Reservoir Routing with the Level Pool Method Solution Procedure Level pool routing consists of two main components: 1. D
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Reservoir Routing with the Level Pool Method Solution Procedure Level pool routing consists of two main components: 1. Develop the storage-outflow function, Q vs. 2S/Δt + Q 2. Route the inflow hydrograph through the reservoir using the discrete form of the continuity equation
2S j 1 2S j Q j 1 I j I j 1 Q j t t
Steps to develop storage-outflow function 1. Determine the Q-H relation. This relation will be given based on measured outflow or calculated using the features of the outflow structure(s), e.g. orifice and/or weir equations. 2. Determine the S-H relation using the reservoir geometry. 3. Find 2S/Δt + Q using the results of the first two steps (note: Δt is determined by the inflow hydrograph). Comments: Watch units for Δt! Q is usually in cfs; therefore S must be in ft3 and Δt in s. If Q increases faster than 2S/Δt, the solution will become unstable. In this situation, reduce Δt.
Steps to route hydrograph (computations occur at the j+1 step) 1. Calculate I j I j 1
2S j Q j , i.e. for the previous step (if the basin is empty and there 2. If j+1 = 2, calculate t is no outflow, the value will be zero). After j+1 = 2, this step is not necessary.
2S j 1 2S j Q j 1 I j I j 1 Q j 3. Calculate t t
CE 460/560
Level Pool Routing
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4. Linearly interpolate the value for Qj+1 using the value from the previous step and storageoutflow function. Once Qj+1 is found, the depth in the reservoir H can be found by interpolating the Q-H relation or direct calculation, if an equation is available.
2S j 1 2S j 1 Q j 1 Q j 1 2Q j 1 . This value is needed for the next time 5. Calculate t t step, (j+2), and replaces step 2.
Review of Linear Interpolation Given pairs of known values (x1, y1) and (x2, y2), the interpolated value for y corresponding to a given value of x where x1 ≤ x ≤ x2 is
y y1
y 2 y1 x x1 x2 x1
y2
y1
x1 CE 460/560
x2 Level Pool Routing
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