9 - INTEGRAL CALCULUS Page 1 ( Answers at the end of all questions ) 1 (1) 1 2 ∫ If I 1 = 2 x dx , I2 = 0 ∫
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9 - INTEGRAL CALCULUS
Page 1
( Answers at the end of all questions ) 1
(1)
1
2
∫
If I 1 =
2 x dx ,
I2 =
0
∫
2
2 x dx ,
2
I4 =
1
(b) I1 > I2
(c) I3 = I4
∫
3
2 x dx , then
1
(d) I3 > I4
[ AIEEE 2005 ]
The area enclosed between the curve y = log e ( x + e ) and the coordinate axes is (a) 1
(3)
2
I3 =
0
(a) I2 > I1
(2)
∫
3
2 x dx ,
(b) 2
(c) 3
(d) 4
2
[ AIEEE 2005 ]
2
The parabolas y = 4x and x = 4y divide the square region bounded by the lines x = 4, y = 4 and the coordinate axes. If S1, S2, S3 are respectively the area of these parts numbered from top to bottom, then S1: S2 : S3 is (a) 1:2:1
(b) 1:3:1
(c) 2:1:2
(d) 1:1:1
[ AIEEE 2005 ]
2
(4)
∫
( log x - 1 ) dx 1 + ( log x ) 2
(a) (c)
(5)
log x ( log x ) 2 + 1
xe x 1+ x
+ c
(b)
+ c
2
(d)
x x2 + 1
+ c
x ( log x ) 2 + 1
+ c
[ AIEEE 2005 ]
Let f ( x ) be a non-negative continuous function such that the area bounded by the π π curve y = f ( x ), X-axis and the ordinates x = and x = β > is 4 4 π π ( β sin β + cos β + 2 β ). Then f ( ) is 4 2 (a)
π + 4
(c) 1 -
2 -1 π 4
The value of
∫
-π
(a) aπ
(b)
(b)
π 4
cos 2 x 1 + ax
π 2
dx ,
(c)
2 + 1 π + 4
(d) 1 -
2 π
(6)
is equal to
2
[ AIEEE 2005 ]
a > 0 is
π a
(d) 2π
[ AIEEE 2005 ]
9 - INTEGRAL CALCULUS
Page 2
( Answers at the end of all questions ) n
(7)
∑
lim
n→∞ r =1
If
is
(b) e - 1
(a) e
(8)
r n e
sin x dx - α)
∫ sin ( x
(c) 1 - e
∫ cos x
dx - sin x
( b ) ( cos α, sin α ) ( d ) ( - cos α, sin α )
π x - + C log tan 2 8 2
x 3π log tan + C 8 2 2
3
( 10 ) The value of
∫
1 - x 2 dx
x log cot + C 2 2
1
(b)
1
(c)
[ AIEEE 2004 ]
is equal to
1
(a)
[ AIEEE 2004 ]
= Ax + B log sin ( x - α ) + C, then the value of ( A, B ) is
( a ) ( sin α, cos α ) ( c ) ( - sin α, cos α )
(9)
(d) e + 1
3π x + log tan + C 8 2 2
1
(d)
[ AIEEE 2004 ]
is
-2
28 3
(a)
(b)
14 3
(c)
7 3
(d)
1 3
[ AIEEE 2004 ]
π 2
( 11 ) The value of I =
∫
( sin x + cos x ) 2 1 + sin 2x
0
(a) 0
(b) 1
(c) 2
∫
is
(d) 3
[ AIEEE 2004 ]
π
π ( 12 ) If
dx
2
x f ( sin x ) dx = A
0
(a) 0
∫
f ( sin x ) dx , then A is equal to
0
(b) π
(c)
π 4
(d) 2π
[ AIEEE 2004 ]
9 - INTEGRAL CALCULUS
Page 3
( Answers at the end of all questions ) f(a)
ex
( 13 ) If f ( x ) =
1 + ex
,
∫
I1 =
f(a)
x g { x ( 1 - x ) } dx
I2 =
and
f(- a)
∫
g { x ( 1 - x ) } dx ,
f(- a)
I then the value of 2 is I1 (b) -3
(a) 2
(c) -1
(d) 1
[ AIEEE 2004 ]
( 14 ) The area of the region bounded by the curves y = l x - 2 l, X-axis is (a) 1
(b) 2
(c) 3 x2
∫
( 15 ) The value of (a) 3
lim
x→0
(b) 2
x = 1,
x = 3
and
(d) 4
[ AIEEE 2004 ]
(d) 0
[ AIEEE 2003 ]
sec 2 t dt
0
is
x sin x (c) 1 1
( 16 ) The value of the integral I =
∫
x ( 1 - x )n dx
is
0
(a)
1 n + 1
(b)
1 n + 2
(c)
1 1 n + 1 n + 2 t
y
( 17 ) If f ( y ) = e ,
g ( y ) = y,
y > 0
and
F(t) =
1 1 + n + 1 n + 2 [ AIEEE 2003 ]
(d)
∫
f ( t - y ) g ( y ) dy ,
then
0
(a) F(t) = te (c) F(t) = e
t
t
(b) F(t) = te-
t t
(d) F(t) = 1 - e- (1 + t)
- (1 + t)
[ AIEEE 2003 ]
b
( 18 ) If f ( a + b - x ) = f ( x ),
then the value of
∫
x f ( x ) dx
is
a
(a)
(c)
b -a 2
b
∫
f ( x ) dx
(b)
a
a + b 2
b
∫
a
f ( b - x ) dx
a + b 2 b
(d)
∫
a
b
∫
f ( x ) dx
a
f ( a + b - x ) dx
[ AIEEE 2003 ]
9 - INTEGRAL CALCULUS
Page 4
( Answers at the end of all questions ) ( 19 ) Let
4
d e sin x F(x ) = , dx x
x > 0.
3 sin x3 e dx = F ( K ) - F ( 1 ), then one of the x
∫
If
1
possible values of K is ( a ) 15
( b ) 16
( c ) 63
( d ) 64
[ AIEEE 2003 ]
( 20 ) Let f ( x ) be a function satisfying f ’ ( x ) = f ( x ) with f ( 0 ) = 1 and g ( x ) be a 1
2
function that satisfies
f ( x ) + g ( x ) = x . The value of the integral
∫
f ( x ) g ( x ) dx
0
is (a) e -
e2 5 2 2
(b) e +
e2 2
-
3 2
(c) e -
e2 3 2 2
(d) e +
e2 2
+
5 2
( 21 ) If
∫ x sin x dx
= - x cos x + α, then the value of α is
( a ) sin x + c ( c ) x cos x + c
( b ) cos x + c ( d ) cos x - sin x + c 1 - cos 2x dx + 1
∫ cos 2x
( 22 ) The value of
[ AIEEE 2003 ]
( a ) tan x - x + c ( c ) x - tan x + c
[ AIEEE 2002 ]
is
( b ) x + tan x + c ( d ) - x - cot x + c
[ AIEEE 2002 ]
π 2
∫
( 23 ) The value of
a cos x + b 2 sin 2 x 0
2
2
(a ) πab
( b ) π ab
∫e
( 24 ) The value of
( a ) log ( x
dx 2
4
( c ) 3 log ( x
3 log x
( c ) π / ab
( x 4 + 1 ) -1 dx
+ 1) +c
(b)
4
(d)
+ 1) +c
is
(d)
π / 2ab
[ AIEEE 2002 ]
is
1 4 log ( x + 1 ) + c 4 - log ( x4 + 1 ) + c
[ AIEEE 2002 ]
9 - INTEGRAL CALCULUS
Page 5
( Answers at the end of all questions ) log x
∫
( 25 ) The value of
x2
dx is
( a ) log ( x + 1 ) + c
(b)
( c ) log ( x - 1 ) + c
(d)
sin2 x
∫
( 26 ) The value of
sin
-1
-
1 log ( x + 1 ) + c x 1 log ( x + 1 ) + c 2 cos2 x
( t ) dt +
0
π 2
(a)
[ AIEEE 2002 ]
∫
cos - 1 ( t ) dt
is
0
(b) 1
(c)
π 4
(d)
π
[ AIEEE 2002 ]
( 27 ) If the area bounded by the X-axis, the curve y = f ( x ) and the lines x = 1, x = b is b2 + 1 -
equal to x - 1
(a)
∫ [x 0
( 28 )
2
for all b > 1, then f ( x ) is
x + 1
(b)
(c)
x2 + 1
(d)
x 1 + x2
[ AIEEE 2002 ]
]
3 + 3x 2 + 3x + 3 + ( x + 1 ) cos ( x + 1 ) dx =
-2
(a) 4
(c) -1
(b) 0
(d) 1
[ IIT 2005 ]
2
2
( 29 ) Find the area between the curves y = ( x - 1 ) , y = ( x + 1 ) and y = 1 3
(a)
1
∫t
( 30 ) If
(b)
2 3
2 f ( t ) dt = 1
(c)
4 3
(d)
1 6
1 4 [ IIT 2005 ]
- sin x, x ∈ [ 0, π / 2 ], then f ( 1 /
3 ) is
sin x
(b) 1/3
(a) 3 t2
( 31 ) If
∫ x f ( x ) dx 0
(a) -
2 5
=
2 5 t 5
(b) 0
(c) 1
(d)
4 for t > 0, then f 25
(c)
2 5
(d) 1
[ IIT 2005 ]
3
is
[ IIT 2004 ]
9 - INTEGRAL CALCULUS
Page 6
( Answers at the end of all questions ) 1
( 32 )
∫
0
(a)
1-x dx is equal to 1+ x
π + 1 2
(b)
π - 1 2
(c) 1
(d)
( 33 ) If the area bounded by the curves x = ay 1
(a)
1 3
(b)
3
x2 + 1
∫
( 34 ) If f ( x ) =
1 2
(c)
2
π
[ IIT 2004 ]
2
and y = ax is 1, then a is equal to
(d) 3
[ IIT 2004 ]
2
e - t dt , then the interval in which f ( x ) is increasing is
x2
( a ) ( 0, ∞ )
(b) (- ∞, 0) 1
( 35 ) If I ( m, n ) =
∫t
( c ) [ - 2, 2 ]
m ( 1 + t )n dt ,
( d ) nowhere
[ IIT 2003 ]
m, n ∈ R, then I ( m, n ) is
0
(a)
n I [ ( m + 1) , ( n - 1 ) ] 1+ m
(b)
2n m I [ ( m + 1) , ( n - 1 ) ] 1+ m 1+ n
(c)
2n m I [ ( m + 1) , ( n - 1 ) ] 1+ m 1+ m
(d)
m I [ ( m + 1) , ( n - 1 ) ] n+1
( 36 ) Area bounded by the curves y = (a) 2
( b ) 18
3
[ IIT 2003 ]
x , x = 2y + 3 in the first quadrant and X-axis is
(c) 9
34 3
(d)
[ IIT 2003 ]
( 37 ) The area bounded by the curves y = l x l - 1 and y = - l x l + 1 is (a) 1
(b) 2 x
( 38 ) If f ( x ) =
∫
(c) 2
2
(d) 4
2 2 - t 2 dt , then the real roots of the equation x
[ IIT 2002 ]
- f ’ ( x ) = 0 are
1
(a) ± 1
(b)
±
1 2
(c)
±
1 2
( d ) 0 and 1
[ IIT 2002 ]
9 - INTEGRAL CALCULUS
Page 7
( Answers at the end of all questions ) ( 39 ) Let T > 0 be a fixed real number. Suppose f is a continuous function such that for 3 + 3T
T
all x ∈ R, f ( x + T ) = f ( x ). If I =
∫
f ( x ) dx , then the value of
0
(a)
3 I 2
(b)
( c ) 3I
I
1 2
-
1 2
(a) -
[ x 1
∫
( 40 ) The integral equals
]+
∫ f ( 2x ) dx
is
3
( d ) 6I
[ IIT 2002 ]
1+ x ln dx equals 1- x
2
(b) 0
(c) 1
( d ) 2 ln
1 2
[ IIT 2002 ]
x
∫ f ( t ) dt
( 41 ) If f : ( 0, ∞ ) → R, F ( x ) =
2
and
2
F ( x ) = x ( 1 + x ),
then f ( 4 ) equals
0
(a)
5 4
(b) 7
π ( 42 ) The value of
(a) π
( 43 ) If f ( x ) =
(a ) 0
∫
(c) 4
cos 2 x
1 + ax -π
(b) aπ
dx,
(c)
(d) 2
a > 0, is
π 2
(c) 2 e2
( 44 ) The value of the integral
∫
e- 1
(a)
3 2
( d ) 2π
e cos x sin x for l x l ≤ 2, 2 otherwise,
(b) 1
(b)
5 2
[ IIT 2001 ]
(c) 3
[ IIT 2001 ]
3
then
(d) 5
=
-2
(d) 3
log e x dx x
∫ f ( x ) dx
[ IIT 2000 ]
is
[ IIT 2000 ]
9 - INTEGRAL CALCULUS
Page 8
( Answers at the end of all questions ) ( 45 ) If f ( x ) = ∫ e x ( x - 1 ) ( x - 2 ) dx , then f decreases in the interval ( a ) ( - ∞, - 2 )
( 46 )
Let
g(x) =
0 ≤ f(t) ≤
(a)
-
(c)
( 47 )
1 2
( b ) ( - 2, - 1 ) x ∫ f ( t ) dt , 0
( c ) ( 1, 2 )
where f is such that
( d ) ( 2, + ∞ )
1 ≤ f(t) ≤ 1 2
for
[ IIT 2000 ]
t ∈ [ 0, 1 ]
and
for t ∈ [ 1, 2 ]. Then g ( 2 ) satisfies the inequality
3 1 ≤ g(2) ≤ 2 2 3 5 ≤ g(2) ≤ 2 2
( b ) 0 ≤ g(2) ≤ 2 (d) 2 < g(2) < 4
[ IIT 2000 ]
If for a real number y, [ y ] is the greatest integer less than or equal to y, then the 3π 2
value of the integral
∫
[ 2 sin x ] dx is
π 2
(a) -π
(b) 0
(c) -
π 2
(d)
π 2
[ IIT 1999 ]
(d) -
1 2
[ IIT 1999 ]
3π
4 ( 48 )
∫
π 4
dx 1 + cos x
(a) 2
( 49 )
=
(b) -2
(c)
1 2
For which of the following values of
m, is the area of the region bounded by the 9 ? curve y = x - x and the line y = mx equals 2 2
(a) -4
( 50 )
(b) -2
(c) 2
(d) 4
[ IIT 1999 ]
If f ( x ) = x - [ x ], for every real number x, where [ x ] is the integral part of x, then 1
∫ f ( x ) dx
is
(a) 1
(b) 2
-1
(c) 0
(d)
1 2
[ IIT 1998 ]
9 - INTEGRAL CALCULUS
Page 9
( Answers at the end of all questions ) x
∫ cos
( 51 ) If g ( x ) =
4
t dt , then g ( x +
π ) equals
0
(a) g(x) + g(π)
(b) g(x) - g(π)
(c) g(x)g(π)
(d)
g( x ) g( π)
k
( 52 )
∫
Let f be a positive function. If I1 =
k
x f [ x ( 1 - x ) ] dx
and I2 =
1- k
where
I1 I2
2k - 1 > 0, then
(a) 2
(b) k
(c)
[ IIT 1997 ]
∫ f [ x ( 1 - x ) ] dx ,
1- k
is
1 2
(d) 1
[ IIT 1997 ]
( 53 ) The slope of the tangent to a curve y = f ( x ) at [ x, f ( x ) ] is 2x + 1. If the curve passes through the point ( 1, 2 ), then the area of the region bounded by the curve, the X-axis and the line x = 1 is (a)
5 6
6 5
(b)
1 6
(c)
(d) 6
[ IIT 1995 ]
2π ( 54 ) The value of
∫
[ 2 sin x ] dx
where [ . ] represents the greatest integer function, is
π (a)
-
5π 3
(b) -π
π 2 ( 55 ) The value of
(a) 0
dx
∫
1 + tan 3 x 0
(b) 1
(c)
(c)
5π 3
(d) -2π
[ IIT 1995 ]
is
π 2
(d)
π 4
[ IIT 1993 ]
( 56 ) If f : R → R be a differentiable function and f ( 1 ) = 4, then the value of f(x) 2t lim dt is ∫ x - 1 x →1 4 (a) 8f’(1)
(b) 4f’(1)
(c) 2f’(1)
(d) f’(1)
[ IIT 1990 ]
9 - INTEGRAL CALCULUS
Page 10
( Answers at the end of all questions ) ( 57 )
If f : R → R and g : R → R are continuous functions, then the value of the integral π 2
∫ -
[ f ( x ) + f ( - x ) ] [ g ( x ) + g ( - x ) ] dx
is
π 2
(a) π
(b) 1
(c) -1
(d) 0 π
∫
( 58 ) For any integer n, the integral
[ IIT 1990 ]
2 e cos x cos 3 ( 2n + 1 ) x dx
has the value
0
(a) π
(b) 1
(c) 0
( d ) none of these
[ IIT 1985 ]
π 2
∫
( 59 ) The value of the integral
0
(a)
( 60 )
π 4
(b)
π 2
cot x cot x +
(c) π
tan x
dx
is
( d ) none of these
[ IIT 1983 ]
If the area bounded by the curves y = f ( x ), the X-axis and the ordinates x = 1 and x = b is ( b - 1 ) sin ( 3b + 4 ), then f ( x ) is ( a ) ( x - 1 ) cos ( 3x + 4 ) ( c ) sin ( 3x + 4 )
( b ) sin ( 3x + 4 ) + 3 ( x - 1 ) cos ( 3x + 4 ) ( d ) none of these
1
( 61 ) The value of the definite integral
∫
[ IIT 1982 ]
2
( 1 + e - x ) dx is
0
(a) -1
(b) 2
(c) 1 + e–
1
( d ) none of these
[ IIT 1981 ]
9 - INTEGRAL CALCULUS
Page 11
( Answers at the end of all questions )
Answers 1 b
2 a
3 d
4 d
5 d
6 b
7 b
8 b
9 a,d
10 a
11 2
12 b
13 a
14 a
15 c
16 c
17 c
18 b
19 d
20 b
21 a
22 c
23 d
24 b
25 b
26 c
27 d
28 a
29 a
30 a
31 c
32 b
33 a
34 b
35 c
36 b
37 b
38 a
39 c
40 a
41 c
42 c
43 c
44 b
45 c
46 b
47 c
48 a
49 b,d
50 a
51 a
52 c
53 a
54 a
55 d
56 a
57 d
58 c
59 a
60 b
61 d
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80