• Author / Uploaded
• Kevin Matews Lujan Quispe

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TUBO #2 Valores teóricos para las pérdidas de carga por fricción 1. Darcy K=0.00164 + 0.000042/0.009 = 6.3067 x 10−3 (6.41𝑥10−4 ) 0.0095 −4 ) (6.38𝑥10 0.3067x10−3x 0.0095 (6.43𝑥10−4 ) 0.3067x10−3x 0.0095



J1 = 0.3067x10−3x

= 43.8839



J2 =

= 43.4731



J3 =

= 44.1582

2. Blasius Re = 4/3.14 x 106 x (6.41 x 10−4/0.009) = 90682.9498 K= 4

(0.0264)

√90682.9498

= 1.52138 x10−3

(6.41𝑥10−4 ) 0.0095 −4 −3 (6.38𝑥10 ) 1.52133x10 x 0.0095 (6.43𝑥10−4 ) 1.52133x10−3x 0.0095



J1 = 1.52133x10−3x

= 10.59



J2 =

= 10.49



J3 =

= 10.65

3. Moody Del grafico : f= 0.022 8𝑥(6.41𝑥10−4 )^2 0.0095 𝑥9.81𝑥(𝜋2 ) 8𝑥(6.38𝑥10−4 )^2 = 0.022x 0.0095 𝑥9.81𝑥(𝜋2 ) 8𝑥(6.43𝑥10−4 )^2 = 0.022x0.0095 𝑥9.81𝑥(𝜋2 )



J1 = 0.022x

= 12.6487



J2

= 12.5306



J3

= 12.7277

* Tabla resumen de los valores teóricos * Errores porcentuales (E=Vt –Ve/Vt x100%) N°

J darcy

J Blasius

J Moody

1

43.8839

10.59

2

43.4731

3

44.1582

J Blasius

J Moody

12.6487

Prueba J darcy N° 1 0.122%

1.27 %

0.55%

10.49

12.5306

2

0.053%

1.04 %

0.56%

10.65

12.7277

3

0.086 %

1.22%

0.56%