10/10/2010 ROPES AND FLAT BELTS Weight W is held in static equilibrium by a rope that passes over a peg. If peg is fric
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10/10/2010
ROPES AND FLAT BELTS Weight W is held in static equilibrium by a rope that passes over a peg. If peg is frictionless: P = W to maintain static equilibrium
peg
Chapter 7(Cont’n) Belt Friction
ROPES AND FLAT BELTS
D•
C
•
Weight W is held in static equilibrium by a rope that passes over a peg.
50N
If peg is frictionless: P = W
peg B•
A•
If the contact surface between the peg and the rope has friction : P W to maintain equilibrium. There is a possibility that P < W and still maintain equilibrium
Determine the weight W to maintain equilibrium if pulleys are frictionless: W = 400N
W
7.64
Analysis of Belt Friction When motion is impending: Thin, flat belt
T2 T1es
s
The 30N weight is attached to a rope that runs over a fixed cylinder. The coefficient of static friction between the rope and the cylinder is 0.3. Determine the range of the force P for which the system will be at rest.
T2 T1es
s
Where: T1= tension in the slack side
CW motion: T2= tension in the tight side T2 > T 1 S= coefficient of static friction = angle of wrap = radians ( radians = 180 deg.)
CCW motion:
P 30e0.3
P 77N
30 Pe0.3
P 11.7N
System is at rest if: 11.7N P 77N
1
10/10/2010
7.59 The rope is wrapped 1 and ½ times around a circular peg. What is ?
1.5( 2)
How many turns of rope around the capstan are needed for the 60N force to resist the 9000-N pull of a docked ship? The coefficient of friction between the capstan and the rope is 0.2.
3 or:
n( 2) n = no. of turns 2 radians = 1 revolution = 360 deg.
Other Applications of Belt Friction:
Capstan – a device for fastening a ship to the dock.
7.59 s=0.2
Capstan – a device for fastening a ship to the dock.
T2 T1es
9000 60e0.2
Belt Drives – the friction between the belt and the pulleys enables power to be transmitted between rotating shafts.
25.05 radians
Solving:
n( 2)
Band Brakes – use friction between a band (belt) and a cylindrical drum to reduce the speed of a rotating machinery.
25.05 n( 2) n 3.98 or 4 turns 4 turns are required to hold the ship.
s=0.15
Problem A
The rope running over two fixed cylinders carries the 4-kg mass at one end. Determine the force P that must be applied to the other end to initiate motion. The coefficient of friction between the rope and the cylinders is 0.15. s=0.15 A
•
•
T T
s=0.15
4(9.81)
B
•
s=0.15
B
•
T
Cylinder A:
Cylinder B:
40o
T2 T1es T 4(9.81)e0.15A
T2 T1es
P Te 0.15B
2
10/10/2010
Determination of : 1.
2.
•
Determination of A and B
•
3.
•
•
90o
•
90o
40o
40o
•
T T
180o o 180
90o o 180 2
40o
90o o 180
A
40o
4(9.81)
A 90o 40o o 180
o 180
•
•
B 40o o 180
130 180o
B
40 180o
s=0.15
7.62 A
•
T T
•
s=0.15
4(9.81)
Cylinder A:
T2 T1e
B
Cylinder B: s
T2 T1es
T 4(9.81)e T 4(9.81)e
0.15A
130 0.15 180
T 55.15N
P Te
FIN.
0.15B
P 55.15e
40 0.15 180
P 61.24N
3