075] = 19.075 mm

A31 = 5tt j f r 2 = 5 × 8.5 × 7.63 × 0.9213 = 298.7 mm 2 A32 = 5t j t j f r 2 = 5 × 7.63 × 7.63 × 0.9213 = 268.1mm 2 A33 = 5ht j f r 2 = 5 × 19.075 × 7.63 × 0.9213 = 670.4mm 2 A3= the smaller of (A31, A32, A33 ) = 268.1 mm2 8-2-1-5(e) Area available in fillet welds A4 8-2-1-5(e)(1) Area available in outward fillet weld A41 A41= (leg)^2 × fr2 = 10.0 × 10.0 × 0.9213 = 92.1 Sq. mm 8-2-1-5(e)(2) Area available in inward fillet weld A43 A43= (leg)^2 × fr2 = 10.0 × 10.0 × 0.9213 = 92.1 Sq. mm 8-2-1-5(f) Total area available A1 +A2 +A3 +A41 +A43 = 407 + 257.6 + 268.1 + 92.1 + 92.1 = 1116.9 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-2-1-6 Check the welds per UW-16 and UW-16.1 (i) 8-2-1-6-1 Check Load to be carried by welds [Fig.UG-41.1 Sketch (a)] 8-2-1-6-1 (a) Per UG-41 (b) (1) W1-1 = (A2 + A5 + A41 + A42) × Sv = ( 257.6 + 0 + 92.1 + 0) × 136 = 47559.2 N W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = ( 257.6+ 268.1 + 92.1 + 92.1 +2 × 7.63 × 8.5 × 0.9213)× 136 = 112798.6 N 8-2-1-6-1 (b) Per UG-41 (b) (2) W= [A - A1 + 2tn fr1 (E1t - Ftr)]Sv = [ 435.2 – 407 + 2× 7.63× 0.9213× (1.0 × 8.5 - 1.0 × 4.34)] *136 = 11789 N Since W is smaller than W1-1 and W2-2, W may be used in place of W1-1 and W2-2 for comparing weld capacity to weld load.

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8-2-1-6-2 Unit Stresses per UG-45(c) and UW-15 (c) 8-2-1-6-2 (a) Fillet weld shear = 0.49×125.3 = 61.4 Mpa 8-2-1-6-2 (b) Nozzle wall shear = 0.7×125.3 = 87.71 Mpa 8-2-1-6-3 Strength of connection elements 8-2-1-6-3 (a) Fillet weld shear = π/2 × nozzle O.D. × weld leg × 61.4 = 1.57 × 114.3 × 10.0 ×61.4 = 110182.9 N 8-2-1-6-3 (b) Nozzle wall shear = π/2 × mean nozzle diameter × tn × 87.71 = 1.57×103.17×8.53 × 87.71 = 121185.6 N 8-2-1-6-4 Check Strength paths Path 1-1 = 110182.9 + 121185.6 = 231368.5 N Path 2-2 = 110182.9 + 110182.9 = 220365.8 N All paths are stronger than the required strength of W of 11789 N [see UG-41 (b) (2)] Weld Strength Paths Are Adequate. 8-2-2 For water inlet from slag-cooler Y2 and secondary steam inlet nozzle J (DN80) per UG-37 ●Internal ●Design

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 3.5

R (mm)

: 903.5

t (mm)

: 8.5

Rno(mm)

: 44.45

Rn (mm)

: 36.82

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

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OF

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 7.63

●Finished

diameter of opening corroded

d (mm)

: 73.64

Weld leg (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

152

8-2-2-1 Size of opening Since ID is 1800mm, according to UG-36(b) (1), third of the vessel diameter is 600 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 73.64 mm, so supplemental rules of 1-7 are not applied. 8-2-2-2 Wall thicknesses Required Required thickness of a seamless shell tr (E=1.0)

Shell

tr =

0.65 × 903.5 PR = = 4.34mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

0.65 × 44.45 PRno = = 0.24mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-2-2-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV= 125.3/136= 0.9213 Strength reduction factor for nozzle fr2 fr2=Sn/SV = 125.3/136 = 0.9213 8-2-2-4 Size of weld required [UW-16(c), Fig.UW-16.1 Sketch (c)] 8-2-2-4(a) throat size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 12.0, 11.13 ) = 11.13 mm

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tc (mininum) = lesser of 1/4 in. or 0.7 tmin, 6.0 or 0.7× 11.13= 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm Cover weld satisfactory 8-2-2-4(b) Check for limits of reinforcement: 8-2-2-4(b) (1) Limit parallel to the vessel wall: larger of d = 73.64 mm or Rn + tn + t = 36.82 + 7.63 + 8.5 = 52.95 mm Use 73.64 mm 8-2-2-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×8.5 = 21.25 mm or 2.5tn+te = 2.5× 7.63 + 0 = 19.075 mm

Use 19.075 mm 8-2-2-5 Area of reinforcement required [UG-37] 8-2-2-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 73.64 × 4.34 × 1.0 + 2 × 7.63 × 4.34 × 1.0 × (1 − 0.9213) = 319.6 + 5.3 = 324.9 mm2 8-2-2-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 73.64×(1.0×8.5-1×4.34)-2×7.63×(1.0×8.5-1.0×4.34)×(1-0.9213) = 306.3 – 5.0 = 301.3 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(8.5 + 7.63) × (1.0×8.5-1×4.34)-2×7.63× (1.0×8.5-1.0×4.34)×(1-0.9213) = 134.2 – 5.0 = 129.2 mm2 A1 = the larger of (A11,A12) = 301.3 mm2 8-2-2-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (7.63 − 0.24 ) × 0.9213 × 8.5 = 289.3mm2 A22 = 5(tn − trn ) f r 2tn = 5 × (7.63 − 0.24) × 0.9213 × 7.63 = 259.7mm2 A2=the smaller of (A21, A22) = 259.7 mm2 8-2-2-5(d) Area available in welds A4

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8-2-2-5(d)(1) Area available in outward weld A41 8-2-2-5(e)

A41= (leg)^2 × fr2 = 9.0 × 9.0 × 0.9213 = 74.6 Sq. mm Total area available

A1 +A2 +A41 = 301.3 + 259.7 + 74.6 = 635.6 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-2-2-6

Strength calculations for attachment welds are not required for this detail which conforms with Fig. UW-16.1 sketch (c) [see UW-15(b)]

8-2-3

For check-up nozzle F (DN150) per UG-37

●Internal ●Design

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 3.5

R (mm)

: 903.5

t (mm)

: 8.5

Rno(mm)

: 84.15

Rn (mm)

: 76.68

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 7.47

●Finished

diameter of opening corroded

d (mm)

: 153.36

Weld leg (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

8-2-3-1 Size of opening Since ID is 1800mm, according to UG-36(b) (1), third of the vessel diameter is 600 mm, and doesn’t

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exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 153.36 mm, so supplemental rules of 1-7 are not applied. 8-2-3-2 Wall thicknesses Required Required thickness of a seamless shell tr (E=1.0)

Shell

0.65 × 903.5 PR = = 4.34mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

tr =

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

0.65 × 84.15 PRno = = 0.44mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-2-3-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV= 125.3/136= 0.9213 Strength reduction factor for nozzle fr2 fr2=Sn/SV = 125.3/136 = 0.9213 8-2-3-4 Size of weld required [UW-16(c), Fig.UW-16.1 Sketch (c)] 8-2-3-4(a) throat size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 12.0, 10.97 ) = 10.97 mm tc (mininum) = lesser of 1/4 in. or 0.7 tmin, 6.0 or 0.7× 10.97= 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm Cover weld satisfactory 8-2-3-4(b) Check for limits of reinforcement: 8-2-3-4(b) (1) Limit parallel to the vessel wall: larger of d = 153.36 mm or Rn + tn + t = 76.68 + 7.47 + 8.5 = 92.65 mm Use 153.36 mm 8-2-3-4(b) (2) Limit normal to the vessel wall:

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2.5t = 2.5×8.5 = 21.25 mm or 2.5tn+te = 2.5× 7.47 + 0 = 18.675 mm

Use 18.675 mm 8-2-3-5 Area of reinforcement required [UG-37] 8-2-3-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 153.36 × 4.34 × 1.0 + 2 × 7.47 × 4.34 × 1.0 × (1 − 0.9213) = 665.6 + 5.2 = 670.8 mm2 8-2-3-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 153.36×(1.0×8.5-1×4.34)-2×7.47×(1.0×8.5-1.0×4.34)×(1-0.9213) = 638 – 4.9 = 633.1 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(8.5 + 7.47) × (1.0×8.5-1×4.34)-2×7.47× (1.0×8.5-1.0×4.34)×(1-0.9213) = 132.9 – 4.9 = 128 mm2 A1 = the larger of (A11,A12) = 633.1 mm2 8-2-3-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (7.47 − 0.44) × 0.9213 × 8.5 = 275.2mm 2 A22 = 5(tn − trn ) f r 2tn = 5 × (7.47 − 0.44) × 0.9213 × 7.47 = 241.9mm2 A2=the smaller of (A21, A22) = 241.9 mm2 8-2-3-5(d) Area available in welds A4 8-2-3-5(d)(1) Area available in outward weld A41 8-2-3-5(e)

A41= (leg)^2 × fr2 = 9.0 × 9.0 × 0.9213 = 74.6 Sq. mm Total area available

A1 +A2 +A41 = 633.1 + 241.9 + 74.6 = 949.6 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-2-3-6

Strength calculations for attachment welds are not required for this detail which conforms with Fig. UW-16.1 sketch (c) [see UW-15(b)]

8-2-4

For feed water inlet nozzle H (large end of conical reducer) (DN350) per UG-37

●Internal ●Design

design pressure

temperature

P (MPa) (℃)

: 0.65 : 300

DOC. NO.: 2011-83-1-86811-342-0

●Material

PAGE

of the vessel wall

●Allowable ●Material

REV.: 0

stress of the vessel wall at design temperature

116

OF

: SA-516MGr.485 SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 3.5

R (mm)

: 903.5

t (mm)

: 8.5

Rno(mm)

: 177.8

Rn (mm)

: 170.17

●Inside

radius of shell corroded

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 7.63

●Finished

diameter of opening corroded

d (mm)

: 340.34

Weld leg (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

152

8-2-4-1 Size of opening Since ID is 1800mm, according to UG-36(b) (1), third of the vessel diameter is 600 mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 340.34 mm, so supplemental rules of 1-7 are not applied. 8-2-4-2 Wall thicknesses Required Shell

Required thickness of a seamless shell tr (E=1.0)

tr =

0.65 × 903.5 PR = = 4.34mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

0.65 × 177.8 PRno = = 0.93mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

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8-2-4-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV= 125.3/136= 0.9213 Strength reduction factor for nozzle fr2 fr2=Sn/SV = 125.3/136 = 0.9213 8-2-4-4 Size of weld required [UW-16(c), Fig.UW-16.1 Sketch (c)] 8-2-4-4(a) throat size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 12.0, 11.13 ) = 11.13 mm tc (mininum) = lesser of 1/4 in. or 0.7 tmin, 6.0 or 0.7× 11.13= 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm Cover weld satisfactory 8-2-4-4(b) Check for limits of reinforcement: 8-2-4-4(b) (1) Limit parallel to the vessel wall: larger of d = 340.34 mm or Rn + tn + t = 170.17 + 7.63 + 8.5 = 186.3 mm Use 340.34 mm 8-2-4-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×8.5 = 21.25 mm or 2.5tn+te = 2.5× 7.63 + 0 = 19.075 mm

Use 19.075 mm 8-2-4-5 Area of reinforcement required [UG-37] 8-2-4-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 340.34 × 4.34 × 1.0 + 2 × 7.63 × 4.34 × 1.0 × (1 − 0.9213) = 1477.1 + 5.3 = 1482.4 mm2 8-2-4-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 )

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= 340.34×(1.0×8.5-1×4.34)-2×7.63×(1.0×8.5-1.0×4.34)×(1-0.9213) = 1415.9 – 5.0 = 1410.9 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(8.5 + 7.63) × (1.0×8.5-1×4.34)-2×7.63× (1.0×8.5-1.0×4.34)×(1-0.9213) = 134.2 – 5.0 = 129.2 mm2 A1 = the larger of (A11,A12) = 1410.9 mm2 8-2-4-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (7.63 − 0.93) × 0.9213 × 8.5 = 262.3mm2 A22 = 5(tn − trn ) f r 2tn = 5 × (7.63 − 0.93) × 0.9213 × 7.63 = 235.4mm2 A2=the smaller of (A21, A22) = 235.4 mm2 8-2-4-5(d) Area available in welds A4 8-2-4-5(d)(1) Area available in outward weld A41 8-2-4-5(e)

A41= (leg)^2 × fr2 = 9.0 × 9.0 × 0.9213 = 74.6 Sq. mm Total area available

A1 +A2 +A41 = 1410.9 + 235.4 + 74.6 = 1720.9 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-2-4-6

Strength calculations for attachment welds are not required for this detail which conforms with Fig. UW-16.1 sketch (c) [see UW-15(b)]

8-2-5 For manhole nozzle A2 (DN450) ●Internal ●Design

per UG-37

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-516MGr.485

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 136

●Corrosion

allowance (designated by customer)

C (mm)

: 3.5

R (mm)

: 903.5

t (mm)

: 8.5

●Inside

radius of shell corroded

●Analysis

thickness of the vessel wall corroded

DOC. NO.: 2011-83-1-86811-342-0

●Outside

●Inside

REV.: 0

radius of the nozzle

radius of the nozzle corroded

PAGE

119

Rno(mm)

: 228.5

Rn (mm)

: 220

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 8.5

●Finished

diameter of opening corroded

d (mm)

: 440

Weld leg (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

OF

152

8-2-5-1 Size of opening Since ID is 1800mm, according to UG-36(b) (1), third of the vessel diameter is 600mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 440 mm, so supplemental rules of 1-7 are not applied. 8-2-5-2 Wall thicknesses Required Required thickness of a seamless shell tr (E=1.0)

Shell

tr =

0.65 × 903.5 PR = = 4.34mm SV E − 0.6 P 136 × 1 − 0.6 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

0.65 × 228.5 PRno = = 1.1mm S n E1 + 0.4 P 136 × 1 + 0.4 × 0.65

8-2-5-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV= 136/136= 1.0 Strength reduction factor for nozzle fr2 fr2=Sn/SV = 136/136 = 1.0 8-2-5-4 Size of weld required [UW-16(c),Fig.UW-16.1 Sketch (e)] 8-2-5-4(a) throat size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin

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152

tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 12.0 , 12.0 ) = 12.0 mm tc (mininum) = lesser of 1/4 in. or 0.7 tmin , 6.0 or 0.7×12.0 = 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 × 9.0 = 6.3 mm Cover weld satisfactory 8-2-5-4(b) Check for limits of reinforcement: 8-2-5-4(b) (1) Limit parallel to the vessel wall: larger of

d= 440 mm

or

Rn + tn + t = 220 + 8.5 + 8.5 = 237 mm

Use 440 mm 8-2-5-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t =2.5×8.5=21.25 mm

or

2.5tn+te = 2.5×8.5 + 0 = 21.25 mm

Use 21.25 mm 8-2-5-5 Area of reinforcement required [UG-37] 8-2-5-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 440 × 4.34 × 1.0 + 2 × 8.5 × 4.34 × 1.0 × (1 − 1.0) = 1909.6 mm2 8-2-5-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) =440×(1×8.5-1×4.34)-2×8.5 ×(1×8.5-1.0×4.34)×(1-1.0) = 1830.4 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(8.5+8.5) × (1×8.5-1×4.34)-2×8.5× (1×8.5-1.0×4.34)×(1-1.0) = 141.44 mm2 A1=the larger of (A11,A12)= 1830.4 mm2 8-2-5-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (8.5 − 1.1) × 1.0 × 8.5 = 314.5mm2

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A22 = 5(tn − trn ) f r 2tn = 5 × (8.5 − 1.1) × 1.0 × 8.5 = 314.5mm2 A2=the smaller of (A21, A22) = 314.5 mm2 8-2-5-5(d) Area available in welds A4 8-4-5(d)(1) Area available in outward weld A41 8-2-5-5(e)

A41= (leg)^2 × fr2 = 9.0 × 9.0 × 1.0 = 81.0 Sq. mm Total area available

A1 +A2 +A41 = 1830.4 + 314.5 + 81.0 = 2225.9 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-2-5-6

Strength calculations for attachment welds are not required for this detail which conforms with Fig. UW-16.1 sketch (e) [see UW-15(b)]

8-2-6 For thermometer nozzle V1 (DN20)

per UG-37

Since the welded nozzles nozzle V1 (DN20) is neither subject to rapid fluctuations in pressure nor larger than 60 mm, reinforcement of openings is not required. [UG-36 (c) (3)] 8-2-7 For pressure gauge nozzle W1 (DN15)

per UG-37

Since the welded nozzles nozzle W1 (DN15) is neither subject to rapid fluctuations in pressure nor larger than 60 mm, reinforcement of openings is not required. [UG-36 (c) (3)] 8-2-8 For pressure signal nozzle W3 (DN10)

per UG-37

Since the welded nozzles nozzle W3 (DN10) is neither subject to rapid fluctuations in pressure nor larger than 60 mm, reinforcement of openings is not required. [UG-36 (c) (3)] 8-2-9

For steam separator nozzle

●Internal ●Design

(DN350) per UG-37

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

stress of the nozzle wall at design temperature

: 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

●Allowable

: 0.65

: 136 : SA-106 Gr.B

Sn (MPa)

: 125.3

DOC. NO.: 2011-83-1-86811-342-0

●Corrosion

●Inside

allowance (designated by customer)

diameter of ellipsoidal head (corroded)

●Analysis

●Outside

●Inside

REV.: 0

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

PAGE

122

OF

C (mm)

: 3.5

D

: 1807

(mm)

t (mm)

: 6.94

Rno(mm)

: 177.8

Rn (mm)

: 170.17

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 7.63

●Finished

diameter of opening corroded

d (mm)

: 340.34

Weld leg (mm)

: 10.0

Weld leg (mm)

: 10.0

θ (deg)

: 0.0

F

: 1.0

●Leg

●Leg

length of outward nozzle fillet weld

length of inward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

152

8-2-9-1 Size of opening Since ID is 1800mm, according to UG-36(b) (1), third of the vessel diameter is 600mm, and doesn’t exceed 1000mm, therefore, 1000mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 340.34 mm, so supplemental rules of 1-7 are not applied. 8-2-9-2 Wall thicknesses Required ellipsoidal head

tr =

Required thickness of a seamless shell tr (E=1.0)

0.65 × 1807 PD = = 4.33mm 2S d E − 0.2 P 2 × 136 × 1.0 − 0.2 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

0.65 × 177.8 PRno = = 0.93mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-2-9-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1= Sn/SV=125.3/136=0.9213

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152

Strength reduction factor for nozzle fr2 fr2= Sn/SV =125.31/136=0.9213 8-2-9-4 Size of weld required [UW-16(c), Fig.UW-16.1 Sketch (i)] 8-2-9-4(a) throat size of weld required UW-16(b) t1 or t2 = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 10.44 , 11.13 ) = 10.44 mm t1 or t2 ≥ min.( 6 , 0.7×10.44 ) = 6.0 mm therefore throat must be at least 6.0 mm Weld 41, actual weld leg = 10.0 mm Weld 43, actual weld leg = 10.0 mm t1 or t2 = 0.7 × weld size = 0.7 ×10.0 = 7.0 mm (actual)

1 tmin = 13.05 mm 4 1 t1 + t2 = 7.0 + 7.0 = 14.0 ＞ 1 tmin = 13.05 mm 4

check t1 + t2 ≥ 1

Cover weld satisfactory 8-2-9-4(b) (1) Limit parallel to the vessel wall: larger of

d= 340.34 mm

or

Rn + tn + t = 170.17 + 7.63 + 6.94 = 184.74 mm

Use 340.34 mm 8-2-9-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t=2.5×6.94 =17.35 mm or 2.5tn+te = 2.5×7.63 + 0 = 19.075 mm

Use 17.35 mm 8-2-9-5 Area of reinforcement required [UG-37] 8-2-9-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 340.34 × 4.33 × 1.0 + 2 × 7.63 × 4.33 × 1.0 × (1 − 0.9213) = 1473.7 + 5.3 = 1479 mm2 8-2-9-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 )

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= 340.34×(1×6.94-1×4.33)-2×7.63×(1×6.94-1.0×4.33)×(1-0.9213) = 888.3-3.1 = 885.2 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(6.94+7.63) × (1×6.94-1×4.33)-2×7.63× (1×6.94-1.0×4.33)×(1-0.9213) = 76.1 – 3.1 = 73 mm2 A1=the larger of (A11,A12)= 885.2 mm2 8-2-9-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (7.63 − 0.93) × 0.9213 × 6.94 = 214.2mm2 A22 = 5(tn − trn ) f r 2tn = 5 × (7.63 − 0.93) × 0.9213 × 7.63 = 235.5mm2 A2=the smaller of (A21, A22) =214.2 mm2 8-2-9-5(d) Area available in nozzle projecting inward A3

Inner "h" limit:

min[h, 2.5t , 2.5tn]= [50, 17.35 , 19.075] = 17.35 mm

A31 = 5tt j f r 2 = 5 × 6.94 × 7.63 × 0.9213 = 243.9mm 2 A32 = 5t j t j f r 2 = 5 × 7.63 × 7.63 × 0.9213 = 268.1mm 2 A33 = 5ht j f r 2 = 5 × 17.35 × 7.63 × 0.9213 = 609.8mm 2 A3= the smaller of (A31, A32, A33 ) = 243.9 mm2 8-2-9-5(e) Area available in fillet welds A4 8-2-9-5(e)(1) Area available in outward fillet weld A41 A41= (leg)^2 × fr2 = 10.0 × 10.0 × 0.9213 = 92.1 Sq. mm 8-2-9-5(e)(2) Area available in inward fillet weld A43 A43= (leg)^2 × fr2 = 10.0 × 10.0 × 0.9213 = 92.1 Sq. mm 8-2-9-5(f) Total area available A1 +A2 +A3 +A41 +A43 = 885.2 + 214.2 + 243.9 + 92.1 + 92.1 = 1528.1 Sq. mm This is greater than the required area so is a reinforcing element is not needed. 8-2-9-6 Check the welds per UW-16 and UW-16.1 (i) 8-2-9-6-1 Check Load to be carried by welds [Fig.UG-41.1 Sketch (a)] 8-2-9-6-1 (a) Per UG-41 (b) (1) W1-1 = (A2 + A5 + A41 + A42) × Sv = ( 214.2 + 0 + 92.1 + 0) × 136 = 41656.8 N

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152

W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = ( 214.2+ 243.9 + 92.1 + 92.1 +2 × 7.63 × 6.94 × 0.9213)× 136 = 100622.3 N 8-2-9-6-1 (b) Per UG-41 (b) (2) W= [A - A1 + 2tn fr1 (E1t - Ftr)]Sv = [1479 – 885.2 + 2× 7.63× 0.9213× (1.0 × 6.94 - 1.0 × 4.33)] *136 = 85747 N Since W is smaller than W2-2, W may be used in place of W2-2 for comparing weld capacity to weld load. 8-2-9-6-2 Unit Stresses per UG-45(c) and UW-15 (c) 8-2-9-6-2 (a) Fillet weld shear = 0.49×125.3 = 61.4 Mpa 8-2-9-6-2 (b) Nozzle wall shear = 0.7×125.3 = 87.71 Mpa 8-2-9-6-3 Strength of connection elements 8-2-9-6-3 (a) Fillet weld shear = π/2 × nozzle O.D. × weld leg × 61.4 = 1.57 × 355.6 × 10.0 ×61.4 = 342791.3 N 8-2-9-6-3 (b) Nozzle wall shear = π/2 × mean nozzle diameter × tn × 87.71 = 1.57×344.47×7.63 × 87.71 = 361930 N 8-2-9-6-4 Check Strength paths Path 1-1 = 342791.3 + 361930 = 704721.3 N Path 2-2 = 342791.3 + 342791.23 = 685582.6 N All paths are stronger than the required strength of W of 85747 N [see UG-41 (b) (2)] Weld Strength Paths Are Adequate. 8-2-10 For annectent nozzle of tank and tower (DN800) ●Internal ●Design

design pressure

temperature

●Material

P (MPa) (℃)

of the vessel wall

●Allowable ●Material

per UG-37

stress of the vessel wall at design temperature

of the nozzle wall

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

: 136 : SA-516MGr.485

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OF

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 136

●Corrosion

allowance (designated by customer)

C (mm)

: 3.5

D

: 1807

●Inside

diameter of ellipsoidal head (corroded)

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

(mm)

t (mm)

: 6.94

Rno(mm)

: 406.4

Rn (mm)

: 393.9

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 12.5

●Finished

diameter of opening corroded

d (mm)

: 787.8

tnc (mm)

: 9.0

θ (deg)

: 0.0

F

: 1.0

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

●Material

of the reinforcing pad

●Allowable

●Outside

factor

stress of reinforcing pad at design temperature

diameter of reinforcing pad

●Nominal

thickness of reinforcing pad

152

: SA-516MGr.485 Sp (MPa)

: 136

Dp (mm)

: 1200

te

(mm)

12

8-2-10-1 Size of opening Since ID is 1800 mm, according to UG-36(b) (1), third of the vessel diameter is 600 mm, and doesn’t exceed 1000 mm, therefore, 1000 mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 787.8 mm, so supplemental rules of 1-7 are not applied. 8-2-10-2 Wall thicknesses Required ellipsoidal head

tr =

Required thickness of a seamless shell tr (E=1.0)

0.65 × 1807 PD = = 4.33mm 2S d E − 0.2 P 2 × 136 × 1.0 − 0.2 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

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REV.: 0

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152

0.65 × 406.4 PRno = = 1.94mm S n E1 + 0.4 P 136 × 1 + 0.4 × 0.65

8-2-10-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1= Sn/SV= 136/136 = 1.0 Strength reduction factor for nozzle fr2 fr2= Sn/SV = 136/136 = 1.0 Strength reduction factor for all parts fr3 fr3= (less of Sn or Sp)/SV = 136/136 = 1.0 Strength reduction factor for reinforcing pad fr4 fr4= Sp/SV = 136/136 = 1.0 8-2-10-4 Size of weld required [UW-16(d),Fig.UW-16.1 Sketch (q)] 8-1-1-4(a) Inner (reinforcing pad) fillet weld size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 10.44 , 16.0 ) = 10.44 mm tc ( minimum ) = lesser of 1/4 in. or 0.7 tmin , 6.0 or 0.7× 10.44 = 6.0 mm Weld 41, actual weld leg = 9.0 mm tc (actual) = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm 8-2-10-4(b) Outer (reinforcing pad) fillet weld: Throat = 1/2 tmin= 0.5 ×10.44 = 5.22 mm ( minimum throat required ) Throat = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm (actual) 8-2-10-4(c) Upper groove weld: tw = 0.7 tmin = 0.7 ×10.44 = 7.308 mm ( required ) tw = 10.44 mm (actual) The weld size used is satisfactory. 8-2-10-4(d) Check for limits of reinforcement:

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8-2-10-4(d) (1) Limit parallel to the vessel wall: larger of d = 787.8 mm

or Rn + tn + t = 393.9 + 12.5 + 6.94 = 413.34 mm

Use 787.8 mm 8-2-10-4(d) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×6.94 = 17.35 mm or 2.5tn+te = 2.5×12.5 + 12 = 43.25 mm

Use 17.35 mm 8-2-10-5 Area of reinforcement required [UG-37] 8-2-10-5(a)

Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 787.8 × 4.33 × 1.0 + 2 × 12.5 × 4.33 × 1.0 × (1 − 1.0) = 3411.2 + 0 = 3411.2 mm2 8-2-10-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 787.8×(1.0×6.94-1×4.33)-2×12.5×(1.0×6.94-1.0×4.33)×(1-1.0) = 2056.1 – 0 = 2056.1 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(6.94 + 12.5) × (1.0×6.94-1×4.33)-2×12.5× (1.0×6.94-1.0×4.33)×(1-1.0) = 101.5 – 0 = 101.5 mm2 A1= the larger of (A11,A12)= 2056.1 mm2 8-2-10-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (12.5 − 1.94) × 1.0 × 6.94 = 366.4mm2 A22 = 2(tn − trn )(2.5tn + te ) f r 2 = 2 × (12.5 − 1.94) × (2.5 × 12.5 + 12) × 1.0 = 913.4mm2 A2=the smaller of (A21, A22) = 366.4 mm2 8-2-10-5(d) Area available in welds A4 8-2-10-5(d)(1) Area available in outward weld A41 A41= (leg)^2 × fr3 = 9.0 × 9.0 × 1.0 = 81.0 Sq. mm A42= (leg)^2 × fr4 = 9.0 × 9.0 × 1.0 = 81 Sq. mm 8-2-10-5(e)

Area provided by:

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A1 +A2 +A41 +A42 = 2056.1 + 366.4 + 81 +81 = 2584.5 Sq. mm 8-2-10-5(f)

Area available in reinforcing pad: A5 = (Dp-d-2tn) te fr4 = (1200-787.8-2×12.5)×12×1.0 = 4646.4 Sq. mm

8-2-10-5(g) Total area available A1 +A2 +A41 + A42 + A5 = 2584.5 + 4646.4 = 7230.9 Sq. mm This is greater than the required reinforcing area of 3411.2 sq. mm; therefore, the opening is adequately reinforced. 8-2-10-6 Check the welds per UW-16 and UW-16.1 (q) 8-2-10-6-1 Check Load to be carried by welds [Fig.UG-41.1 Sketch (a)] 8-2-10-6-1 (a) Per UG-41 (b) (1) W1-1 = (A2 + A5 + A41 + A42) × Sv = (366.4 + 4646.4 + 81 +81 ) × 136 = 703772.8 N W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (366.4+ 0 + 81 + 0 + 2 × 6.94 ×12.5 × 1.0 )× 136 = 84442.4 N W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) Sv = (366.4+ 0 + 4646.4 + 81 + 81+ 0 + 2 × 6.94 ×12.5 × 1.0 )× 136 = 727368.8 N 8-2-10-6-1 (b) Per UG-41 (b) (2) W= [A - A1 + 2tn fr1 (E1t – F tr )]Sv = [3411.2 –2056.1 + 2× 12.5 × 1.0× (1.0 × 6.94 - 1.00× 4.33)] × 136 = 193167.6 N Since W is smaller than W1-1 and W3-3, W may be used in place of W1-1 and W3-3 for comparing weld capacity to weld load. 8-2-10-6-2 Unit Stresses per UG-45(c) and UW-15 (c) 8-2-10-6-2 (a) Fillet weld shear = 0.49×136 = 66.64 Mpa 8-2-10-6-2 (b) Groove weld tension = 0.74×136 = 100.64 Mpa 8-2-10-6-2 (c) Groove weld shear = 0.6×136 = 81.6 Mpa 8-2-10-6-2 (d) Nozzle wall shear

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Path 1-1 = 790963.5 + 696860.9 = 1487824.4 N ＞W1-1 = 626810.4 N

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152

= 0.7×136 = 95.2 Mpa 8-2-10-6-3 Strength of connection elements 8-2-10-6-3 (a) Upper fillet or cover weld = π/2 × nozzle O.D. × weld leg × 66.64 = 1.57 × 508 ×9.0 × 66.64 = 478344.6 N 8-2-10-6-3 (b) Nozzle wall shear = π/2 × mean nozzle diameter × tn × 95.2 = 1.57 × 496 × 9.4 × 95.2 = 696860.9 N 8-2-10-6-3 (c) Lower groove weld tension = π/2 × nozzle O.D. × weld leg × 100.64 = 1.57 × 508 ×9.0 × 100.64 = 722397.9 N 8-2-10-6-3 (d) Outer (reinforcing element) fillet weld = π/2 × reinforcing pad O.D. × weld leg × 66.64 = 1.57 × 840 ×9.0 ×66.64 = 790963.5 N 8-1-1-6-3 (e) Upper groove weld tension = π/2 × nozzle O.D. × weld leg × 100.64 = 1.57 × 508 × 9.0 × 100.64 = 722397.9 N 8-2-10-6-4 Check Strength paths

Path 2-2 = 478344.6 + 722397.9 + 722397.9 = 1923140.4 N＞W2-2 = 102913.4 N Path 3-3 = 790963.5 + 722397.9 = 1513361.4 N＞W3-3 = 655753.3 N

OK

OK

Also paths are stronger than the required strength of W of 151513.2 N [see UG-41 (b) (2)] thus, the Weld Strength Paths Are Adequate. 8-2-11

For safety valve nozzle B (DN150) per UG-37

●Internal ●Design

design pressure

temperature

●Material

(℃)

of the vessel wall

●Allowable ●Material

P (MPa)

stress of the vessel wall at design temperature

: 0.65 : 300 : SA-516MGr.485

SV (MPa)

of the nozzle wall

: 136 : SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 3.5

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●Inside

diameter of ellipsoidal head (corroded)

●Analysis

●Outside

●Inside

REV.: 0

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

PAGE

D

131

(mm)

OF

: 1807

t (mm)

: 6.94

Rno(mm)

: 84.15

Rn (mm)

: 76.68

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 7.47

●Finished

diameter of opening corroded

d (mm)

: 153.36

tnc (mm)

: 9.0

θ (deg)

: 90

F

: 0.5

●Leg

length of outward nozzle fillet weld

●Angle

of plane with longitudinal axis

●Correction

factor

152

8-2-11-1 Size of opening Since ID is 1800 mm, according to UG-36(b) (1), third of the vessel diameter is 600 mm, and doesn’t exceed 1000 mm, therefore, 1000 mm is maximum limit without considering supplemental rules of 1-7. Now, the diameter of opening is 153.36 mm, so supplemental rules of 1-7 are not applied. 8-2-11-2 Wall thicknesses Required ellipsoidal head

tr =

Required thickness of a seamless shell tr (E=1.0)

0.65 × 1807 PD = = 4.33mm 2S d E − 0.2 P 2 × 136 × 1.0 − 0.2 × 0.65

Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

0.65 × 84.15 PRno = = 0.44mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

8-2-11-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1= Sn/SV= 125.3/136 = 0.9213 Strength reduction factor for nozzle fr2 fr2= Sn/SV = 125.3/136 = 0.9213 8-2-11-4 Size of weld required [UW-16(b), Fig.UW-16.1 Sketch (e)]

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8-2-11-4(a) throat size of weld required UW-16(b) tc = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 10.44 , 10.97 ) = 10.44 mm tc (mininum) = lesser of 1/4 in. or 0.7 tmin , 6.0 or 0.7×10.44 = 6.0 mm Weld 41, actual weld leg = 9.0 mm Weld throat = 0.7 × weld size = 0.7 ×9.0 = 6.3 mm ＞6.0 mm The weld size is satisfactory. 8-2-11-4 (b) In plane 90 deg to longitudinal axis : 8-2-11-4 (b) (1) calculate the opening chord length at mid-surface of the required shell thickness as follows: Rm = R+tr/2= 903.5+4.33/2 = 905.665 mm L= 500 mm

500 + 76.68 L + Rn ) = cos-1( ) = 50.5 deg Rm 905.665 500 − 76.68 L − Rn α2= cos-1( ) = cos-1( ) = 62.1 deg Rm 905.665

α1= cos-1(

α=α2-α1= 62.1- 50.5 = 11.6 deg d = 2Rm

1 − cos 2 (α/ 2) =2×905.665× 1 − cos 2 (11.6 / 2) =183.1 mm

Per UG-37(b) and Fig.UG-37, F=0.5 8-2-11-4(b) (2) Check for limits of reinforcement: 8-2-11-4 (b) (2-1) Limit parallel to the vessel wall (circumferentially): larger of

dc = 183.1 mm

or

Rnc + tn + t = 91.55 + 7.47 + 6.94 = 105.96 mm

Use 183.1 mm 8-2-11-4 (b) (2-2) Limit normal to the vessel wall: smaller of

2.5t = 2.5×6.94 = 17.35 mm or 2.5tn+te = 2.5×7.47 + 0 = 18.675 mm

Use 17.35 mm 8-2-11-5 Area of reinforcement required in plane 90 deg to longitudinal axis

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A = dtr F + 2tntr F (1 − f r1 ) = 183.1 × 4.33 × 0.5 + 2 × 7.47 × 4.33 × 0.5 × (1 − 0.9213) = 396.5 + 2.6 = 399.1 mm2 8-2-11-6 Area of reinforcement available in plane 90 deg to longitudinal axis 8-2-11-6 (a) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 183.1×(1×6.94-0.5×4.33)-2×7.47×(1×6.94-0.5×4.33)×(1-0.9213) = 477.9 – 3.1 = 474.8 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(6.94 + 7.47) × (1×6.94-0.5×4.33)-2×7.47× (1×6.94-0.5×4.33)×(1-0.9213) = 137.6 – 3.1 = 134.5 mm2 A1= the larger of (A11,A12)= 474.8 mm2 8-2-11-6 (b) Area available in nozzle A2 α3= cos-1(

500 − 76.68 L − Rn ) = cos-1( ) = 62.3 deg R+t 903.5 + 6.94

A2 = the smaller of the following By observation, A2 on the upper side of the nozzle is smaller than A2 on the lower side of the nozzle. In accordance with UG-37(b), not less than half the required reinforcement shall be on each side of the opening. Therefore, A2 on the lower side shall not be greater than A2 on the upper side.

A21 = 5(tn − trn ) f r 2t / sin(α3 ) = 5 × (7.47 − 0.44 ) × 0.9213 × 6.94 / sin 62.3 = 253.8mm 2 A22 = 5(tn − trn )tn f r 2 / sin(α3 ) = 5 × (7.47 − 0.44 ) × 7.47 × 0.9213 / sin 62.3 = 273.2mm2 A2 = the smaller of (A21, A22) = 253.8 mm2 8-2-11-6(c) Area available in outward nozzle weld: Since the welds vary from a fillet to a butt-type weld, and A41 will not be considered. 8-2-11-6 (d) Area provided by A1 + A2 = 474.8 + 253.8 = 728.6 Sq. mm ＞ A= 399.1 Sq. mm This is greater than the required reinforcing area of 399.1 sq. mm. Therefore, the opening is adequately reinforced in the plane considered. 8-2-11-7 Since the plane under consideration requires only 50% (F=0.5) of the required

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reinforcement in the plane parallel to the longitudinal shell axis, the opening may not be adequately reinforced in the other planes. A check for reinforcement in plane parallel to the longitudinal shell axis is needed. d = 153.36 mm

F = 1.0

8-2-11-7 (a) Area of reinforcement required

A = dtr F + 2tntr F (1 − f r1 ) = 153.36 ×4.33 ×1.0 + 2 ×7.47×4.33×1.0 × (1-0.9213) = 664.1 + 5.1 = 669.2 mm2 8-2-11-7 (b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 153.36×(1×6.94-1×4.33)-2×7.47 ×(1×6.94-1.0×4.33)×(1-0.9213) = 400.3 – 3.1 = 397.2 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2×(6.94+7.47) × (1×6.94-1×4.33)-2×7.47× (1×6.94-1.0×4.33)×(1-0.9213) = 75.2 – 3.1 = 72.1 mm2 A1=the larger of (A11,A12) = 397.2 mm2 8-2-11-7 (c) Area available in nozzle A2

A21 = 5(tn − trn ) f r 2t = 5 × (7.47 − 0.44 ) × 0.9213 × 6.94 = 224.7mm2 A22 = 5(tn − trn ) f r 2tn = 5 × (7.47 − 0.44 ) × 0.9213 × 7.47 = 241.9mm2 A2 = the smaller of (A21, A22) =224.7 mm2 8-2-11-7 (d) Area available in outward nozzle weld A41: A41= (leg)^2 × fr2 = 9.0 × 9.0 × 0.9213 = 74.6 Sq. mm 8-2-11-7 (e) Total area available A1 +A2 +A41 = 397.2 + 224.7 + 74.6 = 696.5 mm This is greater than the required reinforcing area of 669.2 Sq. mm; therefore, opening is adequately reinforced. 8-2-12

For exhaust nozzle G (DN80)

●Internal ●Design

design pressure

temperature

●Material

of the vessel wall (cover)

per UG-39 P (MPa) (℃)

: 0.65 : 300 : SA-105M

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PAGE

SV (MPa)

135

OF

152

: 129.3

temperature ●Material

of the nozzle wall

: SA-106 Gr.B

●Allowable

stress of the nozzle wall at design temperature

Sn (MPa)

: 125.3

●Corrosion

allowance (designated by customer)

C (mm)

: 3.5

dG ( mm )

: 425.3

t (mm)

: 31.9

Rno(mm)

: 44.45

Rn (mm)

: 36.82

●

Diameter, measured as indicated in Fig. UG-34

●Analysis

●Outside

●Inside

thickness of the vessel wall corroded

radius of the nozzle

radius of the nozzle corroded

●Analysis

thickness of nozzle wall corroded

tn (mm)

: 7.63

●Finished

diameter of opening corroded

d (mm)

: 73.64

●Leg

length of outward nozzle fillet weld

Weld leg (mm)

: 10.0

●Leg

length of inward nozzle fillet weld

Weld leg (mm)

: 10.0

θ (deg)

: 0.0

F

: 1.0

●Angle

of plane with longitudinal axis

●Correction

factor

8-2-12-1 Size of opening Since ID is 350mm, according to UG-36(b) (1), one half the vessel diameter is 175 mm, and doesn’t exceed 500mm, therefore, 500mm is maximum limit without considering supplemental rules of 1-7.Now, the diameter of opening is 73.64 mm, so supplemental rules of 1-7 are not applied. 8-2-12-2 Wall thicknesses Required cover

Required thickness of cover tr (E=1.0)

ts = 26.9 mm (calculated by 5-2-15) Nozzle Minimum nozzle thickness due to pressure trn (E1=1.0)

trn =

0.65 × 44.45 PRno = = 0.24mm S n E1 + 0.4 P 125.3 × 1 + 0.4 × 0.65

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8-2-12-3 Material Strength Reduction Factor Strength reduction factor for nozzle fr1 fr1=Sn/SV= 125.3/129.3 = 0.9691 Strength reduction factor for nozzle fr2 fr2=Sn/SV = 125.3/129.3 = 0.9691 8-2-12-4 Size of weld required [UW-16(c), Fig.UW-16.1 Sketch (i)] t1 or t2 = not less than the smaller of 1/4 in. or 0.7 tmin tmin =lesser of 3/4 in. or the thickness less corrosion allowance of the thinner part joined. = min.( 19 , 33.4 , 11.13 ) = 11.13 mm t1 or t2 ≥ min.( 6 , 0.7×11.13 ) = 6.0 mm therefore throat must be at least 6.0 mm Weld 41, actual weld leg = 10.0 mm Weld 43, actual weld leg = 10.0 mm t1 or t2 = 0.7 × weld size = 0.7 ×10.0 = 7.0 mm (actual)

1 tmin = 13.9125 mm 4 1 t1 + t2 = 7.0 + 7.0 = 14.0 ＞ 1 tmin = 13.9125 mm 4

check t1 + t2 ≥ 1

Cover weld satisfactory 8-2-12-4(b) Check for limits of reinforcement: 8-2-12-4(b) (1) Limit parallel to the vessel wall: larger of d = 73.64 mm or Rn + tn + t = 36.82 + 7.63 + 31.9 = 76.35 mm Use 76.35 mm 8-2-12-4(b) (2 ) Limit normal to the vessel wall: smaller of

2.5t = 2.5×31.9 = 79.75 mm or 2.5tn+te = 2.5×7.63 + 0 = 19.075 mm

Use 19.075 mm 8-2-12-5 Area of reinforcement required [UG-37] 8-2-12-5(a)

Area of reinforcement required

A = 0.5dtr + tntr (1 − f r1 ) = 0.5 × 76.35 × 26.9 + 26.9 × 7.63 × (1 − 0.9691)

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= 1027 + 6.4 = 1033.4 mm2 8-2-12-5(b) Area available in shell A1

A11 = d [E1t − Ftr ] − 2tn [E1t − Ftr ](1 − f r1 ) = 76.35×(1.0×31.9-1×26.9)-2×7.63×(1.0×31.9-1.0×26.9)×(1-0.9691) = 382.5 – 2.4 = 380.1 mm2

A12 = 2(t + tn )(E1t − Ftr ) − 2tn (E1t − Ftr )(1 − f r1 ) =2(31.9 + 7.63) × (1.0×31.9-1×26.9)-2×7.63× (1.0×31.9-1.0×26.9)×(1-0.9691) = 395.3 – 2.4 = 392.9 mm2 A1 = the larger of (A11,A12) = 392.9 mm2 8-2-12-5(c)

Area available in nozzle projecting outward A2

A21 = 5(tn − trn ) f r 2t = 5 × (7.63 − 0.24 ) × 0.9691 × 31.9 = 1142.3mm2 A22 = 5(tn − trn ) f r 2tn = 5 × (7.63 − 0.24 ) × 0.9691 × 7.63 = 273.2mm2 A2=the smaller of (A21, A22) = 273.2 mm2 8-2-12-5(d) Area available in nozzle projecting inward A3

Inner "h" limit:

min[h, 2.5t , 2.5tn]= [400, 79.75 , 19.075] = 19.075 mm

A31 = 5tt j f r 2 = 5 × 31.9 × 7.63 × 0.9691 = 1179.4mm 2 A32 = 5t j t j f r 2 = 5 × 7.63 × 7.63 × 0.9691 = 282.1mm 2 A33 = 5ht j f r 2 = 5 × 19.075 × 7.63 × 0.9691 = 705.2mm 2 A3= the smaller of (A31, A32, A33 ) = 282.1 mm2 8-2-12-5(e) Area available in fillet welds A4 8-2-12-5(e)(1) Area available in outward fillet weld A41 A41= (leg)^2 × fr2 = 10.0 × 10.0 × 0.9691 = 96.9 Sq. mm 8-2-12-5(e)(2) Area available in inward fillet weld A43 8-2-12-5(f)

A43= (leg)^2 × fr2 = 10.0 × 10.0 × 0.9691 = 96.9 Sq. mm Total area available

A1 +A2 +A3 +A41 +A43 = 392.9 + 273.2 + 282.1 + 96.9 + 96.9 = 1142 Sq. mm This is greater than the req uired area of 1033.4 Sq. mm so is a reinforcing element is not needed. 8-2-12-6 Check the welds per UW-16 and UW-16.1 (i) 8-2-12-6-1 Check Load to be carried by welds [Fig.UG-41.1 Sketch (a)]

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8-2-12-6-1 (a) Per UG-41 (b) (1) W1-1 = (A2 + A5 + A41 + A42) × Sv = ( 273.2 + 0 + 96.9 + 0) × 129.3 = 47853.9 N W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = ( 273.2+ 282.1 + 96.9 + 96.9 +2 × 7.63 × 31.9 × 0.9691)× 129.3 = 157856.2 N 8-2-12-6-1 (b) Per UG-41 (b) (2) W= [A - A1 + 2tn fr1 (E1t - Ftr)]Sv = [1033.4 – 392.9 + 2× 7.63× 0.9691× (1.0 × 31.9 - 1.0 × 26.9)] *129.3 = 92377.4 N Since W is smaller than W2-2, W may be used in place of W2-2 for comparing weld capacity to weld load. 8-2-12-6-2 Unit Stresses per UG-45(c) and UW-15 (c) 8-2-12-6-2 (a) Fillet weld shear = 0.49×125.3 = 61.4 Mpa 8-2-12-6-2 (b) Nozzle wall shear = 0.7×125.3 = 87.71 Mpa 8-2-12-6-3 Strength of connection elements 8-2-12-6-3 (a) Fillet weld shear = π/2 × nozzle O.D. × weld leg × 61.4 = 1.57 × 88.9 × 10.0 ×61.4 = 85697.8 N 8-2-12-6-3 (b) Nozzle wall shear = π/2 × mean nozzle diameter × tn × 87.71 = 1.57×77.77×7.63× 87.71 = 81712 N 8-2-12-6-4 Check Strength paths Path 1-1 = 85697.8 + 81712 = 167409.8 N Path 2-2 = 85697.8 + 85697.8 = 171395.6 N All paths are stronger than the required strength of W of 92377.4 N [see UG-41 (b) (2)] Weld Strength Paths Are Adequate.

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9. Pressure – temperature rating for flange and flange cover (ASME B16.5 TABLE 2-1.1) Part: nozzle A1 A2.D1-2.G..T1-2.U1-4.X1-2.Z1-2 Flange rating: class 150 pressure – temperature rating Design condition Flange material: SA-105M Design pressure: 0.65 MPa Design temperature: 300℃ Pressure – temperature rating of table 2-1.1 Material group

1.1

Materials

Carbon Steel

Temp (℃)

200

250

300

Pressure (bar)

13.8

12.1

10.2

Therefore, Allowance Pressure:1.02MPa (Design pressure) 0.65 MPa < 1.02 MPa …… OK.

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CALCULATION OF LIFTING LUGS OF TOWER ( Appendix A of HG/T21574-2008)

Equipment empty mass: Lifting plate of material:

m= 4420 kg SA-516MGr.485

Backing strip of material:

SA-516MGr.485

Lifting plate of thickness:

S=16 mm

Backing strip of thickness:

S= 10 mm

Allowable tensile stress:

SA=136 MPa

Allowable shearing stress:

τA = 95.2 MPa

Fillet welded joint factor:

φa= 0.7

Dynamic load factor:

k= 1.65

Lifting vertical load FV=0.5×4420×9.81×1.65= 35773 N Lifting transverse load FH = FV×tan30°= 35773×tan30°= 20654 N Lifting sling load FL = FV/cos30°= 35773/cos30°= 41308 N Lifting radial bend of moment M = FH×L = 20654×80 = 1652320 N·mm Lifting sling max. tensile stress SL= FL/[S(2R-D)]= 41308/[16(2×60-50)]= 36.9 MPa SL＜SA, It is safe. Lifting sling max. shearing stress

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τL= SL= 36.9 MPa τL＜τA , It is safe. Area of fillet weld: A = 2 (L×tan15°+R) S = 2× (80×tan15°+60) ×16 = 2606 mm2 Lifting plate weld tensile stress: St= Fv/A = 35773/2606 = 13.8 MPa Lifting plate weld shearing stress τt= FH/A = 20654/2606 = 8.0 MPa Lifting plate weld bend stress Sab′=6M/S[2(Ltan15°+R)]2 = 6×1652320/{16[2×(80×tan15°+60)] 2}= 23.4 MPa Compound stress Sab=

( St + S ab ′) 2 + 4τ t2 = (13.8 + 23.4) 2 + 4 × 8.02 = 40.5MPa

Lifting plate weld allowable stress [τ]=0.7×SA= 95.2 MPa Sab＜[τ] ,It is safe.

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11. check for strength and stability of the horizontal vessel with supplemental loading

δ

(according to Appendix A of JB/T4731-2005)

11-1 Calculation for Support Reaction Force (due to Uniform Loading) (1) Mass of Cylindrical Shell(between Two Tangents) m1=π(Di+δn)Lδnγe = 10311.5 ㎏ (2) Mass of Head(Curved Surface Portion) m2= 937.911 kg (3) Mass of Attachments (including platform) (4) Volume of Head Vh= 2.87351e+09 (5) Volume of Vessel V = 6.28888e+10

m3= 8000 ㎏

mm3 mm3

(6) Mass of Vesse Filled with Liquid: Under Operating Condition, m4=Vγ= 51460.1 ㎏ Under Hydrostatic Test Condition,

m4′=VγT= 62888.8 ㎏

(7) Total Mass: Under Operating Condition: m = m1 + m2 + m3 + m4 + m5 = 71647.4 ㎏ Under Hydrostatic Test Condition: m′= m1 + m2 + m3 + m4′+ m5 = 83076.1 ㎏ (8) Uniform Load Under Operating Condition:

q=mg/(L+4hi/3)= 68.832 N/mm

Under Hydrostatic Test Condition: q′=m′g/(L+4hi/3)= 79.8116 N/mm (9) Support Reaction Force due to Uniform Loading Under Operating Condition:

F′=mg/2= 351430.5 N

Under Hydrostatic Test Condition

F″= m′g/2 =407488.3 N

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(10) Shearing Force at Support due to Uniform Loading Under Operating Condition, V=F′((L-2A)/(L+4hi/3)= 240862.9 N Under Hydrostatic Test Condition, V′=F″((L-2A)/(L+4hi/3)= 279283.8 N 11-2 Calculations for Radial Load and External Moment due to Accessory Equipments (1) Structure size: L= 7000mm; l1 = 3687 mm; H0 = 250 mm; a = 3500 mm; b = 3500 mm Ri = 1400 mm ; δn = 16 mm ; di = 1800 mm; Si = 12mm; h = 1843.5 mm (2) Radial Load Mass of Cylindrical Shell and Head m1a′ + m2a′ = 1836 ㎏ Mass of Internals,Attachments and Insulation

m3a′ + m5a′ = 3000 ㎏

Mass of Filled Water Under Operating Condition:

m4a′ = 6510 ㎏

Under Hydrostatic Testing Condition:

m4a″ = 7160 ㎏

Mass of Attachment Under Operating Condition, m a′= m1a′ + m2a′ + m3a′ + m4a′ + m5a′ = 11346 ㎏ under Hydrostatic Testing Condition m a″ = m1a′ + m2a′ + m3a′+ m4a″+ m5a′ = 11996 ㎏ Weight Force Acted by Attachment Under Operating Condition,

W′= ma′g = 111304.26 N

Under Hydrostatic Testing Condition,

W”= ma″g = 117680.76 N

W = max(W’, W”) =117680.76 N (3) Calculation Condition without Seismic Load (3)-1 Support Reaction(Concentrated Load) Due to Weight Force

FI=(b/l)W′= 55652.13 N

FII=(a/l)W′= 55652.13 N

FI″=(b/l)W = 58840.38 N

FII″=(a/l)W = 58840.38 N

Combination of Support Reaction Combined Support Force

FIo=F′+ FI = 407082.63 N FIIo=F′+ FII = 407082.63 N FIo′=F″+ FI″= 466328.68 N

FIIo′=F″+ FII″= 466328.68 N

FI=(b/l)W′= 55652.13 N

FII=(a/l)W′= 55652.13 N

Maximum Shearing Force at Support

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2F 2 2 × 351430.5 2 ( hi + A) = 407082.63 − ( × 700 + 1140) 4 4 3 L + hi 9280 + × 700 3 3 3

°

νA = FⅠ −

= 296515.1 N °

νA = FⅡ −

2F 2 2 × 351430.5 2 ( hi + A) = 407082.63 − ( × 700 + 1140) 4 4 L + hi 3 9280 + × 700 3 3 3

= 296515.1 N (3)-2 Combined Moment due to Uniform and Concentrated Load Bending Moment due to Uniform Load At Acting Point K of Concentrated Load Under Operating Condition

M Kq = q[

Ra2 − hi2 2 A2 al a − hi A − + (1 − )] l 4 3 2 2

3500 11402 3500 × 7000 14082 − 7002 2 = 68.832 × [ − × 700 × 1140 − + )] (1 − 7000 2 2 4 3 = 68.832 × [373116 − 532000 − 649800 + 6125000] =3.65933×108 N.mm Under Hydrostatic Testing Condition:

M ′ Kq = q′ [

Ra2 − hi2 2 A2 al a − hi A − + (1 − )] l 4 3 2 2

3500 11402 3500 × 7000 14082 − 7002 2 = 79.8116 × [ − × 700 × 1140 − + )] (1 − 7000 2 2 4 3

= 79.8116 × [373116 − 532000 − 649800 + 6125000] =4.24304×108 N.mm At Support Under Operating Condition

M 2 = − F ′ A[1 −

1−

A Ra2 − hi2 + 2 AL ] L 4hi 1+ 3L

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1140 14082 − 7002 + 9280 2 × 1140 × 9280 ] = − 351430.5 × 1140 × [1 − 4 × 700 1+ 3 × 9280 1 − 0.122845 + 0.0705377 = -400630770×(1)=-5.565214×107 N.mm 1 + 0.100575 1−

Under Hydrostatic Testing condition

A Ra2 − hi2 + 2 AL ] L M T 2 = − F ″′ A[1 − 4hi 1+ 3L 1140 14082 − 7002 1− + 9280 2 × 1140 × 9280 ] = − 407488.3 × 1140 × [1 − 4 × 700 1+ 3 × 9280 1 − 0.122845 + 0.0705377 = -464536662×(1)=-6.452939×107 N.mm 1 + 0.100575 1−

(4) Bending Moment due to Concentrated Load (4)-1 due to Radial Force at Point K Under Operating Condition:

ab ' 3500 × 3500 W = × 111304.26 = 1.46926 × 108 N L 9280

M k' =

Under Hydrostatic Testing Condition

ab ″ 3500 × 3500 W = × 117680.76 = 1.553437 × 108 N L 9280

M k″ =

(4)-2 Combined Bending Moment At Acting Point K of Concentreated Load Under Operating Condition: MK = MKq + Mk′= 3.65933×108 + 1.46926×108 = 5.12859×108 N.mm Under Hydrostatic Testing Condition: MKT = M′Kq + Mk″= 4.24304×108 + 1.553437×108 = 5.796477×108 N.mm (5) Calculation for Axial Stress of Cylindrical Shell (5)-1 At Acting Point K of Concectrated Load, di = 812.8 mm, K10=0.785

Di = 2800 mm arcsinβ= 0.290285714, β= 16.875

K11=0.89

under Operating Condition

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pc Ra Mk 0.65 × 1408 5.12859 × 108 − − = 2 2δe 2 × 13.4 0.785 ×π× 14082 × 13.4 K10πRa δe

= 34.15 - 7.83 = 26.32 MPa At Acting Point K of Concectrated Load underHydrostatic Testing Condition (Vessel under Internal Pressure) After water filling, if PT = 0

σ1kT = −

5.796477 × 108 M kT − = = -8.85 MPa 2 0.785 ×π× 14082 × 13.4 K10πRa δe

At Acting Point K of Concectrated Load under Operating Condition

0.65 × 1408 5.12859 × 108 pc Ra Mk − = + σ2 k = 2 2 × 13.4 0.89 ×π× 14082 × 13.4 2δe K11πRa δe = 34.15 + 6.91 = 41.06 MPa At Acting Point K of Concectrated Load underHydrostatic Testing Condition(Vessel under Outside Pressure)

σ2 kT =

pT Ra M kT 1.04 × 1408 5.796477 × 108 + − = 2 2δe 2 × 13.4 0.89 ×π× 14082 × 13.4 K11πRa δe

= 54.64 + 7.81 = 62.45 MPa (5)-2 At Mid-Point C of Cylindrical Shell under Operating Condition:

407082.63 2 FⅠ0 2 x1 = − hi − A = − × 700 − 1140 = 4307.48 q 3 68.832 3 if x1＞ a =3500 then x2 =

407082.63 2 FⅡ0 2 − hi − A = − × 700 − 1140 = 4307.48 q 3 68.832 3

if x2＞ b =3500 then Mm =0 x1T =

466328.68 2 FⅠ0 ′ 2 − hi − A = − × 700 − 1140 = 4236.2 q′ 3 　 79.8116 3

X2T =

466328.68 2 FⅡ0 ′ 2 − hi − A = − × 700 − 1140 = 4236.2 q′ 3 　 79.8116 3

MmT =0 (5)-3 When Mm = 0, there is no need to calculate σ1 and σ2 When Mm T= 0, there is no need to calculate σT1 and σT2 .

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At Mid-Point C of Cylindrical Shell under Operating Condition

σ1 =

pc Ra Mm − =0 2δe πRa 2δe

At Mid-Point C of Cylindrical Shell under Hydrostatic Testing Condition(Vessel under Internal Pressure) After water filling, if PT = 0

M mT σT 1 = − =0 2 πRa δe At Mid-Point C of Cylindrical Shell under Operating Condition

pc Ra Mm + =0 2δe πRa 2δe

σ2 =

At Mid-Point C of Cylindrical Shell under Hydrostatic Testing Condition(Vessel under Internal Pressure)

σ2T =

pT Ra M mT =0 + 2δe πRa 2δe

(5)-4 Calculation Factors Ra/2 = 704, θ = 120, K1= 1

A = 1140,

K2 = 1

At Top Point of Central Section of Support (a) under Operating Condition

σ3 =

pc Ra M2 0.65 × 1408 − 5.565214 × 107 − − = 2δe πK1Ra 2δe 2 × 13.4 π× 1 × 14082 × 13.4

= 34.15 + 0.67 = 34.82 MPa (b) undet Hydrostatic Testing Conditiong PT = 0

MT 2 − 6.452939 × 107 σT 3 = − − = = 0.78 MPa 2 π× 1 × 14082 × 13.4 πK1Ra δe PT ≠ 0

σT 3 =

pT Ra MT 2 1.04 × 1408 − 6.452939 × 107 = − − 2δe πK1Ra 2δe 2 × 13.4 π× 1 × 14082 × 13.4

= 54.64 + 0.78 = 55.42 MPa

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Maximum Axial Tensile Stress Under Operating Condition < φ[σ ]t = 115.6 MPa

O.K

Maximum Axial Compressive Stress Under Operating Condition < [σ ]ac = 75 MPa

O.K

At Bottom Point of Central Section of Support (a) under Operating Condition

σ4 =

pc Ra M2 0.65 × 1408 − 5.565214 × 107 + + = 2δe πK 2 Ra 2δe 2 × 13.4 π× 1 × 14082 × 13.4

= 34.15 - 0.67 = 33.48 MPa (b) undet Hydrostatic Testing Conditiong PT = 0

σT 4 =

− 6.452939 × 107 MT 2 = = -0.78 MPa 2 2 πK 2 Ra δe π× 1 × 1408 × 13.4

PT ≠ 0

pT Ra MT 2 1.04 × 1408 − 6.452939 × 107 σT 4 = + + = 2δe πK 2 Ra 2δe 2 × 13.4 π× 1 × 14082 × 13.4 = 54.64 - 0.78 = 53.86 MPa (5)-5 check for axial stress in cylindrical shell (a) allowable compressive stress. see UG-23(b) A=

0.125 0.125 = = 0.001412 RO / t 1416 / 16

E = 185×103 MPa ET = 202×103 MPa Under Operating Condition:

B = 75 MPa

Under Hydrostatic Testing Condition:

(from Fig. CS-2)

B = 98 MPa (from Fig. CS-2)

Allowable Compresive Sress t

[σ] ac = min(σt, B) = 75 MPa [σ] ac = min(0.9Rel, B) = min(0.9×204, 75) = 75 MPa (b) Stress Checking

Maximum Axial Tensile Stress Under Hydrostatic Test Condition < 0.9ReL = 183.6 MPa

O.K

Maximum Axial Compressive Stress Under Hydrostatic Test Condition < [σ ]ac = 75 MPa O.K

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11-3 Calculation for Circumferential Shearing Stress With Ra/2, A and θ, from table 6-2:

K3 = 0.319

K4 = ， K0 = 1.2

A>Ra/2, Cylindrical Shell Not Stiffened by Head (1) calculation for circumferential shearing stress in cylindrical shell: F = 466328.68 N τ=

K 3 F ⎛ L − 2 A ⎞ 0.319 × 466328.68 ⎛ 9280 − 2 ×1140 ⎞ ⎜ ⎟= ⎜ ⎟ = 5.41MPa 1408 ×13.4 Ra δ e ⎜⎝ L + 4hi / 3 ⎟⎠ ⎝ 9280 + 4 × 700 / 3 ⎠

(2) check for circumferential shearing stress τ = 5.41 MPa ＜ 0.8 [σ ]t = 108.8 MPa

OK.

11-4 circumferential stress in cylindrical shell at saddle support: Effective Width of Cylindrical Shell

R aδ

b2 = b+1.56

ne

= 378 +1.56 1408 × 16 = 612.146 mm

Cylindrical Shell With Stiffening Ring Parameters of Stiffening Ring e=66.5682 mm d=112.532 mm Number of Stiffening Rings, n = 1 Total Combined Sectional Area , A0= 9841.01

mm2

Total Moment of Innertia of Combined Section, I0 = 5.01192e+07 Allowable Stress at Design Temperature [σ ]t = 136

mm4

MPa

Stiifening Ring Located at Same Plane of Saddle Support C4=-1

C5=1

K7=0.053

K8=0.341

Circumferential Stress of Cylindrical Shell at Side Corner of Saddle Suport： σ7= -

K8 F C4 K 7 FRa e + A0 I0

= −

0.341 × 466328.68 − 1 × 0.053 × 466328.68 × 1408 × 66.5682 + 9841.01 5.01192 × 107

= -16.17 - 46.25 = -62.42 MPa Circumferential Stress of Inner or Outer Surface of Stiffening Ring at Side Corner of Saddle Support： σ8= -

K8 F C5 K 7 FRa d + A0 I0

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0.341 × 466328.68 1 × 0.053 × 466328.68 × 1408 × 112.532 + 9841.01 5.01192 × 107

= -16.17 +78.14 = 61.97 MPa Stress Identification . [σ ] = 170 MPa |σ7| < 125 t

t . [σ ] R = 170 MPa |σ8| < 125

O.K O.K

11-5 Calculation for Saddle Support Stress: (1) horizontal component and strength identification (a) Horizontal component θ= 120deg;

K9 = 0.204

FS=K9F = 95131.1 N horizontal (b) horizontal stress in Web Calculated Height

HS=min(Rm/3, H0) = 250 mm

Thickness of Saddle Support Web b0 = 18 mm Actual width of Saddle Support Backing Plate b4= 620

b= 378 b2 = 612.146 mm

Effective Width of Saddle Support Backing Plate

br= min(b4, b2) = 612.146 mm

Backing Plate Having Stiffening Action: σ9=

Fs 95131.1 = = 8.031 MPa H sb0 + brδre 250 × 18 + 612.146 × 12

(c) stress identification Stress Identification σ9