Pb (hp)= ρ . g .Q . hb 746 e Pb: potencia teórica de la bomba (hp) Ρ: es la densidad del fluido (kg/m3) g: la graved
Views 688 Downloads 4 File size 204KB
Pb (hp)=
ρ . g .Q . hb 746 e
Pb: potencia teórica de la bomba (hp) Ρ: es la densidad del fluido (kg/m3) g: la gravedad (9.81 m/s2) Q: es el caudal (m3/s)
Hb sale de la ecuación de bernoulli
Hb: Cabeza de la bomba (m) e: Eficiencia de la bomba 745.7w = 1hp 3
v 12 p1 v 2 p3 h1 + + +hᵇ =h₃+ + + hƒ ₁͢͢ ₃ 2g γ 2g γ
m
3 139 L m3 min =2,32∗10¯ s min 1000 L 60 s
3
v2 hb =h ₃+ +hƒ ₁ ͢͢ ₃ 2g
43,68 mm
h ₃=4 m+25 m=29 m
v 2=
3
h =29m 3
v=
Q Q 4Q = = A πD ² πD ² 4
( )
V 21 L hf = + F + ∑kc +kv 2g D
[
ℜ=
]
E D
]}
VDp μ
1,548
m kg ( 0,04358 m ) 998 3 s m
1,005 x 10 ¯ 3 pa∗s
ℜ=67155,2 ℜ=¿ 4000 es turbulento
VDp μ
F
1,325 c 5,74 −ln + 0 ² 3,7 D R e ’ ⁹
{ [
ℜ=
m s
P=0,04368 m
L V 21 V 22 V 22 hf =F +∑ kc + kv D2g 2g 2g
R e=
π D2 m =1,548 4 s m L=LD + L s=38
V =1,548
LD LS
F=
m =0,0 4368 m 1000 mm
V =1,,548
Rugosidad relativa
m s
D=0,04368 m
E 0,0015 mm = =3,43∗10 ¯ 5 D 43,68 mm F=
F=
hf =F
1,325 c 5,74 −ln + 0 ² 3,7 D R e ’ ⁹
{ [
hf =
]}
1,325
{ [ −ln
5
3,43∗10 ¯ 5,74 + 3,7 ( 67155,2 )0 ’ 9
2
]}
L∗V 21 V2 V2 +∑kc 2 + kv 2 D∗2 g 2g 2g
V 21 L + F + ∑ kc +kv 2g D
[
1,548 m s hƒ ₁͢͢ ₃= 2g
(
]
2
)
[
0,0196
38 m + ( 0,9∗2 )+ 10 0,04368 m
hƒ ₁ ͢͢ ₃=3,53 m
F=0,0196 3
v2 hb =h ₃+ +hƒ ₁ ͢͢ ₃ 2g
Pb (hp)=
ρ . g .Q . hb 746 e
( 2,32∗10 ¯ 3 ) ( 998 )( 9,8 )( 32,65 )
1.5482 h b=29 m+ +3,53 m 2g
Pb ( hp )=
hb=32,65
Pb ( hp )=1.32 hp
Q=2,32∗10¯ ³ p=998
kg m3
m3 s
e=0,75 hb=32,65
746 ( 0,75 )
]